The caret, when found at the start of a character set, is the equivalent to "not" in RegEx. The regular expression [^a-c] matches any characters except "a", "b" and "c". Write the regular expression that matches any characters except letters, digits and spaces. You must use a negated character set in your expression. Examples txt = " alice15@gmail.com pattern "yourregularexpressionhere" re.findall(pattern, txt) ["@", "."] Notes = You don't need to write a function, just the pattern. • Do not remove import re from the code. • Find more info on RegEx and negation in Resources. • You can find all the challenges of this series in my Basic RegEx collection.

The caret, when found at the start of a character set, is the equivalent to "not" in RegEx. The regular expression [^a-c] matches any characters except "a", "b" and "c". Write the regular expression that matches any characters except letters, digits and spaces. You must use a negated character set in your expression. Examples txt = " alice15@gmail.com pattern "yourregularexpressionhere" re.findall(pattern, txt) ["@", "."] Notes = You don't need to write a function, just the pattern. • Do not remove import re from the code. • Find more info on RegEx and negation in Resources. • You can find all the challenges of this series in my Basic RegEx collection.

Programming with Microsoft Visual Basic 2017

8th Edition

ISBN:9781337102124

Author:Diane Zak

Publisher:Diane Zak

Chapter8: Arrays

Section: Chapter Questions

Problem 4MQ3

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The caret when found at the start of a character set, is the equivalent to "not" in RegEx. The regular expression [^a-c] matches any characters except "a", "b" and "c". Write the regular expression that matches any characters except letters, digits and spaces. You must use a negated character set in your expression. Examples txt = alice15@gmail.com " pattern = "yourregularexpressionhere" re.findall(pattern, txt) ["@", "."] Notes • You don't need to write a function, just the pattern. • Do not remove import re from the code. • Find more info on RegEx and negation in Resources. • You can find all the challenges of this series in my Basic RegEx collection.
Replace all the 0 (Zero) digits in your ID by 4. Example: If your ID is 382200448 , it becomes 382244448 Take the first 6 digits and substitute them in this expression (( A + B) / C) * ((D-E)/F)-2) according to the following table; [1 mark] Letter Replace by Digit Example Digit A 1st 3 B 2nd 8 C 3rd 2 D 4th 2 E 5th 4 F 6th 4 After substitution your expression ? Draw a rooted tree that represents your expression. [3 marks] What is the prefix form of this expression. [3 marks] What is the value of the prefix expression obtained in step 2 above? [3 marks]
Fill in the places with underscores. B4: =IF(B3>B_ „IF(B3>=B ,"OK","No") =IF(AND(B3>=B_,B3<=B_)," _","_")) 11 11 -
Q29:A teacher stores the most recent quiz scores for her class in the list scores. The first element in the list holds the maximum possible number of points that can be awarded on the quiz, and each remaining element holds one student’s quiz score. Assume that scores contains at least two elements. Which of the following code segments will set the variable found to true if at least one student scored the maximum possible number of points on the quiz and will set found to false otherwise?
Strings that contain ‘01’ as substrings at any place except at the beginning or at the end. It accepts 1010,110110, etc. but does not accept 01, 0110, 1101, 00, etc. Ʃ={0, 1}
Using C++ Language Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2 , then numMatches should be 3.Your code will be tested with the following values:matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above)matchValue: 0, userValues: {0, 0, 0, 0}matchValue: 10, userValues: {20, 50, 70, 100} code: #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int userValues[NUM_VALS]; int i; int matchValue; int numMatches = -99; // Assign numMatches with 0 before your for loop cin >> matchValue; for (i = 0; i < NUM_VALS; ++i) { cin >> userValues[i]; } /* Your solution goes here */ cout << "matchValue: " << matchValue << ", numMatches: " << numMatches << endl; return 0;}
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2 , then numMatches should be 3. Your code will be tested with the following values:matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above)matchValue: 0, userValues: {0, 0, 0, 0}matchValue: 10, userValues: {20, 50, 70, 100} In Java
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2 , then numMatches should be 3.Your code will be tested with the following values:matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above)matchValue: 0, userValues: {0, 0, 0, 0}matchValue: 10, userValues: {20, 50, 70, 100} CODE: import java.util.Scanner; public class FindMatchValue {public static void main (String [] args) {Scanner scnr = new Scanner(System.in); final int NUM_VALS = 4;int[] userValues = new int[NUM_VALS];int i;int matchValue;int numMatches = -99; // Assign numMatches with 0 before your for loop matchValue = scnr.nextInt();for (i = 0; i < userValues.length; ++i) {userValues[i] = scnr.nextInt();} /* Your solution goes here */ System.out.println("matchValue: " + matchValue + ", numMatches: " + numMatches);}}
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2 , then numMatches should be 3.Your code will be tested with the following values:matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above)matchValue: 0, userValues: {0, 0, 0, 0}matchValue: 10, userValues: {20, 50, 70, 100} #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int userValues[NUM_VALS]; int i; int matchValue; int numMatches = -99; // Assign numMatches with 0 before your for loop cin >> matchValue; for (i = 0; i < NUM_VALS; ++i) { cin >> userValues[i]; } /* Your solution goes here */ cout << "matchValue: " << matchValue << ", numMatches: " << numMatches << endl; return 0;}
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2, then numMatches should be 3. Your code will be tested with the following values: matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above) matchValue: 0, userValues: {0, 0, 0, 0} matchValue: 10, userValues: {20, 50, 70, 100} (Notes) 324758.2040686.qx3zgy7 3 int main(void) { const int NUM VALS = 4; int userValues[NUM_VALS]; int i; int matchvalue; int numMatches = -99; // Assign numMatches with e before your for loop 4 1 test 5 passed 6 7 All tests 8 passed 9 scanf ("%d", &matchValue); 10 11 for (i = 0; i < NUM_VALS; ++i) { scanf("%d", &(userValues[i])); } 12 13 14 15 16 * Your solution goes here */ 17 18 printf("matchvalue: %d, numMatches: %d\n", matchValue, numMatches); 19 20 return 0;
The parameter represents converted station data for a single station. is_app_only The function should return True if and only if the given station requires the use of an app because it does NOT have a kiosk. Recall that a station requires the use of an app if and only ("Station") -> bool if the string that the constant NO_KIOSK refers to is part of its station name.
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2, then numMatches should be 3. Your code will be tested with the following values: matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above) matchValue: 0, userValues: {0, 0, 0, 0} matchValue: 10, userValues: {20, 50, 70, 100} CODE: import java.util.Scanner; public class FindMatchValue { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); final int NUM_VALS = 4; int[] userValues = new int[NUM_VALS]; int i; int matchValue; int numMatches = -99; // Assign numMatches with 0 before your for loop matchValue = scnr.nextInt(); for (i = 0; i