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The rate law for your reaction is Rate= k[NO2]?. The rate constant for this reaction is 2.5 x 103/M s. If you started out with 0.55M NO2 and you ran the reaction for 5 minutes, what would be the concentration of 4. NO2?

The rate law for your reaction is Rate= k[NO2]?. The rate constant for this reaction is 2.5 x 103/M s. If you started out with 0.55M NO2 and you ran the reaction for 5 minutes, what would be the concentration of 4. NO2?

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter11: Rate Of Reaction
Section: Chapter Questions
Problem 28QAP: Diethylhydrazine reacts with iodine according to the following equation: Â...
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Write the average rate lon for the follo ing reaction. b) If sumption of H3P 4 is M/s, wh is the rate consumption of I' ? What is the average r or this ction? 3. caction that is run at ^ constant of 2.52 x 10-5. ame Teactio un at 157 r ias a rate con x 10-/s. Whe activati nergy for this reacti 14 J/mol K) o 0898mols sec 4. The rate law for your reaction is Rate= k[NO2]². The rate constant for this reaction is 2.5 x 10-3/M s. If you started out with 0.55M NO2 and you ran the reaction for 5 minutes, what would be the concentration of NO2? 13
Transcribed Image Text:Write the average rate lon for the follo ing reaction. b) If sumption of H3P 4 is M/s, wh is the rate consumption of I' ? What is the average r or this ction? 3. caction that is run at ^ constant of 2.52 x 10-5. ame Teactio un at 157 r ias a rate con x 10-/s. Whe activati nergy for this reacti 14 J/mol K) o 0898mols sec 4. The rate law for your reaction is Rate= k[NO2]². The rate constant for this reaction is 2.5 x 10-3/M s. If you started out with 0.55M NO2 and you ran the reaction for 5 minutes, what would be the concentration of NO2? 13
Expert Solution
Step 1

4)

Given,

Rate law for the reaction,

Rate = k[NO2]2

From rate law we can say that this is a second order reaction.

Initial concentration of NO2 = 0.55 M

Concentration of NO2 after 5 min = ?

Time (t) = 5 min = (5×60) s = 300 s

Rate constant (k) = 2.5 × 10-3/M s

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