The steam reforming of methane occurs according to the following chemical equation: CH₂(g) + 2H₂O(g) = CO₂(g) + 4H₂(g) Use the following equations to solve for the enthalpy change of steam reforming of methane: AH° = H₂(g) + 1/2O₂(g) → H₂O(g) -242 kJ/mol 2H₂(g) + C(s) → CH₂(g) = -75 kJ/mol C(s) + O₂(g) → CO₂(g) = -394 kJ/mol 1 4 7 +/- Tap here or pull up for additional resources 3 5 6 8 9 kJ/mol 2 LO ΔΗ° ΔΗ° XU C x 100

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter9: Energy And Chemistry
Section: Chapter Questions
Problem 9.73PAE: 9.73 Without looking up any numerical data or doing calculations, predict whether the enthalpy...
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Question 7 of 17
The steam reforming of methane
occurs according to the following
chemical equation:
CH₂(g) + 2H₂O(g) = CO₂(g) +
4H₂(g)
Use the following equations to
solve for the enthalpy change of
steam reforming of methane:
H₂(g) + 1/2O₂(g) → H₂O(g)
-242 kJ/mol
2H₂(g) + C(s) → CH₂(g)
= -75 kJ/mol
C(s) + O₂(g) → CO₂(g)
= -394 kJ/mol
1
4
7
+/-
2
5
8
kJ/mol
3
60
Submit
9
O
Tap here or pull up for additional resources
AH° =
ΔΗ°
ΔΗ°
XU
x 100
Transcribed Image Text:Question 7 of 17 The steam reforming of methane occurs according to the following chemical equation: CH₂(g) + 2H₂O(g) = CO₂(g) + 4H₂(g) Use the following equations to solve for the enthalpy change of steam reforming of methane: H₂(g) + 1/2O₂(g) → H₂O(g) -242 kJ/mol 2H₂(g) + C(s) → CH₂(g) = -75 kJ/mol C(s) + O₂(g) → CO₂(g) = -394 kJ/mol 1 4 7 +/- 2 5 8 kJ/mol 3 60 Submit 9 O Tap here or pull up for additional resources AH° = ΔΗ° ΔΗ° XU x 100
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