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Trom Rate Given (n) Expirement Imol/L-s NO2 moV co mol/L NO2 mo/L CO mol/L 0.0050 0,10 0.10 2. 0. Os0 0.40 O.10 0.0050 0.10 0.20 Co,

Trom Rate Given (n) Expirement Imol/L-s NO2 moV co mol/L NO2 mo/L CO mol/L 0.0050 0,10 0.10 2. 0. Os0 0.40 O.10 0.0050 0.10 0.20 Co,

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.20P
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Can you tell me where did i go wrong for the experiment 1 and 2?
on Orders from Rate Data occur in a car engine and exhaust +CO(g) rate = K[NO,J"[COJ? determine the individual and ítial [NO] Initial [CO] (mol/L) (mol/L) 0.10 0.10 040 0.10 0.10 0.20
Transcribed Image Text:on Orders from Rate Data occur in a car engine and exhaust +CO(g) rate = K[NO,J"[COJ? determine the individual and ítial [NO] Initial [CO] (mol/L) (mol/L) 0.10 0.10 040 0.10 0.10 0.20
Act #1 Delevminung Reaction Orders from Given Expirement mol/L-s NO2 moV CO mol/L Rate Data (n) 0.0050 O,10 0-10 2 0. Oso 0.40 0.10 0.0050 0.10 0.20 + COCS) Cb 9) expiriment 193 +GI0) (0.16) m *K10) (0.20) m 0,0050 0.0050 1 = (0.10 )" C.20" %3D i lng! -alog.5 e pirement 192 0.00 50 4(10)" (0.10) 0,0e0 log .06 znlog.25 = In 0.06 .25"
Transcribed Image Text:Act #1 Delevminung Reaction Orders from Given Expirement mol/L-s NO2 moV CO mol/L Rate Data (n) 0.0050 O,10 0-10 2 0. Oso 0.40 0.10 0.0050 0.10 0.20 + COCS) Cb 9) expiriment 193 +GI0) (0.16) m *K10) (0.20) m 0,0050 0.0050 1 = (0.10 )" C.20" %3D i lng! -alog.5 e pirement 192 0.00 50 4(10)" (0.10) 0,0e0 log .06 znlog.25 = In 0.06 .25"
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