What is the slow, rate-determining step, in the acid-catalyzed dehydration of 2-methyl-2- propanol? H₂SO4 a) b) c) d) (CH3)3COH Protonation of the alcohol to form an oxonium ion Loss of water from the oxonium to form a carbocation Loss of a B hydrogen and water from the oxonium ion The simultaneous loss of a ß hydrogen and water from the oxonium ion

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter13: Substitution
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What is the slow, rate-determining step, in the acid-catalyzed dehydration of 2-methyl-2-
propanol?
H₂SO4
a)
b)
c)
d)
(CH3)3COH
Protonation of the alcohol to form an oxonium ion
Loss of water from the oxonium to form a carbocation
Loss of a B hydrogen and water from the oxonium ion
The simultaneous loss of a ß hydrogen and water from the oxonium ion
Transcribed Image Text:What is the slow, rate-determining step, in the acid-catalyzed dehydration of 2-methyl-2- propanol? H₂SO4 a) b) c) d) (CH3)3COH Protonation of the alcohol to form an oxonium ion Loss of water from the oxonium to form a carbocation Loss of a B hydrogen and water from the oxonium ion The simultaneous loss of a ß hydrogen and water from the oxonium ion
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