Concept explainers
(a)
To draw: The structure of the given compound with the proper representation of pi bond and geometry.
Interpretation: The structure of the given compound with the proper representation of pi bond and geometry is to be drawn.
Concept introduction: Isomers are the compounds with similar formula but different structures. Stereoisomers are the type of isomers in which arrangement of atoms differ in space. Geometric isomers are one of the types of stereoisomers. These are of two types and are named as, cis and trans isomers. These types of isomers generate due to the restricted rotations around the carbon-carbon double bond within the molecule.
(b)
To determine: The six coplanar atoms in the given compound.
Interpretation: Six coplanar atoms in the given compound are to be circled.
Concept introduction: Carbon –carbon double bonds exist in the same plane. Hydrogen or any other group also lies in the same plane to satisfy its valency. In the given compound,
(c)
To draw: The structure of the trans isomer of the given compound with circled coplanar atoms and if there are still six coplanar atoms.
Interpretation: The structure of the trans isomer of the given compound with circled coplanar atoms is to be drawn and the existence of six coplanar atoms is to be validated.
Concept introduction: Stereoisomers are the type of isomers in which arrangement of atoms differ in space. Geometric isomers are one of the types of stereoisomers. These are of two types and are named as, cis and trans isomers. These types of isomers generate due to the restricted rotations around the carbon-carbon double bond within the molecule.
(d)
To determine: The representation of circled coplanar atoms in the given compound.
Interpretation: The coplanar atoms in the given compound are to be circled.
Concept introduction: Carbon –carbon double bonds exist in the same plane. Hydrogen or any other group also lies in the same plane to satisfy its valency. In the given compound,
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Organic Chemistry (9th Edition)
- Which of the following compounds has both geometrical (cis/trans) and optical isomers (mirror image to one and another)? O a. CH3CHCICH=CHCH3 CH2(OH)CH=CHCH3 C6H5CH=CHNH2 d. C2H5CH=CH2arrow_forwardWhich of the compounds in the Figure below can have cis and trans isomers? B A D CH3 CH,-CH=C-CH-CH, CH3 A. Compound B B. Compounds A, B and D C. Compound A D. Compounds A and Barrow_forwardUse the ball-and-stick model of vitamin Bg to answer each question. vitamin Be a. Draw a skeletal structure of vitamin Bộ. b. How many sp? hybridized carbons are present? c. What is the hybridization of the N atom in the ring?arrow_forward
- CH3+ and CH3- are two highly reactive carbon species. a. What is the predicted hybridization and geometry around each carbon atom? b. Two electrostatic potential plots are drawn for these species. Which ion corresponds to which diagram and why?arrow_forwardprohibited. Remaining Time: 1 hour, 01 minute, 25 seconds. * Question Completion Status: A Moving to the next question prevents changes to this answer. Quèstion 2 In methyleyclohexane: O a. ring-carbon atoms are sp- hybridized and the methyl group is sp hybridized. O b. all bond angles are approximately 120°. C. all carbon atoms are sp hybridized. O d. ring-bond angles are approximately 120° and the ring-methyl bond angle is approximately 109°. A Moving to the next question prevents changes to this answer. O Type here to search hp 144 10 & %23 5 6. R T U W 3]arrow_forwardPredict the approximate bond angles for a. the C¬N¬C bond angle in (CH3)2N + H2. b. the C¬N¬H bond angle in CH3CH2NH2. c. the H¬C¬N bond angle in (CH3)2NH. d. the H¬C¬O bond angle in CH3OCH3.arrow_forward
- For CH3OCH2CH2 and CH3COCH, a. where are the locations of the partial charges? b. where are the dipole moments? c. what is the hybridization?arrow_forwardCitric acid is responsible for the tartness of citrus fruits, especially lemons and limes. [3] a. What is the molecular formula for citric acid? b. How many lone pairs are present? c. Draw a skeletal structure. d. How many sp? hybridized carbons are present? e. What orbitals are used to form each indicated bond ([1)–14))? [1]. [2] -[4] citric acidarrow_forwardWhich of the following compounds show cis-trans isomerism? Draw the cis and trans isomers of those that do. a. CHF=CHF b. C. F2C=CH2 CHCH,arrow_forward
- 2) Are these compounds chiral? Build models and take a picture, utilize online sketching software and take screen captures, draw diagrams or redraw the molecules to justify your answer? HOH HO. HN NH HOarrow_forwardThe arrow in the structure points to a bond that is formed by a. overlap between s and sp2 orbitals b. overlap between two sp orbitals c. overlap between two sp3 orbitals d. overlap between sp and sp2 orbitals e. overlap between sp2 and sp3 orbitalsarrow_forward26. TRUE or FALSE: The bond angles in the orthonitrate anion (NO43-) are all equal and each measure 109.5°. A. TRUE B. FALSE 27. Since the orthonitrate anion (NO43-) is best described as an acyclic molecule, which pairing describes the electronic structure and hybridization its central atom? A. Linear and sp B. Trigonal planar and sp2 C. Pyramidal and sp3 D. Tetrahedral and sp3 E. None of the above are correct 28. Recalling that orthonitrate anion (NO43-) is best described as acyclic, what is the formal charge at the central atom of this ion in its most important resonance form? А. —2 В. —1 С. О D. +1 Е. +2 29. Recalling that the orthonitrate anion (N043-) is best described as acyclic, how many non-bonded (lone) electron pairs are there (in total) in this ion in its most important resonance structure? A. 3 non-bonded (lone) electron pairs in total. B. 9 non-bonded (lone) electron pairs in total C. 11 non-bonded (lone) electron pairs in total D. 12 non-bonded (lone) electron pairs in…arrow_forward
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