Chapter 1, Problem 1.84EP

(a)

Interpretation Introduction

Interpretation:

Whether $N{O}_2$ has got more total atoms, same number of total atoms, or fewer total atoms than that of $N_{2}O$ has to be indicated.

Concept Introduction:

The composition of a chemical compound can be presented in a very precise was with the use of chemical formula.  Chemical formula uses chemical symbols of the elements that is present in the compound and numerical subscripts that represent how many number of atoms of each element is present in the compound.

Explanation of Solution

Given chemical formulas are $N{O}_{2}and{N}_{2}O$.

Total number of atoms in $N{O}_2$:  This contains one nitrogen atom and two oxygen atoms in its chemical formula.  Therefore, a total of three atoms are present in the chemical formula.

Total number of atoms in $N_{2}O$:  This contains two nitrogen atoms and one oxygen atom in its chemical formula.  Therefore, a total of three atoms are present in the chemical formula.

On comparing the total number of atoms between the two chemical formulas, it is found that they both contain same number of atoms.

(b)

Interpretation Introduction

Interpretation:

Whether $Cu{(S{O}_4)}_2$ has got more total atoms, same number of total atoms, or fewer total atoms than that of $CuS{O}_4$ has to be indicated.

Concept Introduction:

The composition of a chemical compound can be presented in a very precise was with the use of chemical formula.  Chemical formula uses chemical symbols of the elements that is present in the compound and numerical subscripts that represent how many number of atoms of each element is present in the compound.

Explanation of Solution

Given chemical formulas are $Cu{(S{O}_4)}_{2}andCuS{O}_4$.

Total number of atoms in $Cu{(S{O}_4)}_2$:  This contains one copper atom, two sulfur atom and eight oxygen atoms in its chemical formula.  Therefore, a total of nine atoms are present in the chemical formula.

Total number of atoms in $CuS{O}_4$:  This contains one copper atom, one sulfur atom and four oxygen atoms in its chemical formula.  Therefore, a total of six atoms are present in the chemical formula.

On comparing the total number of atoms between the two chemical formulas, it is found that $Cu{(S{O}_4)}_2$ contain more number of atoms than $CuS{O}_4$.

(c)

Interpretation Introduction

Interpretation:

Whether $KSCN$ has got more total atoms, same number of total atoms, or fewer total atoms than that of $NaBr{O}_2$ has to be indicated.

Concept Introduction:

The composition of a chemical compound can be presented in a very precise was with the use of chemical formula.  Chemical formula uses chemical symbols of the elements that is present in the compound and numerical subscripts that represent how many number of atoms of each element is present in the compound.

Explanation of Solution

Given chemical formulas are $KSCNandNaBr{O}_2$.

Total number of atoms in $KSCN$:  This contains one potassium atom, one sulfur atom, one carbon atom and one nitrogen atom in its chemical formula.  Therefore, a total of four atoms are present in the chemical formula.

Total number of atoms in $NaBr{O}_2$:  This contains one sodium atom, one bromine atom and two oxygen atoms in its chemical formula.  Therefore, a total of four atoms are present in the chemical formula.

On comparing the total number of atoms between the two chemical formulas, it is found that they both contain the same number of atoms.

(d)

Interpretation Introduction

Interpretation:

Whether $Al{(C_2{H}_3{O}_2)}_3$ has got more total atoms, same number of total atoms, or fewer total atoms than that of $Ba{(H_{2}P{O}_4)}_2$ has to be indicated.

Concept Introduction:

The composition of a chemical compound can be presented in a very precise was with the use of chemical formula.  Chemical formula uses chemical symbols of the elements that is present in the compound and numerical subscripts that represent how many number of atoms of each element is present in the compound.

Explanation of Solution

Given chemical formulas are $Al{(C_2{H}_3{O}_2)}_{3}andBa{(H_{2}P{O}_4)}_2$.

Total number of atoms in $Al{(C_2{H}_3{O}_2)}_3$:  This contains one aluminium atom, six carbon atoms, nine oxygen atoms and six oxygen atoms in its chemical formula.  Therefore, a total of twenty two atoms are present in the chemical formula.

Total number of atoms in $Ba{(H_{2}P{O}_4)}_2$:  This contains one barium atom, four hydrogen atoms, two phosphorus atoms, and eight oxygen atoms in its chemical formula.  Therefore, a total of fifteen atoms are present in the chemical formula.

On comparing the total number of atoms between the two chemical formulas, it is found that $Al{(C_2{H}_3{O}_2)}_3$ contain more number of atoms than $Ba{(H_{2}P{O}_4)}_2$.