Chapter 11, Problem 18SGR

To determine

To find: The area of the rhombus.

Answer to Problem 18SGR

The area of the rhombus is $168f{t}^2$ .

Explanation of Solution

Given Information: In figure a rhombus is given.

In figure a rhombus is given.

  $\begin{array}{l}{d}_1=2\times 12=24\mathrm{ft}\\ d_2=2\times 7=14\mathrm{ft}\end{array}$

Area of rhombus is:

  $\begin{array}{l}=\frac{1}{2}{d}_1{d}_2\\ =\frac{1}{2}\times 24\times 14\\ =24\times 7\\ =168f{t}^2\end{array}$

Thus, the area of the rhombus is $168f{t}^2$ .