Concept explainers
(a)
The
(a)
Answer to Problem 5PEB
The nuclear equation for the alpha emission decay is
Explanation of Solution
The nuclear equation for the alpha emission decay reaction for the given element is given as,
Here,
Thus the nuclear equation for the alpha emission decay reaction of americium is given as,
(b)
The nuclear equation for the alpha emission decay reaction for
(b)
Answer to Problem 5PEB
The nuclear equation for the alpha emission decay is
Explanation of Solution
The nuclear equation for the alpha emission decay reaction for the given element is given as,
Here,
Thus the nuclear equation for the alpha emission decay reaction of thorium is given as,
(c)
The nuclear equation for the alpha emission decay reaction for
(c)
Answer to Problem 5PEB
The nuclear equation for the alpha emission decay is
Explanation of Solution
The nuclear equation for the alpha emission decay reaction for the given element is given as,
Here,
Thus the nuclear equation for the alpha emission decay reaction of radium is given as,
(d)
The nuclear equation for the alpha emission decay reaction for
(d)
Answer to Problem 5PEB
The nuclear equation for the alpha emission decay is
Explanation of Solution
The nuclear equation for the alpha emission decay reaction for the given element is given as,
Here,
Thus the nuclear equation for the alpha emission decay reaction of uranium is given as,
(e)
The nuclear equation for the alpha emission decay reaction for
(e)
Answer to Problem 5PEB
The nuclear equation for the alpha emission decay is
Explanation of Solution
The nuclear equation for the alpha emission decay reaction for the given element is given as,
Here,
Thus the nuclear equation for the alpha emission decay reaction of curium is given as,
(f)
The nuclear equation for the alpha emission decay reaction for
(f)
Answer to Problem 5PEB
The nuclear equation for the alpha emission decay is
Explanation of Solution
The nuclear equation for the alpha emission decay reaction for the given element is given as,
Here,
Thus the nuclear equation for the alpha emission decay reaction of neptunium is given as,
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Chapter 11 Solutions
Integrated Science
- (a) Calculate the number of grams of deuterium in an 80.000L swimming pool, given deuterium is 0.0150% of natural hydrogen. (b) Find the energy released in joules if this deuterium is fused via the reaction 2H+2H3He+n. (c) Could the neutrons be used to create more energy? (d) Discuss the amount of this type of energy in a swimming pool as compared to that in, say, a gallon of gasoline, also taking into consideration that water is far more abundant.arrow_forward(a) Calculate BE/A for 235U, the rarer of the two most common uranium isotopes. (b) Calculate BE/A for 238U. (Most of uranium is 238U.) Note that 238U has even numbers at both protons and neutrons. Is the BE/A of 238U significantly different from that of 235U?arrow_forwardThe ceramic glaze on a red-orange “Fiestaware” plate is U2O3and contains 50.0 grams of 238U, but very little 235U. (a) What is the activity of the plate? (b) Calculate the total energy that will be released by the 238U decay, (c) If energy is worth 12.0 cents per kWh , what is the monetary value of the energy emitted? (These brightly- colored ceramic plates went out of production some 30 years ago, but are still available as collectibles.)arrow_forward
- (a) Calculate the energy released in the a decay of 238U . (b) What fraction of the mass of a single 238U is destroyed in the decay? The mass of 234Th is 234.043593 u. (c) Although the fractional mass loss is large for a single nucleus, it is difficult to observe for an entire macroscopic sample of uranium. Why is this?arrow_forward(a) Calculate the energy released in the a decay of 238U. (b) What fraction of the mass at a single 238U is destroyed in the decay? The mass of 234Th is 234.043593 u. (c) Although the fractional mass loss is laws for a single nucleus, it is difficult to observe for an entire macroscopic sample of uranium. Why is this?arrow_forwardUnreasonable Results The relatively scarce naturally occurring calcium isotope 48Ca has a halflife at about 21016y. (a) A small sample of this isotope is labeled as having an activity of 1.0 Ci. What is the mass of the 48Ca in the sample? (b) What is unreasonable about this result? (c) What assumption is responsible?arrow_forward
- Data from the appendices and the periodic table may be needed for these problems. Unreasonable Results (a) Repeat Exercise 31.57 but include the 0.0055% natural abundance of 234U with its 2.45105y halflife. (b) What is unreasonable about this result? (c) What assumption is responsible? (d) Where does the 234U come from if it is not primordial?arrow_forwardData from the appendices and the periodic table may be needed for these problems. The ceramic glaze on a red-orange Fiestaware plate is U2O3 and contains 50.0 grams of 238U, but very little 235U. (a) What is the activity of the plate? (b) Calculate the total energy that will be released by the 238U decay. (c) If energy is worth 12.0 cents per kW (h, what is the monetary value of the energy emitted? (These plates went out of production some 30 years ago, but are still available as collectibles.)arrow_forward(a) Calculate BEN for 235U, the rarer of the two most common uranium isotopes; (b) Calculate BEN for 238U(Most of uranium is 238U .)arrow_forward
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