Organic Chemistry (8th Edition)
Organic Chemistry (8th Edition)
8th Edition
ISBN: 9780134042282
Author: Paula Yurkanis Bruice
Publisher: PEARSON
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Chapter 11.1, Problem 1P
Interpretation Introduction

Interpretation:

From the given set of reactions the reactions those favor the formation of products have to be identified.

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Draw an energy diagram for the Brønsted–Lowry acid–base reaction of CH3CO2H with −OC(CH3)3 to form CH3CO2− and (CH3)3COH. Label the axes, starting materials, products, ΔH°, and Ea. Draw the structure of the transition state.
Which of the following two acids has the stronger conjugate base? Nitrous acid, Ka = 7.1 x 10–4                                          Phenol, Ka = 1.0 x 10–10 The strength of the conjugate base cannot be obtained from the information given. Nitrous acid, because it has a larger Ka value. Nitrous acid, because it has a smaller Ka value. Phenol, because it has a larger Ka value. Phenol, because it has a smaller Ka value.
For the following reaction, K> 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry acids or bases. CH3COOH + C18H2103NC18H2103NH+ + CH3COO- C18H2103NH+ CH3COO C18H2103N CH3COOH 1) Stronger Bronsted-Lowry acid 2) Weaker Bronsted-Lowry acid 3) Stronger Bronsted-Lowry base 4) Weaker Bronsted-Lowry base

Chapter 11 Solutions

Organic Chemistry (8th Edition)

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