Foundations of Materials Science and Engineering
Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
bartleby

Videos

Question
Book Icon
Chapter 11.13, Problem 102AAP
To determine

The viscosity of the soda-lime glass at the temperature of 675°C.

Expert Solution & Answer
Check Mark

Answer to Problem 102AAP

The viscosity of the soda-lime glass at the temperature of 675°C is 1011.33P.

Explanation of Solution

Write the equation involving the viscosity to temperature for a viscous flow in the glass.

  η=η0eQ/RT                                                                                                            (I)

Here, viscosity of the glass is η, pre-exponential constant is η0, molar activation energy for viscous flow is Q, universal gas constant is R and absolute temperature is T.

Conclusion:

At the temperature of 560°C, write the equation involving the viscosity to temperature for a viscous flow in the glass.

  η1=η0eQ/RT1                                                                                                          (II)

Here, viscosity of the soda-lime glass at the temperature of 560°C is η1 and initial temperature of the soda-lime glass is T1.

At the temperature of 675°C, write the equation involving the viscosity to temperature for a viscous flow in the glass.

  η2=η0eQ/RT2                                                                                                        (III)

Here, viscosity of the soda-lime glass at the temperature of 675°C is η2 and final temperature of the soda-lime glass is T2.

Divide Equation (II) by Equation (III).

  η1η2=η0eQ/RT1η0eQ/RT2=eQ/RT1eQ/RT2=exp[QR(1T11T2)]                                                                                  (IV)

Substitute 1014.6P for η1, 430kJ/mol for Q, 8.314J/molK for R, 560°C for T1 and 675°C for T2 in Equation (IV).

 1014.6Pη2=exp[430kJ/mol8.314J/molK(1560°C1675°C)]1014.6Pη2=exp[430×103J/mol8.314J/molK(1833K1948K)]1014.6Pη2=exp(7.532)1014.6Pη2=1866.6

 η2=1014.6P1866.6=2.133×1011P=1011.329P=1011.33P

Thus, the viscosity of the soda-lime glass at the temperature of 675°C is 1011.33P.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
What are the strengths and weaknesses of this Visceoelastic model?
Calcium oxide (CaO) is a ceramic that has the same crystal strudture as NaCl. Given: R(Ca2)= 0.106 nm and R(O²)-0.132 Calculate the lonic Packing Factor (IPF) of CaO? Select one: Oa. 0.542 Ob.0.21 Oc.0.41 Od.0.12 Oe 0.47 O to.14 Og0.51 On074. 9:12 PM A D 4) ENG 15-Apr-2021
Calculate the residual molar entropy for molecular crystals of 1,3,5-Trichlorobenzene

Chapter 11 Solutions

Foundations of Materials Science and Engineering

Ch. 11.13 - Prob. 11KCPCh. 11.13 - Prob. 12KCPCh. 11.13 - Prob. 13KCPCh. 11.13 - Prob. 14KCPCh. 11.13 - Describe the feldspar network structure.Ch. 11.13 - Prob. 16KCPCh. 11.13 - Prob. 17KCPCh. 11.13 - Describe two methods for preparing ceramic raw...Ch. 11.13 - Prob. 19KCPCh. 11.13 - Prob. 20KCPCh. 11.13 - Prob. 21KCPCh. 11.13 - Prob. 22KCPCh. 11.13 - Prob. 23KCPCh. 11.13 - Prob. 24KCPCh. 11.13 - Prob. 25KCPCh. 11.13 - Prob. 26KCPCh. 11.13 - What are the purposes of drying ceramic products...Ch. 11.13 - Prob. 28KCPCh. 11.13 - What is the vitrification process? In what type of...Ch. 11.13 - Prob. 30KCPCh. 11.13 - Prob. 31KCPCh. 11.13 - Prob. 32KCPCh. 11.13 - Prob. 33KCPCh. 11.13 - Prob. 34KCPCh. 11.13 - Prob. 35KCPCh. 11.13 - Prob. 36KCPCh. 11.13 - Prob. 37KCPCh. 11.13 - Prob. 38KCPCh. 11.13 - Why do most ceramic materials have low thermal...Ch. 11.13 - Prob. 40KCPCh. 11.13 - Prob. 41KCPCh. 11.13 - Prob. 42KCPCh. 11.13 - Prob. 43KCPCh. 11.13 - Prob. 44KCPCh. 11.13 - Prob. 45KCPCh. 11.13 - Prob. 46KCPCh. 11.13 - How is a glass distinguished from other ceramic...Ch. 11.13 - Prob. 48KCPCh. 11.13 - Prob. 49KCPCh. 11.13 - Prob. 50KCPCh. 11.13 - Prob. 51KCPCh. 11.13 - Prob. 52KCPCh. 11.13 - Prob. 53KCPCh. 11.13 - Prob. 54KCPCh. 11.13 - Prob. 55KCPCh. 11.13 - Prob. 56KCPCh. 11.13 - Prob. 57KCPCh. 11.13 - Prob. 58KCPCh. 11.13 - Prob. 59KCPCh. 11.13 - Prob. 60KCPCh. 11.13 - Prob. 61KCPCh. 11.13 - Prob. 62KCPCh. 11.13 - Prob. 63AAPCh. 11.13 - Prob. 64AAPCh. 11.13 - Prob. 65AAPCh. 11.13 - Prob. 66AAPCh. 11.13 - Prob. 67AAPCh. 11.13 - Prob. 70AAPCh. 11.13 - Calculate the ionic packing factor for (a) MnO and...Ch. 11.13 - Prob. 72AAPCh. 11.13 - Prob. 73AAPCh. 11.13 - Prob. 74AAPCh. 11.13 - Prob. 75AAPCh. 11.13 - Prob. 77AAPCh. 11.13 - Prob. 78AAPCh. 11.13 - Prob. 79AAPCh. 11.13 - Prob. 80AAPCh. 11.13 - Prob. 81AAPCh. 11.13 - Why are triaxial porcelains not satisfactory for...Ch. 11.13 - Prob. 83AAPCh. 11.13 - Prob. 84AAPCh. 11.13 - Prob. 85AAPCh. 11.13 - What causes the lack of plasticity in crystalline...Ch. 11.13 - Prob. 87AAPCh. 11.13 - Prob. 88AAPCh. 11.13 - Prob. 89AAPCh. 11.13 - A reaction-bonded silicon nitride ceramic has a...Ch. 11.13 - Prob. 91AAPCh. 11.13 - Prob. 92AAPCh. 11.13 - Prob. 93AAPCh. 11.13 - Prob. 94AAPCh. 11.13 - How does the silica network of a simple silica...Ch. 11.13 - Prob. 96AAPCh. 11.13 - Prob. 97AAPCh. 11.13 - Prob. 98AAPCh. 11.13 - Prob. 99AAPCh. 11.13 - Prob. 100AAPCh. 11.13 - Prob. 101AAPCh. 11.13 - Prob. 102AAPCh. 11.13 - Prob. 103AAPCh. 11.13 - Prob. 104AAPCh. 11.13 - Prob. 105AAPCh. 11.13 - Prob. 106AAPCh. 11.13 - Prob. 107AAPCh. 11.13 - Prob. 108SEPCh. 11.13 - Prob. 109SEPCh. 11.13 - Prob. 110SEPCh. 11.13 - Prob. 111SEPCh. 11.13 - Prob. 112SEPCh. 11.13 - Alumina (A12O3) and chromium oxide (Cr2O3) are...Ch. 11.13 - (a) How are the ceramic tiles used in the thermal...Ch. 11.13 - The nose cap and the wing leading edges of the...Ch. 11.13 - Prob. 116SEPCh. 11.13 - Prob. 117SEPCh. 11.13 - Prob. 118SEPCh. 11.13 - Prob. 119SEPCh. 11.13 - Prob. 120SEPCh. 11.13 - Prob. 121SEPCh. 11.13 - Prob. 122SEPCh. 11.13 - Prob. 123SEPCh. 11.13 - Prob. 124SEPCh. 11.13 - Prob. 125SEPCh. 11.13 - Prob. 126SEPCh. 11.13 - Prob. 127SEPCh. 11.13 - Prob. 128SEPCh. 11.13 - Prob. 129SEP
Knowledge Booster
Background pattern image
Mechanical Engineering
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Text book image
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Text book image
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Text book image
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Text book image
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Text book image
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Polymer Basics; Author: Tonya Coffey;https://www.youtube.com/watch?v=c5gFHpWvDXk;License: Standard youtube license