Understanding Our Universe
3rd Edition
ISBN: 9780393614428
Author: PALEN, Stacy, Kay, Laura, Blumenthal, George (george Ray)
Publisher: W.w. Norton & Company,
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 11.2, Problem 11.2CYU
To determine
The different processes through which the energy travel from core to outer surface in Sun.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The Sun has a radius of about 700,000 km and a surface temperature of 5800 K. Assuming it is a perfect blackbody (an emissivity of 1), what is the rate of energy radiated (in W) from the surface of the Sun? (Hint: the surface area of a sphere is 4πR2; enter your answer in scientific notation, 1.23E12 means 1.23 * 1012).
The sun has a radius of 6.959 × 108 m and a surface temperature of 5.81 x 10° K.
When the sun radiates at a rate of 3.91 x 1026 W and is a perfect emitter. What is
the rate of energy emitted per square meter? Stefan-Boltzmann constant is 5.67 x
10-8 J/s-m2 K4
a)
5.6 x 107 W/m2
b) 12.8 x 107 W/m2
c)
6.4 x 107 W/m2
25.6 x 107 W/m2
5.6 x 1017 W/m2
Proxima Centauri, the nearest star
to our Sun, has a surface
temperature of 2,768.85 °C. What is
its total intensity emitted?
O 4.3 MW per square meter.
O 4.9 MW per square meter.
O 5.2 MW per square meter.
O 5.7 MW per square meter.
O 6.4 MW per square meter.
Chapter 11 Solutions
Understanding Our Universe
Ch. 11.1 - Prob. 11.1CYUCh. 11.2 - Prob. 11.2CYUCh. 11.3 - Prob. 11.3CYUCh. 11.4 - Prob. 11.4CYUCh. 11 - Prob. 1QAPCh. 11 - Prob. 2QAPCh. 11 - Prob. 3QAPCh. 11 - Prob. 4QAPCh. 11 - Prob. 5QAPCh. 11 - Prob. 6QAP
Ch. 11 - Prob. 7QAPCh. 11 - Prob. 8QAPCh. 11 - Prob. 9QAPCh. 11 - Prob. 10QAPCh. 11 - Prob. 11QAPCh. 11 - Prob. 12QAPCh. 11 - Prob. 13QAPCh. 11 - Prob. 14QAPCh. 11 - Prob. 15QAPCh. 11 - Prob. 16QAPCh. 11 - Prob. 17QAPCh. 11 - Prob. 18QAPCh. 11 - Prob. 19QAPCh. 11 - Prob. 20QAPCh. 11 - Prob. 21QAPCh. 11 - Prob. 22QAPCh. 11 - Prob. 23QAPCh. 11 - Prob. 24QAPCh. 11 - Prob. 25QAPCh. 11 - Prob. 26QAPCh. 11 - Prob. 27QAPCh. 11 - Prob. 28QAPCh. 11 - Prob. 29QAPCh. 11 - Prob. 30QAPCh. 11 - Prob. 31QAPCh. 11 - Prob. 32QAPCh. 11 - Prob. 33QAPCh. 11 - Prob. 34QAPCh. 11 - Prob. 35QAPCh. 11 - Prob. 36QAPCh. 11 - Prob. 37QAPCh. 11 - Prob. 38QAPCh. 11 - Prob. 39QAPCh. 11 - Prob. 40QAPCh. 11 - Prob. 41QAPCh. 11 - Prob. 42QAPCh. 11 - Prob. 43QAPCh. 11 - Prob. 44QAPCh. 11 - Prob. 45QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Give proper explanation The surface temperature of the Sun is about 5750 K. What is this temperature on the Fahrenheit scale?arrow_forwardUsing the provided equation of radiative energy transport, find an estimate for the central temperature of the sun. (Hint: the average opacity of the sun is κ⨀ = 8 m2 kg-1)arrow_forwardClimate scientists use the Stefan-Boltzmann Law R=oT4 to estimate the change in the earth's average temperature T (in kelvins) that results from a change in the radiation R (in joules per square meter per second) that the earth receives from the sun. Here, o = 5.67 x 10-8 Js-'m-²K-4. Calculate d R/dt, assuming that T = 283 and 4 = 0.05 K/year. What are the units of dR/dt? %3D dtarrow_forward
- Why are measurements of the Sun's 10.7 cm radio emission used to monitor the state of the solar cycle? Choose all correct answers. A. It provides a repeatable, objective measurement of solar activity B. It serves as a good proxy for EUV emissions C. It is measured from space, so it is not affected by clouds D. It can be used to predict the occurrence of coronal mass ejectionsarrow_forwardThe planet Venus is different from the earth in several respects. First, it is only 70% as far from the sun. Second, its thick clouds reflect 77% of all incident sunlight. Finally, its atmosphere is much more opaque to infrared light. Calculate the solar constant at the location of Venus, and estimate what the average surface temperature of Venus would be if it had no atmosphere and did not reflect any sunlight.arrow_forward(W/m), in Santa solar radiation into energy- solar radiation (w/m?) 400 300 200 100 time (hrs past midnight) 4 8 12 16 20 ot dengndi loarrow_forward
- Near the martian equator, temperatures at the same spot can vary from an average of 135 °C at night to an average of 30 °C during the day. How can you explain such a wide difference in temperature compared to that on Earth?arrow_forwardOur Sun shines bright with a luminosity of 3.828 x 1026 Watt. Her energy is responsible for many processes and the habitable temperatures on the Earth that make our life possible. Calculate the amount of energy arriving on the Earth in a single day. To how many litres of heating oil (energy density: 37.3 x 106 J/litre) is this equivalent? The Earth reflects 30% of this energy: Determine the temperature on Earth’s surface. What other factors should be considered to get an even more precise temperature estimate? Note: The Earth’s radius is 6370 km; the Sun’s radius is 696 x 103 km; 1 AU is 1.495 x 108 km.arrow_forwardThe best solar panels currently available are about 19% efficient in converting sunlight to electricity. A typical home will use about 40. kWh of electricity per day (1 kWh=1 kilowatt hour; 1kW=1000J/s). Assuming 8.1 hours of useful sunlight per day, calculate the minimum solar panel surface area necessary to provide all of a typical home’s electricity. The energy rate supplied by the sun is 1.0kJ/s times meters squared . Area = meters squaredarrow_forward
- The radiant flux at Earth is 1365 W/m2. Say we move towards the sun to a radius that is 1/3 the radius of the Earth's orbit. By what factor would the radiant flux increase or decrease?arrow_forwardDescribe how a convection current works. In a simple way.arrow_forwardThe average temperature of the atmosphere has increased by 0.4°C over the last thirty years. Estimate how much energy has gone into warming up the planet in this way. Keep in mind that the atmosphere has a mass of 5 × 1018kg, and the specific heat capacity of air is about 1 Jg−1K−1. How do we get to this answer (2×1021J)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
AstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStax
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Astronomy
Physics
ISBN:9781938168284
Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff
Publisher:OpenStax