Concept explainers
(a)
To find:the number of possible sets of heads and tails that has
(a)
Answer to Problem 11CFU
There is only one set that will have
Explanation of Solution
Given: A coin is flipped five times.
Concept used:
Using binomial or pascal triangle the possible sets in the form of equation can be expanded.
Where
Coin is tossed or flipped
Calculation:
Let
Use the sixth row of pascals triangle for the expansion.
To have
The coefficient of
Hence, there is only one set that will have
(b)
To find:the number of possible sets of heads and tails that has
(b)
Answer to Problem 11CFU
The possible sets are
Explanation of Solution
Given:
A coin is flipped five times.
Concept used:
Using binomial or pascal triangle the possible sets in the form of equation can be expanded.
Where
Coin is tossed or flipped
the number of head and tail is represented by the power of
Calculation:
Let
Use the sixth row of pascals triangle for the expansion.
To have the
since, the coefficient of
Hence, the possible sets are
(c)
To find:the number of possible sets of heads and tails that has at least
(c)
Answer to Problem 11CFU
There is
Explanation of Solution
Given:
A coin is flipped five times.
Concept used:
Using binomial or pascal triangle the possible sets in the form of equation can be expanded.
Where
Coin is tossed or flipped
the number of head and tail is represented by the power of
Calculation:
Let
Use the sixth row of pascals triangle for the expansion.
To have the at least
The total number of sets is the same as the sum of coefficient of
Since, the sum of coefficient of
Hence, there is
(d)
To find:the number of possible sets of heads and tails that has at least
(d)
Answer to Problem 11CFU
There is
Explanation of Solution
Given:
A coin is flipped five times.
Concept used:
Using binomial or pascal triangle the possible sets in the form of equation can be expanded.
Where
Coin is tossed or flipped
the number of head and tail is represented by the power of
Calculation:
Let
Use the sixth row of pascals triangle for the expansion.
To have the at most
The total number of sets is the same as the sum of coefficient of
Since, the sum of coefficient of
Hence, there is
Chapter 12 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Additional Math Textbook Solutions
Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
Calculus: Early Transcendentals (3rd Edition)
Thomas' Calculus: Early Transcendentals (14th Edition)
Calculus and Its Applications (11th Edition)
Calculus: Early Transcendentals (2nd Edition)
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