To find: The measure of variation and any outliers for the given set of data
Answer to Problem 4PPS
Range is
Median is
Lower quartile is
Upper quartile is
Interquartile range is
Outlier is
Explanation of Solution
Given:
Calculation:
The given data is
Arrange this set of the data in numeric order
Hence, the range is given by
The median is 92
The lower quartile is the median of the left half of the data.
So, lower quartile is given by
The upper quartile is the median of the right half of the data.
So, upper quartile is given by
Therefore, the interquartile range is given by
Now, outliers are the data which is below
So, find the value for these expressions
And
So, the outliers are the value which is below
So, the outlier for the given set of data is
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