Campbell Biology (10th Edition)
10th Edition
ISBN: 9780321775658
Author: Jane B. Reece, Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Robert B. Jackson
Publisher: PEARSON
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Chapter 14.1, Problem 1CC
DRAW IT Ø Pea plants heterozygous for flower position and stem length (AaTt) are allowed to self-pollinate, and 400 of the resulting seeds are planted. Draw a Punnett Square for this cross. How many offspring would be predicted to have terminal flowers and be dwarf? (See Table 14.1.)
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list all gamets that could be made by a pea plant heterozygous for seed colour, seed shape and pod shape(Yy, Rr, Ii) what size punnett square would you need to determine offspring of self pollination of this hybrid
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produced by a plant that is heterozygous for both traits? hint* This is a dihybrid self cross of an F1 heterozygous
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A pea plant is heterozygous for three genes (Tt Rr Yy), whereT = tall, t = dwarf, R = round seeds, r = wrinkled seeds, Y = yellowseeds, and y = green seeds. Tall, round, and yellow are the dominanttraits. What is the probability that an offspring from self-fertilizationof this plant will be tall with wrinkled, yellow seeds?
Chapter 14 Solutions
Campbell Biology (10th Edition)
Ch. 14.1 - DRAW IT Pea plants heterozygous for flower...Ch. 14.1 - WHAT IF? List all gametes that could be made by a...Ch. 14.1 - MAKE CONNECTIONS In some pea plant crosses, the...Ch. 14.2 - Prob. 1CCCh. 14.2 - Two organisms, with genotypcs BbDD and BBDd, are...Ch. 14.2 - WHAT IF? Three characters (flower color, seed...Ch. 14.3 - What two properties, one structural and one...Ch. 14.3 - If a man with type AB blood marries a woman with...Ch. 14.3 - WHAT IF? A rooster with gray feathers and a hen...Ch. 14.4 - Beth and Tom each have a sibling with cystic...
Ch. 14.4 - Prob. 2CCCh. 14.4 - Prob. 3CCCh. 14.4 - MAKE CONNECTIONS In Table 14.1, note the...Ch. 14 - When Mendel did crosses of true-breeding purple-...Ch. 14 - DRAW IT Redraw the Punnett Square on The right...Ch. 14 - Inheritance patterns are often more complex than...Ch. 14 - Both members of a couple know that they are...Ch. 14 - DRAW IT Two pea plants heterozygous for the...Ch. 14 - A man with type A blood marries a woman with type...Ch. 14 - A man has six fingers on each hand and six toes on...Ch. 14 - DRAW IT A pea plant heterozygous for inflated pods...Ch. 14 - Flower position, stem length, and seed shape are...Ch. 14 - Prob. 6TYUCh. 14 - The genotype of F1, individuals in a tetrahybrid...Ch. 14 - What is the probability that each of thc following...Ch. 14 - Prob. 9TYUCh. 14 - Prob. 10TYUCh. 14 - In tigers, a recessive allele of a particular gene...Ch. 14 - In maize (com) plants,a dominant allele I inhibits...Ch. 14 - The pedigree belowtraces the inheritance of...Ch. 14 - Imagine that you are a genetic counselor, and a...Ch. 14 - EVOLUTION CONNECTION Over the past half century,...Ch. 14 - SCIENTIFIC INQUIRY You are handed a mystery pea...Ch. 14 - Prob. 17TYUCh. 14 - SYNTHESIZE YOUR KNOWLEDGE Just for fun, imagine...
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- Y = yellow, y = green; R = round seed, r = wrinkled seed Dihybrid cross: If you mate YyRr x YyRr then what proportion of offspring will be green and wrinkled? 6/16 3/16 O 1/16 O 9/16arrow_forwardSuppose a purple flower heterozygous for stem size is crossed with a large stem (dominant) purple flower. What are the possible genotypes and phenotypes of offspring?arrow_forward. In nature, the plant Plectritis congesta is dimorphic forfruit shape; that is, individual plants bear either winglessor winged fruits, as shown in the illustration.Wingless fruit Winged fruitPlants were collected from nature before floweringand were crossed or selfed with the following results:Number of progenyPollination Winged WinglessWinged (selfed) 91 1*Winged (selfed) 90 30Wingless (selfed) 4* 80Winged × wingless 161 0Winged × wingless 29 31Winged × wingless 46 0Winged × winged 44 0*Phenotype probably has a nongenetic explanation.Interpret these results, and derive the mode ofinheritance of these fruit-shaped phenotypes. Usesymbols. What do you think is the nongeneticexplanation for the phenotypes marked by asterisks inthe table?arrow_forward
- as: For pea plant, yellow seeds coat are dominant ov green seed coat, and long stems are dominant over she stem. Determine the phenotype and genotype rations the F1 offspring from cross-pollination of a heterozygous yellow seed coat, a homozygous long stem plant.arrow_forwardSuppose you have an AAaa tetraploid plant and it undergo self- fertilization. At least two copies of the dominant allele A are needed to obtain the dominant phenotype. At what frequency will progeny with the dominant phenotype appear?arrow_forwardIdentify the genotypes of the pea flower plants for each generation P (Guadretieding parents) Phenotypes Purple flowers : Genotypes White flowers 1 2 F1 Gerleyatids) Phenotypes All purple flowers : Genotypes 3 Self- or cross-pollination F2 Generation Phenotypes Purple flowers : Genotypes White flowers 4arrow_forward
- Round seed is dominant over wrinkled. Yellow cotyledon is dominant overgreen. Full pod is dominant over constricted. The genes for these traits arefound on separate chromosomes. If a trihybrid plant is self-fertilized, whatproportion of the progeny will have round seeds in constricted pods?Express answer in fraction form.arrow_forwardA pea plant that is (RrYy) is allowed to self-fertilize. Round seed(R) is dominant to wrinkled (r), and yellow seed (Y) is dominant togreen (y). What is the probability of producing the following groupof five seeds: two round, yellow; one round, green; one wrinkled,yellow; and one wrinkled, green?arrow_forwardConsider a corn plant dihybrid for the traits of purple and smooth kernels. When allowed to self-fertilize, 489 offspring are produced. How many of these offspring are expected to exhibit the traits of yellow and smooth kernels?arrow_forward
- GgTt pea plants can produce _____ type(s) of gamete(s), but a ggtt plant can produce _____ type(s) of gamete(s). explainarrow_forwardThis image shows the offspring that result from a dihybrid cross between a plant with wrinkled green seeds and a plant with round yellow seeds. Generation Generation 2 round, yellow wrinkled, yel wrled green How can this graphic be used to support the idea of independent assortment? O The fact that the seeds can be one of two different colors shows that the chromosomes with the seed color gene must sort independently. O The fact that the seeds can be one of two different textures shows that the chrorhosomes with the seed texture gene must sort independently. O The idea that alleles sort independently is supported by the fact that some second generation offspring have trait combinations that the first generation parents do not have. O The idea that alleles sort independently is supported by the fact that some second generation offspring have the same trait combinations that the first generation parents have. https://student.masteryconnect.com/?iv=it4119tzPsQ…arrow_forwardCharacter Seed Shape Round (R) Wrinkled (r) Seed Color Yellow (Y) Green (y) Pod Shape Inflated (I) Constricted (i) If a plant that is heterozygous for all theses characters is crossed with a plant homozygous dominant for seed shape and seed color and heterozygous for pod shape, what proportion of the offspring would you expect to be as follows: 1. Homozygous dominant for the three characters. (Answer in fraction) ____ 2. Recessive for the three characters. (Answer in fraction) _________ 3. Heterozygous dominant for the three characters. Answer in fraction) _______arrow_forward
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