Physics of Everyday Phenomena
Physics of Everyday Phenomena
9th Edition
ISBN: 9781259894008
Author: W. Thomas Griffith, Juliet Brosing Professor
Publisher: McGraw-Hill Education
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Chapter 16, Problem 2SP

(a)

To determine

The position of first bright fringe.

(a)

Expert Solution
Check Mark

Answer to Problem 2SP

The position of first bright fringe is 17.1 mm away from the center at each side.

Explanation of Solution

Given info:

Wavelength of the light is 580nm, order of bright fringe is 1, the distance of screen from slits is 1.3m and spacing between adjacent slits is 0.044mm.

Write an expression for condition of maxima.

y=nλDd

Here,

y is the distance of nth bright fringe from center

n is the order of the bright fringe

D is the screen’s distance from slit

λ is the wavelength

d is the slit separation

Substitute 580nm for λ, 1 for n, 1.3m for D and 0.044mm for d to find y.

y=(1)((580nm)(1m109nm))(1.3m)(0.044mm)(1m103mm)=17.1×103m=(17.1×103m)(1mm103m)=17.1mm

Thus, the position of first bright fringe is 17.1 mm away from the center at each side.

Conclusion:

The position of first bright fringe is 17.1 mm away from the center at each side.

(b)

To determine

The position of second bright fringe.

(b)

Expert Solution
Check Mark

Answer to Problem 2SP

The position of second bright fringe is 34.3 mm away from the center at each side.

Explanation of Solution

Given info:

Wavelength of the light is 580nm, order of bright fringe is 2, the distance of screen from slits is 1.3m and spacing between adjacent slits is 0.044mm.

Write an expression for condition of maxima.

y=nλDd

Here,

y is the distance of nth bright fringe from center

n is the order of the bright fringe

D is the screen’s distance from slit

λ is the wavelength

d is the slit separation

Substitute 580nm for λ, 2 for n, 1.3m for D and 0.044mm for d to find y.

y=(2)((580nm)(1m109nm))(1.3m)(0.044mm)(1m103mm)=34.3×103m=(34.3×103m)(1mm103m)=34.3mm

Thus, the position of second bright fringe is 34.3 mm away from the center at each side.

Conclusion:

The position of second bright fringe is 34.3 mm away from the center at each side.

(c)

To determine

The position of first dark bright fringe.

(c)

Expert Solution
Check Mark

Answer to Problem 2SP

The position of first dark fringe is 25.7 mm away from the center at each side.

Explanation of Solution

Given info:

Wavelength of the light is 580nm, order of dark fringe is 1, the distance of screen from slits is 1.3m and spacing between adjacent slits is 0.044mm.

Write an expression for condition of minima.

y=(n+12)λDd

Here,

y is the distance of nth dark fringe from center

n is the order of the bright fringe

D is the screen’s distance from slit

λ is the wavelength

d is the slit separation

Substitute 580nm for λ, 1 for n, 1.3m for D and 0.044mm for d to find y.

y=(1+12)((580nm)(1m109nm))(1.3m)(0.044mm)(1m103mm)=25.7×103m=(25.7×103m)(1mm103m)=25.7mm

Thus, the position of first dark fringe is 25.7 mm away from the center at each side.

Conclusion:

The position of first dark fringe is 25.7 mm away from the center at each side.

(d)

To determine

Sketch the diffraction pattern and mark the position of the fringes.

(d)

Expert Solution
Check Mark

Answer to Problem 2SP

The diffraction pattern is given in figure 1.

Explanation of Solution

Following figure gives the diffraction pattern.

Physics of Everyday Phenomena, Chapter 16, Problem 2SP

Figure 1

Here, the first, second and third order bright fringes will appear at distance of 17.1 mm, 34.3 mm and 51.4 mm from center respectively at each side of the central maxima. The dark fringes of order 1, 2 and 3 will form distances 25.7 mm, 42.8 mm and 60.0 mm respectively.

Conclusion:

The diffraction pattern is given in figure 1.

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Students have asked these similar questions
Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.7 m from the slits. The center of the third order bright band on the screen is separated from the central maximum by 0.90 m. A. Determine the frequency of the light. B. Determine the angle of the third-order bright band. C. Determine the slit separation.
Light with a wavelength of 646 nm passes through two slits and forms an interference pattern on a screen 8.75 Im away. The distance between the two second-order bright fringe is 10.32 cm. What is the separation between the slits? A. 1.99 x 10-4 m B. 3.55 x 10-4 m C.1.10 x 10-4 m D.2.19 x 10-4 m E. 3.01 x 10-4 m
Light with a wavelength of 646 nm passes through two slits and forms an interference pattern on a screen 8.75 Im away. The distance between the two second-order bright fringe is 10.32 cm. What is the angle of the third order minimum fringe? A. 3.98 B. 0.42. C. 0.02. D.0.84° E. 0.11.

Chapter 16 Solutions

Physics of Everyday Phenomena

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