(a)
Interpretation:
The balanced half reactions for the given reaction have to be stated.
Concept Introduction:
(a)
Answer to Problem 13QRT
The half reaction that represents oxidation is as follows.
The half reaction that represents reduction is as follows.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of bromine is
Apply charge balance formula in
Therefore, the oxidation number of iron in
In the given reaction, the oxidation number of
The oxidation number of
The half reaction that represents oxidation is as follows.
The half reaction that represents reduction is as follows.
(b)
Interpretation:
The balanced half reactions for the given reaction have to be stated.
Concept Introduction:
Refer to part (a).
(b)
Answer to Problem 13QRT
The half reaction that represents oxidation is as follows.
The half reaction that represents reduction is as follows.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of chlorine is
Apply charge balance formula in
Therefore, the oxidation number of aluminium in
In the given reaction, the oxidation number of
The oxidation number of
The half reaction that represents oxidation is as follows.
The half reaction that represents reduction is as follows.
(c)
Interpretation:
The balanced half reactions for the given reaction have to be stated.
Concept Introduction:
Refer to part (a).
(c)
Answer to Problem 13QRT
The half reaction that represents oxidation is as follows.
The balanced half cell reaction represents reduction is shown below.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element in its native form is zero. So, the oxidation number of
In almost all compounds oxidation number of iodine is
Apply charge balance formula in
Therefore, the oxidation number of sulfur in
Apply charge balance formula in
Therefore, the oxidation number of sulfur in
In the given reaction, the oxidation number of sulfur changes from
The oxidation number of
The half reaction that represents oxidation is as follows.
The half reaction that represents reduction is as follows.
The number of oxygen atoms is balanced by adding four molecules of water on product side as shown below.
In acidic medium, the number of hydrogen atoms is balanced by adding
The charge on reactant side is
The balanced half cell reaction represents reduction is shown below.
(d)
Interpretation:
The balanced half reactions for the given reaction have to be stated.
Concept Introduction:
Refer to part (a).
(d)
Answer to Problem 13QRT
The half reaction that represents oxidation is as follows.
The balanced half cell reaction represents reduction is shown below.
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element carrying charge is equal to that charge. So, the oxidation number of
In almost all compounds oxidation number of hydrogen is
Apply charge balance formula in
Therefore, the oxidation number of oxygen in
Apply charge balance formula in
Therefore, the oxidation number of oxygen in
In the given reaction, the oxidation number of
The oxidation number of
The half reaction that represents oxidation is as follows.
The reaction for the conversion of
The number of oxygen atoms is balanced by adding one molecule of water on product side as shown below.
In acidic medium, the number of hydrogen atoms is balanced by adding
The charge on reactant side is
The balanced half cell reaction represents reduction is shown below.
(e)
Interpretation:
The balanced half reactions for the given reaction have to be stated.
Concept Introduction:
Refer to part (a).
(e)
Answer to Problem 13QRT
The half cell reaction for oxidation of
The half cell reaction for reduction of
Explanation of Solution
The given reaction is shown below.
The oxidation number of any element carrying charge is equal to that charge. So, the oxidation number of
In almost all compounds oxidation number of hydrogen is
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of nitrogen in
Apply charge balance formula in
Therefore, the oxidation number of iron in
In the given reaction, the oxidation number of
In the given reaction, the oxidation number of
The oxidation number of
The reaction for the oxidation of
The number of oxygen atoms is balanced by adding four molecules of water on reactant side as shown below.
In acidic medium, the number of hydrogen atoms is balanced by adding
The charge on reactant side is zero and the charge on product side is
The half cell reaction for oxidation of
The reaction for the reduction of
The number of oxygen atoms is balanced by adding two molecules of water on product side as shown below.
In acidic medium, the number of hydrogen atoms is balanced by adding
The charge on reactant side is
The half cell reaction for reduction of
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Chapter 17 Solutions
Chemistry: The Molecular Science
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- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning