Concept explainers
Calculate the molar solubility of
Interpretation:
The molar solubility of
Concept introduction:
The amount of solute dissolved in a given volume of the solvent to form a saturated solution at a given temperature is termed as the solubility of the solute in the solvent at that temperature.
The solubility product of a sparinglysoluble salt is given as the product of the concentration of the ions raised to the power equal to the number of times the ion occurs in the equation after the dissociation of the electrolyte.
The number of moles of solute dissolved per litre of solution is called molar solubility.
Molar solubility of a substance is defined as the number of moles of solution present in one liter of saturated solution.
The unit of molar solubility is
At a given temperature, the product of molar concentrations of the ions of salt present in the solution is known as the solubility product of the salt. It is represented by
Higher is the value of solubility product of a salt, more is its solubility.
The presence of common ions in the solution decreases the solubility of a given compound.
For a general reaction:
The solubility product can be calculated by the expression as:
Here,
The expression of
The relation between
Answer to Problem 69QP
Solution:
a)
The molar solubility of
b)
The molar solubility of
Explanation of Solution
a)ApH is
The equation of the dissociation of
The concentration of
The concentration of
Substitute the value of
The concentration of
Summarise the concentrations at equilibrium as follows:
Consider s to be the molar solubility.
The equilibrium expression for a reaction is written as follows:
Here,
Substitute the values of
The value of s is very small as compared to
On solving further,
Hence, the molar solubility of
b) ApH is
The equation of the dissociation of
The value of
The concentration of
Substitute the value of
Summarise the concentrations at equilibrium as follows
Consider s to be the molar solubility.
The equilibrium expression for a reaction is written as follows:
Here,
Substitute the values of
The value of s is very small as compared to
On solving further,
Hence, the molar solubility of
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