Concept explainers
(a)
Interpretation:
The
Concept introduction:
The number of unshared valence electrons on the metal is the number
Answer to Problem 18.9P
The
Explanation of Solution
The formula for calculation of
The formula for the calculation of oxidation state is given below
• n is the number of ligands.
•
•
•
Therefore, the oxidation state of
Now, valence electronic configuration of
L-type ligands have no effect on the
Value of
Therefore, the given complex is a
The value of
(b)
Interpretation:
The
Concept introduction:
The number of unshared valence electrons on the metal is the number
Answer to Problem 18.9P
The
Explanation of Solution
The formula for calculation of
The oxidation state of the metal is calculated by the formula given below.
Since phosphine is a neutral ligand and there is no overall charge on the complex.
The formula for the calculation of oxidation state is given below
• n is the number of ligands
•
•
•
So, the oxidation state of Pd in the complex is calculated as shown below.
Now, valence electronic configuration of
Value of
Therefore, the given complex is a
The value of
(c)
Interpretation:
The
Concept introduction:
The number of unshared valence electrons on the metal is the number
Answer to Problem 18.9P
The
Explanation of Solution
The given complex is shown below.
Figure 1
The formula for calculation of
The oxidation state of metal is calculated by the formula given below.
Since, phosphine is a neutral ligand.and there is no overall charge on the complex. The charge assosciated with chlorine and hydride ligands is
The formula for the calculation of oxidation state is given below.
• n is the number of ligands.
•
•
•
So, the oxidation state of Rh in the complex is calculated below.
The valence electronic configuration of Rh is
Value of
Therefore, the given complex is a
The value of
Want to see more full solutions like this?
Chapter 18 Solutions
Organic Chemistry
- Four different octahedral chromium coordination compounds exist that all have the same oxidation state for chromium and have H2O and Cl as the ligands and counterions. When 1 mole of each of the four compounds is dissolved in water, how many moles of silver chloride will precipitate upon addition of excess AgNO3?arrow_forwardPlatinum(II) forms many complexes, among them those with the following ligands. Give the formula and charge of each complex. (a) two ammonia molecules and one oxalate ion (C2O42-) (b) two ammonia molecules, one thiocyanate ion (SCN-), and one bromide ion (c) one ethylenediamine molecule and two nitrite ionsarrow_forwardGive the number of unpaired electrons in octahedral complexes with strong-field ligands for (a) Rh3+ (b) Mn3+ (c) Ag+ (d) Pt4+ (e) Au3+arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning