Universe: Stars And Galaxies
Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 18, Problem 28Q
To determine

(a)

The radius of the circumsteller accretion disc using ruler.

Expert Solution
Check Mark

Answer to Problem 28Q

The radius of circumstellar accretion disc is 166.6au and The radius of circumstellar accretion disc in km is 248.2×108km.

Explanation of Solution

Calculation:

The radius of circumstellar accretion disc is one-sixth of the measuring ruler which has a total length of 1000au.

The radius of circumstellar accretion disc is calculated as,

R=16×1000au=166.6au

The radius of circumstellar accretion disc in km is calculated as,

R=166.6au=(166.6au× 1.49× 10 8 km 1au)=248.2×108km

Conclusion:

The radius of circumstellar accretion disc is 166.6au and The radius of circumstellar accretion disc in km is 248.2×108km.

To determine

(b)

The orbital period of the particle at outer edge of the disc.

Expert Solution
Check Mark

Answer to Problem 28Q

The orbital period of particle is 7.67×106years.

Explanation of Solution

Given:

Mass of the young star is M=1M.

Formula used:

The expression of orbital period is given by,

T=4π2R3GM

Calculation:

The orbital period of the particle at the edge of disc is calculated as,

T= 4 π 2 R 3 GM= 4 π 2 ( 248.23× 10 8 km× 1m 10 3 km ) 3 ( 6.673 ×  10 11   Nm 2 /kg 2 )( 1 M × 2× 10 30 kg 1 M )=(6723.03× 107hours× 1year 8760hours)=7.67×106years

Conclusion:

The orbital period of particle is 7.67×106years.

To determine

(c)

The length of the jet that extends to the right of the circumstellar accretion disc and time taken by the star to traverse the entire visible range of jet.

Expert Solution
Check Mark

Answer to Problem 28Q

The distance of the jet extends to the right of the disc is 496.617×108km and time taken by the star to traverse the entire visible range of jet is 6.88×104hours.

Explanation of Solution

Given:

Speed of the gas is v=200km/s

Formula used:

The expression of time taken is given by,

T=Dv

Calculation:

The length of the jet which extends at the right side of the circumstellar accretion disc is one third of the total length of about 1000au.

The length of jet is calculated as,

L=13×1000au=(333.3au× 1.49× 10 8 km 1au)=496.617×108km

The time taken by the gas is calculated as,

T=Dv=( 496.617× 10 8 km)( 200 km/s )=(2.48× 108s× 1hour 3600s)=6.88×104hours

Conclusion:

The distance of the jet extends to the right of the disc is 496.617×108km and time taken by the star to traverse the entire visible range of jet is 6.88×104hours.

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