College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Textbook Question
Chapter 2, Problem 4CQ
(a) Can the equations in Table 2.4 be used in a situation where the acceleration varies with time? (b) Can they be used when the acceleration is zero?
Table 2.4 Equations for Motion in a Straight Line Under Constant Acceleration
Equation | Information Given by Equation |
v = v0 + at | velocity as a function of time |
Δx = v0t +
|
Displacement as a function of time |
v2 =
|
Velocity as a function if displacement |
Note: Motion is along the x -axis. At t = 0, | the velocity of the particle is v |
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An object attains a velocity of 5m per second by moving in a straight line with an acceleration which varies uniformly from zero to 2.4m/s^2 in 6 sec. Compute its initial velocity and the change in displacement during the 6 sec interval. Solve by using motions curves and calculus.
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%3D
If we apply the above equations to the case of an object that does not change its
direction of travel as it moves with constant acceleration, we find that the object:
Undergoes a displacement Ax = x- x, . Note that displacement is a positive
quantity if x > x, and a negative quantity if x < x,.
Has average velocity v = (x - x )/t = (v + vo)/2. Note that velocity has the same
sign as displacement.
Travels distance d = |Ax| = |x – x,| . Note that distance is always a positive
quantity.
Has average speed d/t . Note that speed is always a positive quantity.
Has constant acceleration a = (v – vo)/t . Acceleration may be positive or
negative, depending on how velocity changes.
- Xo
For the case of an object that does change its direction of travel as it moves with
constant acceleration, which of the quantities listed above are different?
Question
Chapter 2 Solutions
College Physics
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