(a)
The missing value of fusion reactions.
Answer to Problem 57QAP
The fusion reaction is
Explanation of Solution
Given info:
The given reaction is,
Calculation:
To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
So, 1 neutron will be released from the above equation
Hence, the complete reaction would be
(b)
The missing value of fusion reactions.
Answer to Problem 57QAP
The fusion reaction is
Explanation of Solution
Given info:
The given reaction is,
Calculation:
To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
So, 1 neutron will be released from the above equation
Hence, the complete reaction would be
(c)
The missing value of fusion reactions.
Answer to Problem 57QAP
The fusion reaction is
Explanation of Solution
Given info:
The given reaction is,
Calculation:
To calculate the number of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
So, 1 neutron will be released from the above equation
Hence, the complete reaction would be
(d)
The missing value of fusion reactions.
Answer to Problem 57QAP
The fusion reaction is
Explanation of Solution
Given info:
The given reaction is,
Calculation:
To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
And
So, the atomic number is 2.
Hence, the complete reaction would be
(f)
The missing value of fusion reactions.
Answer to Problem 57QAP
The fusion reaction is
Explanation of Solution
Given info:
The given reaction is,
Calculation:
To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
So, 1 neutron will be released from the above equation
Hence, the complete reaction would be
To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,
So, 1 neutron will be released from the above equation
Hence, the complete reaction would be
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Chapter 27 Solutions
COLLEGE PHYSICS
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- If two nuclei are to fuse in a nuclear reaction, they must be moving fast enough so that the repulsive Coulomb force between them does not prevent them for getting within R1014mof one another. At this distance or nearer, the attractive nuclear force can overcome the Coulomb force, and the nuclei are able to fuse. (a) Find a simple formula that can be used to estimate the minimum kinetic energy the nuclei must have if they are to fuse. To keep the calculation simple, assume the two nuclei are identical and moving toward one another with the same speed v. (b) Use this minimum kinetic energy to estimate the minimum temperature a gas of the nuclei must have before a significant number of them will undergo fusion. Calculate this minimum temperature first for hydrogen and then for helium. (Hint: For fusion to occur, the minimum kinetic energy when the nuclei are far apart must be equal to the Coulomb potential energy when they are a distance R apart.)arrow_forwardThe mass (M) and the radius (r) of a nucleus can be expressed in terms of the mass number, A. (a) Show that the density of a nucleus is independent of A (b) Calculate the density of a gold (Au) nucleus. Compare your answer to that for iron (Fe).arrow_forward(a) Calculate the number of grams of deuterium in an 80.000L swimming pool, given deuterium is 0.0150% of natural hydrogen. (b) Find the energy released in joules if this deuterium is fused via the reaction 2H+2H3He+n. (c) Could the neutrons be used to create more energy? (d) Discuss the amount of this type of energy in a swimming pool as compared to that in, say, a gallon of gasoline, also taking into consideration that water is far more abundant.arrow_forward
- The ceramic glaze on a red-orange “Fiestaware” plate is U2O3and contains 50.0 grams of 238U, but very little 235U. (a) What is the activity of the plate? (b) Calculate the total energy that will be released by the 238U decay, (c) If energy is worth 12.0 cents per kWh , what is the monetary value of the energy emitted? (These brightly- colored ceramic plates went out of production some 30 years ago, but are still available as collectibles.)arrow_forwardThe purpose of this problem is to show in three ways that the binding energy at the election in a hydrogen atom is negligible compared with the masses of the proton and electron. (a) Calculate the mass equivalent in u of the 13.6eV binding energy of an electron in a hydrogen atom, and compete this with the mass of the hydrogen atom obtained from Appendix A. (b) Subtract the mass at the proton given in Table 31.2 from the mass at the hydrogen atom given in Appendix A. You will find the difference is equal to the electron’s mass to three digits, implying the binding energy is small in comparison. (c) Take the ratio of the binding energy at the electron (13.6 eV) to the energy equivalent of the electron's mass (0.511 MeV). (d) Discuss how your answers confirm the stated purpose of this problem.arrow_forward(a) If the average molecular mass of compounds in food is 50.0 g, how many molecules are mere in 1.00 kg at food? (b) How many ion pairs are created in 1.00 kg of food, if it is exposed to 1000 Sv and it takes 32.0 eV to create an ion pair? (c) Find the ratio of ion pairs to molecules. (d) If these ion pairs recombine into a distribution of 2000 new compounds, how many parts per billion is each?arrow_forward
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