EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
6th Edition
ISBN: 9781305687875
Author: Gilbert
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Question
Chapter 3.2, Problem 9E
Interpretation Introduction
Interpretation:Reason for preference of Pasteur filter-tip pipet over regular Pasteur pipet to transfer hot volatile solutions should be determined.
Concept introduction:Pasteur pipet consists of glass tube that is designed in such way that its one end forms tip through which liquid is allowed to enter with help of latex suction bulb. Pasteur filter-tip is modified version of Pasteur pipet; it is useful to transfer liquids with volatile components.
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RESULT:
Q1. Give three criteria for a good recrystallization solvent.
Q2. You want to purify 10 grams of benzoic acid that has been contaminated with 0.2 g
of salicylic acid. You are given the following data:
Solubility in water at 20 °C Solubility at 100 °C
(g/10 ml)
Compound
(g/10 ml)
Benzoic Acid 0.029 0.680
Salicylic Acid
0.680
0.029
0.22
6.67
a) What volume of Boiling water is needed to dissolve the 10 g of benzoic acid?
(show calculations)
b) How much benzoic acid will crystallize after cooling to 20 °C (show calculations)
c) Will any salicylic acid crystals form? Why or why not? (show calculations/ reason for
answer)
d) What is the maximum amount of benzoic acid that could be recovered in the first
crop of this recrystallization? (Show calculations)
e) How can you prove the purity and identity of the purified Benzoic acid?
2. When performing the recrystallization of an impure solid, why is it advised to use the minimal amount of solvent possible?
Group of answer choices
To minimize the amount of pure solid lost due to its solubility.
To minimize the cost of the recrystallization.
To reduce the time needed to filter the pure solid from the solvent after recrystallization.
To minimize the amount of hazardous materials used.
Chapter 3 Solutions
EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
Ch. 3.2 - Prob. 1ECh. 3.2 - Prob. 2ECh. 3.2 - Prob. 3ECh. 3.2 - Prob. 4ECh. 3.2 - Prob. 5ECh. 3.2 - Prob. 6ECh. 3.2 - Prob. 7ECh. 3.2 - Prob. 8ECh. 3.2 - Prob. 9ECh. 3.2 - Prob. 10E
Ch. 3.2 - Prob. 11ECh. 3.2 - Prob. 12ECh. 3.2 - Prob. 13ECh. 3.2 - Prob. 14ECh. 3.2 - Prob. 15ECh. 3.2 - Prob. 16ECh. 3.2 - Prob. 17ECh. 3.2 - Prob. 18ECh. 3.2 - Prob. 19ECh. 3.2 - Prob. 20ECh. 3.2 - Prob. 21ECh. 3.2 - Prob. 22ECh. 3.2 - Prob. 23ECh. 3.2 - Prob. 24ECh. 3.2 - Prob. 25ECh. 3.2 - Prob. 26ECh. 3.2 - Prob. 27ECh. 3.2 - Prob. 28ECh. 3.2 - Prob. 29ECh. 3.2 - Prob. 30ECh. 3.2 - Prob. 31ECh. 3.2 - Prob. 32ECh. 3.2 - Prob. 34ECh. 3.3 - Prob. 1ECh. 3.3 - Prob. 2ECh. 3.3 - Prob. 3ECh. 3.3 - Prob. 4ECh. 3.3 - Prob. 5ECh. 3.3 - Prob. 6ECh. 3.3 - Prob. 7ECh. 3.3 - Prob. 8ECh. 3.3 - Prob. 10ECh. 3.3 - Prob. 11ECh. 3.3 - Prob. 12ECh. 3.3 - Prob. 13ECh. 3.3 - Prob. 14ECh. 3.3 - Prob. 15ECh. 3.3 - Prob. 16ECh. 3.3 - Prob. 17ECh. 3.3 - Prob. 18ECh. 3.3 - Prob. 19ECh. 3.3 - Prob. 21ECh. 3.3 - Prob. 22ECh. 3.3 - Prob. 23ECh. 3.3 - Prob. 24ECh. 3.3 - Prob. 25ECh. 3.3 - Prob. 26E
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