Essential University Physics
4th Edition
ISBN: 9780134988566
Author: Wolfson, Richard
Publisher: Pearson Education,
expand_more
expand_more
format_list_bulleted
Question
Chapter 37.1, Problem 37.1GI
To determine
The magnitude of the energies associated with molecular bonds.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The gap between valence and conduction bands in diamond is 5.47 eV. (a) What is the maximum wavelength of a photon that can excite an electron from the top of the valence band into the conduction band? In what region of the electromagnetic spectrum does this photon lie? (b) Explain why pure diamond is transparent and colorless. (c) Most gem diamonds have a yellow color. Explain how impurities in the diamond can cause this color.
The forbidden energy bandgap of AIP is
2.43 eV. Determine the wavelength (in
nm) of an incident photon that can
interact with a valence electron and
elevate the electron into the conduction
band.
Oλ = 511 nm
Oλ = 419 nm
O λ = 882 nm
λ = 575 nm
A ALAS semiconductor crystal has a lattice constant of a = 0.13 nm, the volume density of As
atoms in this crystal will be:
O 3.641e24 /cm^3
2.048e30 /cm^3
O 1.821e24 /cm^3
O 3.550e16 /cm^3
O 1.593e24 /cm^3
Chapter 37 Solutions
Essential University Physics
Ch. 37.1 - Prob. 37.1GICh. 37.2 - If a scientist uses microwave technology to study...Ch. 37.3 - Prob. 37.3GICh. 37 - Prob. 1FTDCh. 37 - Prob. 2FTDCh. 37 - Prob. 3FTDCh. 37 - Prob. 4FTDCh. 37 - Prob. 5FTDCh. 37 - Prob. 6FTDCh. 37 - Prob. 7FTD
Ch. 37 - Prob. 8FTDCh. 37 - Prob. 9FTDCh. 37 - Prob. 10FTDCh. 37 - Prob. 11ECh. 37 - Prob. 12ECh. 37 - Prob. 13ECh. 37 - Prob. 14ECh. 37 - Prob. 15ECh. 37 - Prob. 16ECh. 37 - Prob. 17ECh. 37 - Prob. 18ECh. 37 - Prob. 19ECh. 37 - Prob. 20ECh. 37 - Prob. 21ECh. 37 - Prob. 22ECh. 37 - Prob. 23ECh. 37 - Prob. 24ECh. 37 - Prob. 25ECh. 37 - Prob. 26ECh. 37 - Prob. 27ECh. 37 - Prob. 28ECh. 37 - Prob. 29ECh. 37 - Prob. 30ECh. 37 - Prob. 31PCh. 37 - Prob. 32PCh. 37 - Prob. 33PCh. 37 - Prob. 34PCh. 37 - Prob. 35PCh. 37 - Prob. 36PCh. 37 - Prob. 37PCh. 37 - Prob. 39PCh. 37 - Prob. 40PCh. 37 - Prob. 41PCh. 37 - Prob. 42PCh. 37 - Prob. 43PCh. 37 - Prob. 44PCh. 37 - Prob. 45PCh. 37 - Prob. 46PCh. 37 - Prob. 47PCh. 37 - Prob. 48PCh. 37 - Prob. 49PCh. 37 - Prob. 50PCh. 37 - Prob. 51PCh. 37 - Prob. 52PCh. 37 - Prob. 53PCh. 37 - Prob. 54PCh. 37 - The critical field in a niobium-titanium...Ch. 37 - The transition from the ground state to the first...Ch. 37 - Prob. 57PCh. 37 - Prob. 58PCh. 37 - Youre troubled that Example 37.1 neglects the mass...Ch. 37 - Prob. 60PCh. 37 - The Madelung constant (Section 37.3) is...Ch. 37 - Prob. 62PCh. 37 - (a) Count the number of electron states N(E) with...Ch. 37 - Prob. 64PCh. 37 - Prob. 65PCh. 37 - Prob. 66PCh. 37 - Prob. 67PPCh. 37 - Prob. 68PPCh. 37 - Prob. 69PPCh. 37 - Prob. 70PP
Knowledge Booster
Similar questions
- An empirical interatomic pair potential for xenon atoms, in units of eV, and nm, and the lattice parameter of Xenon is equal to 0.630 nm. V(r) = 12.6 X 10-7 31.8 X 10-4 712 The calculated interatomic separation (nearest-neighbour) distance is: A. 0.2227 nm. B. 0.3536 nm C. 0.4455 nm D. 1.414 nmarrow_forwardThe potential energy of one of the atoms in the hydrogen molecule is given by U(x) = U₁ (e-2(1-10)/b - 2e-(1-10)/b) where U₁ = 2.36 [eV], zo = 0.037 [nm], and b = 0.034 [nm]. Note that 1 [eV] = 1.6 × 10-¹⁹ [J]. Part (a) Find the energy of the hydrogen molecule in ground state. Part (b) If the measured energy of each atom in the hydrogen molecule is E= -1.15 [eV], where are the classical turning points of the atomic vibration in the hydrogen molecule?arrow_forwardQuestion Consider a germanium crystal. Calculate the number of the quantum states per cm and the energy levels per cm? in the valence band (VB) and the conduction band (CB). The mass density of the germanium crystal is 5.33 g/cm. i) 3.54x10 quantum states cm in each VB and CB i) 1.77x1023 quantum states cm in each VB and CB i) 8.85x102 quantum states cm in each VB and CB iv) 3.54x103 energy levels cm in each VB and CB v) 1.77x10 energy levels cm in each VB and CB vi) 8.85x10 energy levels cm in each VB and CB Please choose ene Cl, v NOi, iv e Cii, iv 4 Oi, v eONone of the abovearrow_forward
- Graph below shows the electron occupancy probability P(E) as a function of energy for Bismuth (mBi = 3.47 × 10-25 kg) at the temperature T = 0 K. What is the number of conduction electrons per unit volume for Bismuth? 1 1 2 3 4 5 6 7 8 E (ev) P(E)arrow_forward1. An electron moving in a conjugated bond framework can be viewed as a particle in a box. An externally applied electric field of strength & interacts with the electron in a fashion described by the perturbation: V(r) = ee (x - 1) Where x is the position of the electron in the box, e is the electron charge, and Lis the length of the box. (a) Compute the first order correction to the energy (b) The first order correction to the wave-function (compute only the contribution to Y made by Y2)arrow_forward(b) Describe the nature and origin of various forces existing between the atoms of a crystal. Explain the formation of a stable bond using the potential energy versus interatomic distance curve. Assume that the potential energy of two particles in the field of each other is given by U(R) = - R where A and B are constants. R9 (i) Show that the particles form a stable compound for R= R. = (9B/A)/8 (R, is equilibrium separation) i) Show that for stable configuration, the energy of attraction is nine times the energy of repulsion. 8A (iii) Show that the potential energy of the system under stable configuration is 9Rearrow_forward
- For a K*- CH ion pair, attractive and repulsive energies EA and ER, respectively, depend on the distance between the ions r, according to 5.8 x 10-6 1.436 EA and ER For these expressions, energies are expressed in electron volts per K*- CH pair, and r is the distance in nanometers. a) If the net energy EN is just the sum of the two expressions above: EN = E, + ER, Find the values of ro and E, ? b) If curves of E, ER, and EN are plotted in given figure, compare the calculated values of ro and E, with that from the graph. 2 am 0.00 010 0.20 0.30 040 0.70 00 1.00 Interatomic Separation, nm Bonding Energy, eVarrow_forwardDetermine the energy required to dissociate a Na Cl molecule into a Na and a Cl atom, given that the electron affinity of Cl is 3.70 eV, the first ionization potential of Na is 5.14 eV, and the separation of Na Cl at equilibrium is 0.236 nm. (а) 6.10 eV (b) 5.57 eV (с) 4.66 eV (d) 3.29 eVarrow_forward1) A Si p-n-p transistor has the following properties at room temperature: Tn = Tp 0.1 us NE 1019 сті Emitter concentration — 10 ст2/s -3 Dn = Dp NB 3D 1016 ст Base concentration Nc 1019 ст -3 = Collector concentration WE 3 µm Emitter width W 1.5 um Metallurgical base width, i.e. the distance between base-emitter junction and base-collector junction A = 10-5 cm² = Cross-sectional area If VCB = 0 V and VEB = 0.6 V, calculate the following: ЕВ a) Neutral base width (WB) b) Base transport factor c) Emitter injection efficiency d) a, ß and y. e) Ic, Ig and Ig.arrow_forward
- The gap between valence and conduction bands in silicon is 1.12 eV. A nickel nucleus in an excited state emits a gamma-ray photon with wavelength 9.31 * 10-4 nm. How many electrons can be excited from the top of the valence band to the bottom of the conduction band by the absorption of this gamma ray?arrow_forwardOne model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is U(r) = Uo[(¹) ¹2 – ( )²] where ro = 0.8 nm and U₁ = 6.1 eV. Note: 1 eV = 1.6 × 10-19 J. Some helpful units: [Force] = eV/nm [Energy] = eV [distance] = nm Equilibrium Distance What is the distance between the atoms when the molecule is in stable equilibrium? Click here for a hint T'eq Hint: Hint: Hint: Hint: Hint: Hint: Force If the distance between the atoms increases from equilibrium by r₁ = 0.35 nm, then what is the force from one atom on the other associated with this potential energy? (Enter your answer as postive if they repel each other, and negative if they attract.) Fr(req+r₁) Hint: Hint: 0.89105934nm Kinetic Energy Hint: The atoms are oscillating back and forth. The maximum separation of the atoms is r₂ = 2 nm. What is the kinetic energy of the atoms when they are separated by the equilibrium distance? Click here for a hint K(req) Hint: Hint: = -1.288eV/nm 3.99eVarrow_forwardThe wavelength of the X-rays that is reflected from an ionic crystal with a lattice structure is 2 nm. The density of the lattice structure is 3.32 g/cm. The lattice constant of the 01 stricture is 6.0 A. The molecular weight is 108 AMU. The lattice structure is, [Hìnt: 1 AMU =1.66 x10" kg] %3Darrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax