Concept explainers
(a)
The unknown tension and masses.
(a)
Answer to Problem 52P
The value of the tension
Explanation of Solution
Given:
The given diagram is shown in Figure 1
Figure 1
Formula used:
For the given diagram, the expression for the horizontal forces is given by,
The equation for the forces resolved in the vertical direction is given by,
The expression for the mass of the block is given by,
Calculation:
The tension
The expression for the value of the tension
The mass of the block is calculated as,
Conclusion:
Therefore, the value of the tension
(b)
The unknown tension and masses.
(b)
Answer to Problem 52P
The value of the tension
Explanation of Solution
Formula used:
The free body diagram for the tension in the rope for figure (b) is shown in Figure 2
Figure 2
For the given diagram, the expression for the horizontal forces is given by,
The equation for the forces resolved in the vertical direction is given by,
The expression for the mass of the block is given by,
Calculation:
The tension
The expression for the value of the tension
The mass of the block is calculated as,
Conclusion:
Therefore, the value of the tension
(c)
The unknown tension and masses.
(c)
Answer to Problem 52P
The value of the tension
Explanation of Solution
Formula used:
The free body diagram for the tension in the rope for figure (c) is shown in Figure 3
Figure 3
For the given diagram, the expression for the horizontal forces is given by,
The equation for the forces resolved in the vertical direction is given by,
The expression for the mass of the block is given by,
The expression for the forces resolved in the horizontal direction is given by,
Calculation:
The tension
The expression for the value of the tension
The mass of the block is calculated as,
Conclusion:
Therefore, the value of the tension
Want to see more full solutions like this?
Chapter 4 Solutions
Physics for Scientists and Engineers
- The Sun rotates about the center of the Milky Way Galaxy (Fig. 6-29) at a distance of about 30,000 light- years from the center (1 ly = 9.5 × 105 m). If it takes about 200 million years to make one rotation, estimate the mass of our Galaxy. Assume that the mass distribu- tion of our Galaxy is concentrated mostly in a central uniform sphere. If all the stars had about the mass of our Sun (2 x 1030 kg), how many stars would there be in our Galaxy? %3D (II) Sun AW (I) 1E bins viool 30,000 ly ovarrow_forwardThe Sun revolves around the center of the Milky Way Galaxy (Fig. 5–49) at a distance of about 30,000 light-years from the center (1 ly = 9.5 × 1015 m). If it takes about 200 mil- lion years to make one revolution, estimate the mass of our Galaxy. Assume that the mass distribution of our Galaxy is concentrated mostly in a central uniform sphere. If all the stars had about the mass of our Sun (2 × 1030 kg), how many stars would there be in our Galaxy? Sun - 30,000 ly- FIGURE 5-49 Edge-on view of our galaxy. Problem 84.arrow_forwardAsteroid Toutatis passed near Earth in 2012 at eighteen times the distance to our Moon. The asteroid's mass is 5.0 x 1013 kg. (Enter the magnitudes.) (a) What was the acceleration (in m/s?) of Earth due to asteroid Toutatis at its closest approach in 2012? ]m/s² (b) What was the acceleration (in m/s?) of Toutatis due to Earth at this point in 2012? m/s?arrow_forward
- My Print Center The mass of a sun is 3.36 x 1030 kg. The radius of the circular orbit of a planet around this sun is 9.7 x 1011 m. Determine the length of one year on this planet. Express the result in earth days where 1 day = 24 x 3600 seconds. Recall: G = 6.67E-11 N m²/kg² In submitting this result, I attest that I have not given nor received any assistance in violation of the UTC Honor Code Pledge. Q Search No new data to save. Last checked at 9:32pm Submit Quizarrow_forwardIf a woman A approaches a man B at a distance C, the gravitational force between them quadruples as C halves exceeds their weight is proportional to the sum A + B is proportional to the distance C squaredarrow_forwardTwo identical particles of each mass M are located on the x-axis at x =+ a and at x - a. Write down an expression for the net gravitational pull F on a unit (a) mass (m-1), placed on the y-axis, due to these two particles as a function of y and a. Discuss the variation of this gravitational pull on the unit mass as it move along the y axis from - to tx. (b) (c) At what point (or points) on the y-axis, is the magnitude of the net gravitational pull F a maximum?arrow_forward
- Question 3 - Particle A of mass 100 kg is located at m. Particle B of mass 380 kg is located at m. The relative position vector pointing 1) from the particle A to particle B TAB= m the gravitational force between 4) In the formula sheet provided which equation can be used to calculate the gravitational force exerted by particle A on particle B. ◆ 5) The magnitude of the gravitational force exerted by particle A on particle B F grav |= N 6) The magnitude of the gravitational force exerted by particle B on particle A || F grav | = | N 7) If the distance between the particles were 4 times larger. The magnitude of the gravitational force between particle A and particle B |F grav |=| Narrow_forwardThe weight of an object above the surface of the earth varies inversely as the square of its distance from the center of the earth. Find the weight of 50 kg man (measure on the surface) at point 100 km above the earth's surface. Assume the radius of the earth to be 6400 km.arrow_forwardangle with 1.00 m sides. Find the magnitude and direction of the resultant gravitational force on each particle. * 12 A spaceship of mass 1.0 × 106 kg is accelerated at a rate of 1.0 m/s² toward a binary star, which consists of two stars of equal mass m, as shown in Fig. 6-16. Find the mass m of each star. m M 1.0 × 106 kg x 1.5 X 1010 m 1.0 × 1010 m Fig. 6-16 I * 13 A particle of mass m is between a 1.00 × 10² kg mass and a 4.00 × 10² kg mass, which are 10.0 m apart. X a €arrow_forward
- Two planets P₁ and P₂ orbit around a star S in circular orbits with speeds v₁ = 43.2 km/s, and v₂ = 60.0 km/s respectively. (a) If the period of the first planet P₁ is 710 years what is the mass, in kg, of the star it orbits around? kg (b) Determine the orbital period, in years, of P₂. yrarrow_forward(a) One of the moons of Jupiter, named Io, has an orbitalradius of 4.22 x 108 m and a period of 1.77 days. Assumingthe orbit is circular, calculate the mass of Jupiter. (b) The largestmoon of Jupiter, named Ganymede, has an orbital radiusof 1.07 x 109 m and a period of 7.16 days. Calculate the massof Jupiter from this data. (c) Are your results to parts (a) and(b) consistent? Explain.arrow_forwardTwo planets P, and P, orbit around a star S in circular orbits with speeds v, = 46.4 km/s, and v, = 57.4 km/s respectivel (a) If the period of the first planet P, is 710 years what is the mass, in kg, of the star it orbits around? kg (b) Determine the orbital period, in years, of P2. yrarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON