Concept explainers
(a)
The atomic number and mass number of the nucleus UX1.
(a)
Answer to Problem 45SP
Solution:
Explanation of Solution
Given data:
By natural radioactivity,
The heavy nucleus UX1 emits a beta particle to form the resultant nucleusUX2.
Formula used:
The conservation of mass is applied in the reaction
Here,
The reaction, when an alpha particle is emitted from a nucleus, is written as
Here,
Explanation:
Consider the given nucleus
Compare the nucleus
Write the standard expression for the emission of an alpha particle from a nucleus as
Here,
The parent nucleus for the reaction is
Apply the conservation of mass by equating the atomic masses on both sides of the chemical equation (1):
Apply the conservation of mass by equating the atomic numbers on both sides of the chemical equation (1):
The value of
Rewrite equation (1) as
Substitute
Conclusion:
The complete equation, after filling the values of
(b)
The atomic number and mass number of the nucleus
(b)
Answer to Problem 45SP
Solution:
Explanation of Solution
Given data:
By natural radioactivity,
The heavy nucleus
Formula used:
The conservation of mass is applied in the reaction
Here,
The emission of a
Here,
Explanation:
Write a standard expression for the emission of abeta particle from the nucleus
Here,
From part (a), the parent nucleus for this reaction is
Apply the conservation of mass by equating the atomic masses on both sides of chemical equation (2):
Apply the conservation of mass by equating the atomic numbers on both sides of chemical equation (2):
The value of
Rewrite equation (2) as
Substitute
Conclusion:
The complete equation, after filling the values of
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Chapter 45 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
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