Chapter 5, Problem 1P

To determine

Summarize the number of neutrons, protons, and electrons for neutral atoms of the following nuclides: ${}^{29}\text{Si,}{}^{44}\text{Sc,}{}^{49}\text{V,}{}^{210}\text{Bi, and}{}^{241}\text{Pu}$.

Explanation of Solution

For nuclide ${}^{29}\text{Si}$:

Find the atomic number (Z):

Refer Periodic Table,

The atomic number (Z) (it gives both the number of protons and electrons for the neutral atom) is 14.

Find the number of neutrons (N):

$\begin{array}{l}A=N+Z\\ N=A-Z\end{array}$

Here, A is total number of nucleons.

Substitute 29 for A and 14 for Z.

$\begin{array}{c}N=29-14\\ =15\end{array}$

Similarly calculate the number of neutrons, protons, and electrons for the remaining neutral atoms.

Summarize the calculated values of number of neutrons, protons, and electrons as in Table (1).

Nuclide	Neutrons (N)	Protons	Electrons
${}^{29}\text{Si}$	15	14	14
${}^{44}\text{Sc}$	23	21	21
${}^{49}\text{V}$	26	23	23
${}^{210}\text{Bi}$	127	83	83
${}^{241}\text{Pu}$	147	94	94