Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN: 9781305079373
Author: William L. Masterton, Cecile N. Hurley
Publisher: Cengage Learning
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Chapter 5, Problem 51QAP
Interpretation Introduction

(a)

Interpretation:

The partial pressure of oxygen needs to be determined.

Concept introduction:

Dalton’s law of partial pressure will be used, which can be calculated by; that, partial pressure of any substance is equal to the mole fraction of that substance multiplied by the total pressure. It can be given as-

pi= ptotal×xi

Interpretation Introduction

(b)

Interpretation:

The number of moles of dry gas needs to be determined.

Concept introduction:

Ideal gas equation which holds the characteristic of ideal gas will be used, which can be given as-

PV=nRT

V=nRTP

n=VPRT

Number of moles of a gas can be calculated by dividing mass of substance by mass of one mole or molar mass.

Number of moles=massmolar mass

Interpretation Introduction

(c)

Interpretation:

The number of moles of wet gas needs to be determined.

Concept introduction:

Ideal gas will be used to calculate the no. of moles of wet gas. It is given as-

PV=nRT

V=nRTP

n=VPRT

Interpretation Introduction

(d)

Interpretation:

The partial pressure of nitrogen in the flask needs to be determined.

Concept introduction:

To calculate the partial pressure mass and molar mass relation and ideal gas law will be used.

Mass and molar mass relation is given as-

Number of moles=massmolar mass

Ideal gas equation for pressure is given as-

P=nRTV

Interpretation Introduction

(e)

Interpretation:

The total pressure in the flask after addition of nitrogen needs to be determined.

Concept introduction:

Ideal gas equation for pressure is given as-

P=nRTV

With the help of ideal gas equation pressure of both gases will be calculated which is added later to calculate total pressure.

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Chapter 5 Solutions

Chemistry: Principles and Reactions

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