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Show that the acceleration of any object down an incline where friction behaves simply (that is, where
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- Find the maximum value of the force F making angle 0 with the normal of the block of mass m such that the block of mass m stays at rest with respect to the block of mass 3m as shown in the Figure. The coefficient of the static friction is u between the blocks while there is no friction between the surface of the ground and the block of mass 3m (Here, tan 0 > 2µ and g is the gravitational acceleration.). F >H 3m H=0arrow_forwardA force P= 696 KN whose line of action passes through points A(3, 2, 1) and B(7, 7, 10). Determine the y-component of force P in kN. Write the numerical value only and in 2 decimal places.arrow_forwardA mug of root beer is sliding across a horizontal table with a constant velocity of 5.0[m/s], and is experiencing a friction force. If the mug has a total mass of 2.60[kg] and μk = 0.250, find the force due to friction. Express your answer in N.arrow_forward
- A block of mass 8.3 kg is initially at rest on a horizontal plane. The coefficients of kinetic and static friction between the plane and the block are respectivelyμc= 0.25 and μe= 0.36. Consider g = 10 m/s2 A horizontal force of magnitude F = 26.3 N is then applied to the block. In this situation, calculate the magnitude of the friction force (in N, to one decimal place).arrow_forwardIn each my sections of MCEG 1101 (PO1 & P02), a student was asked to toss a tennis ball in front of the screen upon which a grid was projected. Based on my slow-motion video recording of the ball tossed in Section P01, the following data was generated (also see uploaded Excel file "tennis ball toss trajectory"). x (grid units) 1 2 3 4 5 6 verti cal position, y (ft) 4 3.5 2.5 2 Based on these data, a parabolic trendline was developed, as shown in the plot below: 1.5 1 0.5 819 0 7 y (grid units) 0 3 5.3 6.5 6.7 5.8 4 0.9 0.5 1 x(ft) 0.55 1.1 1.65 2.2 2.75 3.3 3.85 4.4 Tennis Ball Toss Data from MCEG 1101-P01 y(ft) 0 1.5 1.65 2.915 3.575 3.685 3.19 2.2 0.495 y = -0.9307x² + 4.7619x - 2.3925 R² = 0.999 2.5 2 3.5 horizontal position, x (ft) 3 4 4.5 5arrow_forwardA 1.80x10^4 kg semi-trailer truck drives up a 200 m hill [θ = 30 degrees above horizontal], at a constant speed of 25.0 m/s. The force of friction is 6.00x10^2 N. Write an equation to isolate and solve for P.arrow_forward
- The magnitudes of the three forces are F1 = 1.6kN,F2 = 1.2kN and F3= 1.0kN. Compute their resulatant in the form (a) R=Rxi + Ryj+Rzkl and (b) R=Rλarrow_forwardIf the resultant force is required to act along the positive y axis and have a magnitude of 5 kN . Determine the required magnitude of FB and its direction θ.arrow_forwardQ. 142. A small disc P is placed on an inclined plane forming an angle 0 with the horizontal and imparted an initial velocity vo. Find how the velocity of disc depends on the angle o which its velocity vector makes with the x axis (see figure). The coefficient of friction is u= tan 0 and initially 2 P.arrow_forward
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