Solid Waste Engineering
3rd Edition
ISBN: 9781305635203
Author: Worrell, William A.
Publisher: Cengage Learning,
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Question
Chapter 6, Problem 6.1P
To determine
The sludge and refuse needed to meet the required
Expert Solution & Answer
Answer to Problem 6.1P
The sludge requirement is
The refuse requirement is
Explanation of Solution
Given:
Required
Calculation:
Assume the refuse fraction be
Write the equation to calculate the sludge fraction.
Here, the sludge fraction is
Write the equation to complete the mass balance on carbon.
Calculate the value of
Calculate the sludge fraction.
Substitute
Conclusion:
Thus, the mass balance on carbon is calculated first to find out the answer.
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Students have asked these similar questions
6-1. Assume that refuse has a C/N ratio
of 24:1. If raw sludge with a C/N of
16:1 is to be added to refuse to reach
a required C/N of 20:1, how much of
each-refuse and sludge-is needed?
(Note: Use a wet weight basis.)
3. Circular clarifiers are used to remove solid materials from water. They allow continuous treatment of water and can handle fairly large flows. Solids settle to the bottom of the clarifier and are carried away by a small stream of water (the waste stream). Most of the water exits the tank as treated effluent. Assume a clarifier receives a flow of 0.10 m3/s with a solid concentration of 800 mg/L. If the waste stream consists of 3% of the incoming flow and carries 90% of the incoming solids,
a) what is the solids concentration in the waste stream, and
b) what is the solids concentration in the treated effluent?
List down the materials required in
the installation of a waste pipe in the
figure as shown using (a) 100 mm.
diameter by 3.0 m. long cast iron
pipe and (b) 100 mm. diameter by 6.0
m. long double pipe. The face to face
distance is 22.25m.
Chapter 6 Solutions
Solid Waste Engineering
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