(a)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy is represented by
If the
Answer to Problem 6.38P
The formation of starting material is favored at the given value of
Explanation of Solution
Given
The value of
The given value of
(a) The formation of starting material is favored at the given value of
(b)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the productis favored at the given value of
Explanation of Solution
Given:
The value of
The given value of
The formation of the product is favored at the given value of
(c)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the starting material is favoredat the given values of
Explanation of Solution
Given
The values of
The given values of
The formation of the starting material is favouredat the given values of
(d)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy is represented by
If the
Answer to Problem 6.38P
The formation of the productis favored at the given value of
Explanation of Solution
Given
The value of
The given value of
The formation of the product is favored at the given value of
(e)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the starting materialis favored at the given value of
Explanation of Solution
Given
The value of
The given value of
The formation of the starting material is favored at the given value of
(f)
Interpretation: The starting material or product which is favored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the productis favored at the given value of
Explanation of Solution
Given
The value of
For the spontaneous reaction, the value of
The formation of the product is favored at the given value of
(g)
Interpretation: The starting material or product which isfavored at equilibrium is to be identified.
Concept introduction: The change in Gibbs free energy, enthalpy and entropy is represented by
The change in Gibbs free energy describes the spontaneity of the reaction. The change in enthalpy describes the relative bond strength in the substance, whereas the change in entropy describes the randomness in the system.
Answer to Problem 6.38P
The formation of the starting material is favored at the given value of
Explanation of Solution
Given
The value of
The value of
The formation of the starting material is favored at the given value of
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Chapter 6 Solutions
Organic Chemistry
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- a.Which value corresponds to a negative value of ΔGo: Keq = 10−2 or Keq = 102? b.In a unimolecular reaction with five times as much starting material as product at equilibrium, what is the value of Keq? Is ΔGo positive or negative? c.Which value corresponds to a larger Keq: ΔGo = −8 kJ/mol or ΔGo = 20 kJ/mol?arrow_forwardb. Calculate the value of the equilibrium constant for this reaction.arrow_forwardCalculate ΔSsurr at the indicated temperature for each reaction.a. ΔH °rxn = -385 kJ; 298 K b. ΔH °rxn = -385 kJ; 77 Kc. ΔH °rxn = +114 kJ; 298 K d. ΔH °rxn = +114 kJ; 77 Karrow_forward
- 4. The equation shows an equation at equilibrium. 3H2(g) + N2(g) 2NH3(g) + 76 kJ Which of the following describes what happens if NH; is added to the system? Equilibrium is restored as the reaction shifts toward the products. Equilibrium is restored as the concentration is increased to the products. Equilibrium is restored as the reaction shifts toward the reactants. Equilibrium is restored as more heat energy is released from the system.arrow_forwardAcetaldehyde (CH3CHO) is an important chemical both industrially and biologically. For instance, it is a (somewhat toxic) intermediate in the body's metabolism of ethanol into acetic acid, and thus is possibly implicated in the "hungover" symptoms of someone who has had too much to drink the night before. In aqueous solution, it establishes an equilibrium with a hydrated form, shown below. CH3CHO (aq) + H2O (l) <--> CH3CH(OH)2 (aq) You start with an aqueous sample, already at equilibrium, with the CH3CH(OH)2 (the hydrated form) at a concentration of 2.60 M. You have no information about how much, if any, of the anhydrous form (CH3CHO) is initially in the flask. If you add 2.0 M of CH3CHO to the reaction flask, and as the equilibrium is being restored the amount of CH3CH(OH)2 changes by 1.13 M, what is the final amount of CH3CHO?arrow_forwardFor a given reaction, AG° is large and positive. Which of the following statements is true? All of these are true. The reaction will not take place at all. Products are favored at equilibrium. Reactants are favored at equilibrium. The equilibrium constant, K, is large.arrow_forward
- At 3373 degC and 1 atm total pressure, water is 20.77% dissociated at equilibrium by the way of the reaction 2 H2O(g) ⇋ 2 H2(g) + O2(g). Calculate the a.) K b.) ΔGrxn0 c.) ΔGrxn at this temperature. show your complete solution. please answer thanks.arrow_forwardThis reaction has K = 2.3 * 10-18. Are the reactants or the products favored?arrow_forwardConsider the reaction: A + B. When this reaction reaches equilibrium, which quantity equals zero? The equilibrium constant, Keg The free energy change, AG The concentration of A and B O The enthalpy change, AHarrow_forward
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