Starting Out with Java: From Control Structures through Objects (7th Edition) (What's New in Computer Science)
7th Edition
ISBN: 9780134802213
Author: Tony Gaddis
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Expert Solution & Answer
Chapter 7.1, Problem 7.7CP
Explanation of Solution
Output of the given code:
The given code is developed into a complete
Program:
// Class definition
class Sample
{
// Main class definition
public static void main(String args[]) {
// Array declaration
int[] values = new int[5];
// Loop to get the values
for (int count = 0; count < 5; count++)
/* Increment the count value and store it in variable */
values [count] = count + 1 ;
// Read the values in the variable
for (int count = 0; count < 5; count++)
// Display the values
System...
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
#include <stdio.h>
int main(){ int arr[10]; int i; for (i=0; i<10; i++){ arr[i] = i; } for (i=0; i<10; i++){ printf("arr[%d] = %d\n", i, arr[i]); } return 0;}
Copy the code and modify it as follows:
Add another separate array of 10 integers. The following code parts are to be added (in the same order as specified) after the printing of the values of the first array:(1) Copy the content of the first array to the second array. Add 10 to each of the values of the second array. Make use of a single loop to achieve this part.(2) Print each element of the second array. Make use of another loop for this part
#include <stdio.h>
struct dna
{
int number;
char text;
char stringvalue[30];
};
int main()
{
struct dna dnavalue[5];
int i;
for(i=0; i<4; i++)
{
printf("Sample %d\n",i+1);
printf("Enter Number:\n");
scanf("%d", &dnavalue[i].number);
printf("Enter Text :\n");
scanf("%c",&dnavalue[i].text);
printf("Enter String :\n");
scanf("%s",dnavalue[i].stringvalue);
}
printf("Sample DNA Number Text String\n");
for(i=0; i<4; i++)
{
printf("%d\t\t", i+1);
printf("%d\t\t", dnavalue[i].number);
printf("%c\t\t", dnavalue[i].text);
printf("%s", dnavalue[i].stringvalue);
printf("\n");
}
return 0;
}
Write comments on every line of this program explaining what's happening briefly
#include <stdio.h>#include <stdlib.h>
int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr.
void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;}
int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…
Chapter 7 Solutions
Starting Out with Java: From Control Structures through Objects (7th Edition) (What's New in Computer Science)
Ch. 7.1 - Write statements that create the following arrays:...Ch. 7.1 - Whats wrong with the following array declarations?...Ch. 7.1 - Prob. 7.3CPCh. 7.1 - Prob. 7.4CPCh. 7.1 - Prob. 7.5CPCh. 7.1 - Prob. 7.6CPCh. 7.1 - Prob. 7.7CPCh. 7.1 - Prob. 7.8CPCh. 7.2 - Prob. 7.9CPCh. 7.2 - Prob. 7.10CP
Ch. 7.2 - A program has the following declaration: double[]...Ch. 7.2 - Look at the following statements: int[] a = { 1,...Ch. 7.3 - Prob. 7.13CPCh. 7.3 - Write a method named zero, which accepts an int...Ch. 7.6 - Prob. 7.15CPCh. 7.7 - Recall that we discussed a Rectangle class in...Ch. 7.10 - Prob. 7.17CPCh. 7.11 - What value in an array does the selection sort...Ch. 7.11 - How many times will the selection sort swap the...Ch. 7.11 - Prob. 7.20CPCh. 7.11 - Prob. 7.21CPCh. 7.11 - If a sequential search is performed on an array,...Ch. 7.13 - What import statement must you include in your...Ch. 7.13 - Write a statement that creates an ArrayList object...Ch. 7.13 - Write a statement that creates an ArrayList object...Ch. 7.13 - Prob. 7.26CPCh. 7.13 - Prob. 7.27CPCh. 7.13 - Prob. 7.28CPCh. 7.13 - Prob. 7.29CPCh. 7.13 - Prob. 7.30CPCh. 7.13 - Prob. 7.31CPCh. 7 - In an array declaration, this indicates the number...Ch. 7 - Each element of an array is accessed by a number...Ch. 7 - The first subscript in an array is always. a. 1 b....Ch. 7 - The last subscript in an array is always. a. 100...Ch. 7 - Array bounds checking happens. a. when the program...Ch. 7 - This array field holds the number of elements that...Ch. 7 - Prob. 7MCCh. 7 - This search algorithm repeatedly divides the...Ch. 7 - Prob. 9MCCh. 7 - When initializing a two-dimensional array, you...Ch. 7 - Prob. 11MCCh. 7 - To delete an item from an ArrayList object, you...Ch. 7 - To determine the number of items stored in an...Ch. 7 - True or False: java does not allow a statement to...Ch. 7 - True or False: An arrays sitze declarator can be a...Ch. 7 - Prob. 16TFCh. 7 - True or False: The subscript of the last element...Ch. 7 - Prob. 18TFCh. 7 - True or False: The Java compiler does not display...Ch. 7 - Prob. 20TFCh. 7 - True or False: The first size declarator in the...Ch. 7 - Prob. 22TFCh. 7 - Prob. 23TFCh. 7 - int[] collection = new int[-20];Ch. 7 - Prob. 2FTECh. 7 - Prob. 3FTECh. 7 - Prob. 4FTECh. 7 - Prob. 5FTECh. 7 - The variable names references an integer array...Ch. 7 - The variables numberArray1 and numberArray2...Ch. 7 - Prob. 3AWCh. 7 - In a program you need to store the populations of...Ch. 7 - In a program you need to store the identification...Ch. 7 - Prob. 6AWCh. 7 - Prob. 7AWCh. 7 - Prob. 8AWCh. 7 - Prob. 9AWCh. 7 - Prob. 10AWCh. 7 - Prob. 11AWCh. 7 - Prob. 1SACh. 7 - Prob. 2SACh. 7 - Prob. 3SACh. 7 - Prob. 4SACh. 7 - Prob. 5SACh. 7 - Prob. 6SACh. 7 - Prob. 7SACh. 7 - Prob. 8SACh. 7 - Prob. 9SACh. 7 - Rainfall Class Write a RainFall class that stores...Ch. 7 - Payroll Class Write a Payroll class that uses the...Ch. 7 - Charge Account Validation Create a class with a...Ch. 7 - Charge Account Modification Modify the charge...Ch. 7 - Prob. 5PCCh. 7 - Drivers License Exam The local Drivers License...Ch. 7 - Magic 8 Ball Write a program that simulates a...Ch. 7 - Grade Book A teacher has five students who have...Ch. 7 - Grade Book Modification Modify the grade book...Ch. 7 - Average Steps Taken A Personal Fitness Tracker is...Ch. 7 - Array Operations Write a program with an array...Ch. 7 - Prob. 12PCCh. 7 - Sorted List of 1994 Gas Prices Note: This...Ch. 7 - Name Search If you have downloaded this books...Ch. 7 - Population Data If you have downloaded this books...Ch. 7 - World Series Champions If you have downloaded this...Ch. 7 - 2D Array Operations Write a program that creates a...Ch. 7 - Prob. 18PCCh. 7 - Trivia Game In this programming challenge, you...Ch. 7 - Prob. 20PC
Knowledge Booster
Similar questions
- #include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…arrow_forward#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…arrow_forward#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…arrow_forward
- int* p: int a[3]{1, 2, 3}; p = a; What is the value of *(p+2)?arrow_forward#include <stdio.h>#include <string.h> int findRepeat(char* s){int p , i , j; p = -1; for (i = 0 ; i < strlen(s) ; i++){for (j = i + 1; j < strlen(s); j++){if (s[i] == s[j]){p = i;break;}}if (p != -1)break;}return p;} int main(){char str[] = "Hello World";int pos = findRepeat(str);if (pos == -1)printf("Not found");elseprintf("%c", str[pos]);return 0;}can you please explain this code for mearrow_forwardint X[10]={2,0,6,11,4,5,9,11,-2,-1); From the code above, what is the value of X[8] ?arrow_forward
- int a[ 10] = {1,5,3,8,4,2,6,9,7}; int *p; p = &a[2]; p[0] = 10; p[1] = 15; What are the values of a? Select one: O a. {10,15,3,8,4,2,6,9,7} O b. {1,15,10,8,4,2,6,9,7} O c. {1,5,10,15,4,2,6,9,7} O d. {1,10,15,8,4,2,6,9,7}arrow_forward#include using namespace std; const int y = 1; int main () { int static y = 2; int i = 3, j = 4, m = 5, n = 6; %3D int a = [] (int x, int i = 1) { return x * i; } (y, 3) ; %3D int b = [=] (int x) { return [=] (int b) { return b + j; } (x) % 7; } (a); int c = [=] (int x) mutable ->int { m = 6; return [6] (int j) mutable { y = a * b; return y / j; } (x) -m; } (b) ; cout << a << endl; cout << b << endl; cout << c << endl; cout << m << endl; cout << y < endl; return 0; This program outputs 5 lines. What are they? Please explain your work and your answer.arrow_forward#include using namespace std; int find(int arr[], int value, int left, int right) { int midpt = (left+right)/2; if (left > right) return -1; if ( arr[midpt] return midpt; else if (arr[midpt] < value) == value) return else return find(arr,value, left,midpt-1); } void main(void) { int arr[] ={4,5,6,9,11}; cout<arrow_forwardint a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *parrow_forward#include #include #include int main() { int i, j; printf("Columns | JIn"); for (i = 1; i< 4; ++i) { printf("Outer %6d\n", i); for (j = 0; j< i; ++j) { printf(" Inner%10d\n", j); } } /* heading of outer for loop */ /* heading of inner loop */ %3D return (0); } Create a new code modifying it to use "while loop" instead of the "for loop"arrow_forwardinclude<stdio.h> #include<stdlib.h> int main() { int N; scanf("%d", &N); int input[N], ind, rem; for(ind=0;ind<N;ind++) scanf("%d", &input[ind]); // 8 7 6 4 int two_digits[22], two_digits_ind; unsignedlonglongint res = 0; two_digits[0] = 1; for(two_digits_ind=1;two_digits_ind<22;two_digits_ind++) two_digits[two_digits_ind] = ((two_digits[two_digits_ind-1])*2)%100; for(ind=0;ind<N;ind++) { if(input[ind]>21) { rem = input[ind] % 22; rem += 2; } else rem = input[ind]; res = res + two_digits[rem]; } printf("%llu", res%.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
- Database System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill EducationStarting Out with Python (4th Edition)Computer ScienceISBN:9780134444321Author:Tony GaddisPublisher:PEARSONDigital Fundamentals (11th Edition)Computer ScienceISBN:9780132737968Author:Thomas L. FloydPublisher:PEARSON
- C How to Program (8th Edition)Computer ScienceISBN:9780133976892Author:Paul J. Deitel, Harvey DeitelPublisher:PEARSONDatabase Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781337627900Author:Carlos Coronel, Steven MorrisPublisher:Cengage LearningProgrammable Logic ControllersComputer ScienceISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
Database System Concepts
Computer Science
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:McGraw-Hill Education
Starting Out with Python (4th Edition)
Computer Science
ISBN:9780134444321
Author:Tony Gaddis
Publisher:PEARSON
Digital Fundamentals (11th Edition)
Computer Science
ISBN:9780132737968
Author:Thomas L. Floyd
Publisher:PEARSON
C How to Program (8th Edition)
Computer Science
ISBN:9780133976892
Author:Paul J. Deitel, Harvey Deitel
Publisher:PEARSON
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781337627900
Author:Carlos Coronel, Steven Morris
Publisher:Cengage Learning
Programmable Logic Controllers
Computer Science
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education