Human Heredity: Principles and Issues (MindTap Course List)
Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 9, Problem 18QP

The following is a portion of a protein: met-trp-tyr-arg-gly-pro-thr-Various mutant forms of this protein have been recovered. Using the normal and mutant sequences, determine the DNA and mRNA sequences that code for this portion of the protein, and explain each of the mutations.

  1. a. met-trp-
  2. b. met-cys-ile-val-val-leu-gln-
  3. c. met-trp-tyr-arg-ser-pro-thr-
  4. d. met-trp-tyr-arg-gly-ala-val-ile-ser-pro-thr-

a.

Expert Solution
Check Mark
Summary Introduction

To determine: The DNA and mRNA sequences that code for this normal protein “met-trp-tyr-arg-gly-pro-thr” and explain the mutation in “met-trp”.

Introduction: The proteins are coded from triplet codons. There are 64 triplet codons, which code for 20 amino acids in which initiation and stop codons are also included. The initiation codons allow the mRNA to transcribe the DNA template while stop codons restrict the translation.

Explanation of Solution

The possible triplet codons for the normal protein “met-trp-tyr-arg-gly-pro-thr” are as follows:

MetTrpTyrArgGlyProThr
AUGUGGUAUAGAGGUCCUACU
  UACAGGGGCCCCACC
    GGACCAACA
    GGGCCGACG

These are the possible triplet codons for “met-trp-tyr-arg-gly-pro-thr” protein. Any mutation in the above sequences may lead to mutation.

The first mutation occurred and formed “met-trp” protein. Possibly, the mutation occurred at ‘tyr’, which resulted in the termination. The termination is caused by a stop codon. The possible triplet codons after mutation in “met-trp” are :

MetTrpStop codons
AUGUGGUAA
  UAG

In the original sequence, tyrosine is present. However in mutated sequences,  stop codons are formed, which shorten the polypeptide to Trp.

b.

Expert Solution
Check Mark
Summary Introduction

To determine: The DNA and mRNA sequences that code for this normal protein “met-trp-tyr-arg-gly-pro-thr” and explain the mutation in “met-cys-ile-val-val-leu-gln”.

Introduction: The proteins are coded from triplet codons. There are 64 triplet codons which code for 20 amino acids in which initiation and stop codons are also included. The initiation codon allows the mRNA to transcribe the DNA template; whereas, stop codons restrict the translation.

Explanation of Solution

The possible triplet codons for the normal protein “met-trp-tyr-arg-gly-pro-thr” are as follows:

MetTrpTyrArgGlyProThr
AUGUGGUAUAGAGGUCCUACU
  UACAGGGGCCCCACC
    GGACCAACA
    GGGCCGACG

These are the possible triplet codons for “met-trp-tyr-arg-gly-pro-thr” protein. Any mutation in the above sequences may lead to mutation.

The second mutation occurred and formed “met-cys-ile-val-val-leu-gln” protein. Possibly the point mutation occurred which caused changes in the reading frame. The triplet codons of the mutated protein “met-cys-ile-val-val-leu-gln” are :

MetCysIleValValLeuGln
AUGUGUAUAGUGGUCCUAACU
   GUG  ACC
      ACA
      ACG

The highlighted codons are mutated. The single place deletion or insertion may arise this type of situation where the complete sequence is changed.

c.

Expert Solution
Check Mark
Summary Introduction

To determine: The DNA and mRNA sequences that code for this normal protein “met-trp-tyr-arg-gly-pro-thr” and explain the mutation in “met-trp-tyr-arg-ser-pro-thr”.

Introduction: The proteins are coded from triplet codons. There are 64 triplet codons which code for 20 amino acids in which initiation and stop codons are also included. The initiation codon allows the mRNA to transcribe the DNA template; whereas, the stop codons restrict the translation.

Explanation of Solution

The possible triplet codons for the normal protein “met-trp-tyr-arg-gly-pro-thr” are as follows:

MetTrpTyrArgGlyProThr
AUGUGGUAUAGAGGUCCUACU
  UACAGGGGCCCCACC
    GGACCAACA
    GGGCCGACG

These are the possible triplet codons for “met-trp-tyr-arg-gly-pro-thr” protein. Any mutation in the above sequences may lead to mutation.

The third mutation occurred and formed “met-trp-tyr-arg-ser-pro-thr” protein. Possibly the frameshift mutation occurred, which caused changes in the reading frame. The triplet codons of the mutated protein “met-trp-tyr-arg-ser-pro-thr” are :

MetTrpTyrArgSerProThr
AUGUGGUAUAGAAGUCCUACU
  UACAGG CCCACC
     CCAACA
     CCGACG

Here, the only codon for glycine is completely changed. The single frame is inserted and deleted from the same place.

d.

Expert Solution
Check Mark
Summary Introduction

To determine: The DNA and mRNA sequences that code for this normal protein “met-trp-tyr-arg-gly-pro-thr” and explain the mutation in “met-trp-tyr-arg-gly-ala-val-ile-ser-pro-thr-”.

Introduction: The proteins are coded from triplet codons. There are 64 triplet codons, which code for 20 amino acids in which initiation and stop codons are also included. The initiation codon allows the mRNA to transcribe the DNA template; whereas, the stop codons restrict the translation.

Explanation of Solution

The possible triplet codons for the normal protein “met-trp-tyr-arg-gly-pro-thr” are as follows:

MetTrpTyrArgGlyProThr
AUGUGGUAUAGAGGUCCUACU
  UACAGGGGCCCCACC
    GGACCAACA
    GGGCCGACG

These are the possible triplet codons for “met-trp-tyr-arg-gly-pro-thr” protein. Any mutation in the above sequences may lead to mutation.

The second mutation occurred and formed “met-trp-tyr-arg-gly-ala-val-ile-ser-pro-thr-” this protein. This is a type of mutation where the reading frame is shifted because this protein is relatively larger than the normal protein.

Hence, frame insertion is a possible way due to which the protein is completely changed.

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Students have asked these similar questions
What potential polypeptides can be produced from the following mRNA sequence?  There are more than one answer..  5’ ...GGAGCUCGUUGUAUU... 3’ a. ser-ser-leu-tyr b. leu-cys-cys-ser-arg c. gly-ala-ser-trp-ile d. gly-ala-arg-cys-ile e. glu-leu-val-val f. You can't translate without a start codon.    I know (d) is one of the answer but I'm stuck on how to find the rest. Please help.
Compare the two DNA sequences shown below and consider the single nucleotide mutation made in the lower DNA sequence (shown in bold font). This is an example of a mutation. DNA: ATG CGC ТСС САТ стт ААС АAА GAG GTT GG C TAT TT Protein: Met-Arg-Ser-His-Leu-Asn-Lys-Glu-Ala-Gly-Tyr-Phe DNA: АTG CGC ТСС САТ стТ ААС АAG GAG GTT GGC ТАТ ТТT Protein: Met-Arg-Ser-His-Leu-Asn-Lys-Glu-Ala-Gly-Tyr-Phe missense nonsense frame-shift silent antisense
A. What amino acid sequence is encoded by the codon sequence AUAAUGGUAACGGUU? B. Suppose the codon sequence AGACACUCUAUUAAA has a single base pair mutation to AGACACUCUUUUAAA. If the old protein sequence was Arg-His-Ser-Ile-Lys, what will be the new sequence encoded by the mutant gene?

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Human Heredity: Principles and Issues (MindTap Course List)

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