Concept explainers
(a)
Interpretation:
The statement that one mole of
(a)
Answer to Problem 3RQ
The statement is correct.
Explanation of Solution
The given balanced equation is,
In the mole ratio, the coefficients of the balanced equation are used. Therefore the mole ratio is
The number of moles of phosphine can be calculated as,
The statement that one mole of
(b)
Interpretation:
The statement that one gram of
(b)
Answer to Problem 3RQ
The statement is incorrect.
Explanation of Solution
Given,
The mass of
The mass of phosphine is
The molecular weight of phosphine is
The molecular weight of
The given balanced equation is,
In the mole ratio, the coefficients of the balanced equation are used. Therefore the mole ratio is
The number of grams of phosphine can be calculated as,
The statement one gram of
(c)
Interpretation:
The statement that three moles of
(c)
Answer to Problem 3RQ
The statement is correct.
Explanation of Solution
The given balanced equation is,
In the mole ratio, the coefficients of the balanced equation are used. Therefore the mole ratio is
The statement that three moles of
(d)
Interpretation:
The statement that the mole ratio between phosphine and calcium phosphide is
(d)
Answer to Problem 3RQ
The statement is correct.
Explanation of Solution
The given balanced equation is,
In the mole ratio, the coefficients of the balanced equation are used. Therefore the mole ratio is
The statement is correct statement.
(e)
Interpretation:
The statement
(e)
Answer to Problem 3RQ
The statement is incorrect.
Explanation of Solution
The given balanced equation is,
In the mole ratio, the coefficients of the balanced equation are used. Therefore the mole ratio is
The number of moles of phosphine produced from water can be calculated as,
(f)
Interpretation:
The statement
(f)
Answer to Problem 3RQ
The statement is correct.
Explanation of Solution
The given balanced equation is,
In the mole ratio, the coefficients of the balanced equation are used. Therefore the mole ratio is
The number of moles of
(g)
Interpretation:
The possibility of limiting agent being
Concept Introduction:
The limiting reactant of the reaction is the reactant that is completely used during the reaction. Using the mole ratio and starting amounts of the reactants limiting reactant can be determined.
Example:
Consider a reaction starts with
(g)
Answer to Problem 3RQ
The statement is incorrect.
Explanation of Solution
Given,
The mass of
The mass of
The molecular weight of phosphine is
The molecular weight of
The molecular weight of
The given balanced equation is,
The amount of water needed to react with
The amount of water present is less than needed to react with
(h)
Interpretation:
The theoretical yield of
(h)
Answer to Problem 3RQ
The statement is incorrect.
Explanation of Solution
Given,
The mass of
The mass of
The molecular weight of phosphine is
The molecular weight of
The molecular weight of
The given balanced equation is,
The theoretical yield of phosphine from
The theoretical yield of phosphine from
The theoretical yield of phosphine is
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Chapter 9 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
- Phosphorus occurs naturally in the form of fluorapatite, CaF2 3Ca3(PO4)2. The dot indicates 1 part CaF2 to 3 parts Ca3(PO4)2. This mineral is reacted with an aqueous solution of H2SO4 in the preparation of a fertilizer. The products are phosphoric acid, hydrogen fluoride, and gypsum, CaSO4 2H2O. Write the balanced equation describing this process.arrow_forward4.48 Elemental phosphorous is used in the semiconductor industry. It can be obtained from an ore called fluoroapatite via reaction with SiO2 and C: 4Ca5( PO4)3F+18SiO2+30C3P4+30CO+18CaSiO3+2CaF2 Suppose a particular semiconductor production plant requires 1500 kg of P4. If the recovery of P4 from this reaction is 73% efficient, what mass of fluoroapatite is needed?arrow_forwardPhosphate buffers are important in regulating the pH of intracellular fluids. If the concentration ratio of H2PO4/HPO42 in a sample of intracellular fluid is 1.1: 1, what is the pH of this sample of intracellular fluid? H2PO4(aq)HPO42(aq)+H+(aq)Ka=6.2108arrow_forward
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