(a)
To determine: The structure of the
Interpretation: The structure of the alkyne that undergoes oxidative cleavage to give adipic acid and two equivalents of acetic acid is to be proposed.
Concept introduction: An oxidative cleavage results in formation of
Ozonolysis is the process, in which triple bonds of alkyne molecules cleave with ozone.
(b)
To determine: The structure of the alkyne that undergoes oxidative cleavage to give a triacid and propionic acid.
Interpretation: The structure of the alkyne that undergoes oxidative cleavage to give a triacid and propionic acid is to be shown.
Concept introduction: The oxidative cleavage results in the formation of
Ozonolysis is the process, in which triple bonds of alkyne molecules cleave with ozone.
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Chapter 9 Solutions
Organic Chemistry (9th Edition)
- 问题5 5分 Which of the following describe the major product(s) of this reduction reaction (you may assume excess LIAIH4 is used)? 1. LİAIH4 2. H20 rning primary alcohol secondary alcohol tertiary alcohol aldehyde ketone esterarrow_forwardAlkynes are prepared by double two halogens, so that they can both be removed. Complete the reaction sequence. Br₂ reactions. If starting with an alkene, first add 2 KOH (or 2 NaNH2)arrow_forwardIII An alkyne reagent is shown in the following figure, write the products of the following reactions (if the reaction occurs in more than one step, write, and identify the species that are formed.) H, 2B12 CH3CH2CH2C CH KMNO, 1HC1 Lindlar Catalyst H,O, H,SO, HgSO4 H, Pd/C Catalystarrow_forward
- Write the names and draw the structures of the product/s formed from the reaction of 3-methylpent-2-ene with: 1. HBr 2. Cl2 3. H2O in the presence of H2SO4 4. Ethanol in the presence of H2SO4 5. Br2, H2O 6. [1] 9-BBN; [2] H2O2, OH-arrow_forwardIt is a type of organic reaction in which parts from two molecules exchange. * Elimination Substitution Addition Rearrangement In the reaction given below, what type of addition reaction is used? * H H H H H-C-c=C HBr н-с — с — С —с —н + H H H Br H O Hydrogenation O Hydrohalogenation O Halogenation O Dehalogenation H-O-Iarrow_forwardFree radical halogenation is used to replace one or more hydrogens on an alkane with one or more halogens (either chlorine or bromine). It is a substitution reaction. A student performs a free radical bromination on 3-methyl-pentane (5.88 g) to create the desired product of 3-bromo-3-methyl-pentane. The product mix, which hopefully contains almost all 3-bromo-3-methyl-pentane, is cleaned up by passing it through a gas chromoatograph, which separates out the 3-bromo-3-methyl-pentane from any undesired products made during the reaction (undesired products are created frequently in free radical halogenation). The initial product mix weighed 9.45 g; the purified 3-bromo-3-methyl-pentane weighed 7.21 g. What is the student's percent recovery?arrow_forward
- Draw the skeletal structure of the starting material needed for the reaction below (if a leaving group is needed, use Br). 1. NaCN -NH₂ 2. H₂ Pt organic reactantarrow_forwardHydroboration of Alkenes vs. Alkynes. Addition of an alkylboranes to a carbon- carbon double bond ("hydroboration") followed by oxidation is a common way to alcohols, for example, addition of dimethylborane to 2,3-dimethyl-2-butene yields 2,3-dimethyl-2-butanol. Me₂BH + Me₂C=CMe₂- →→ Me₂CH-CMe₂OH The reaction is more general as borane also adds to carbon-carbon triple bonds. obtain structures and energies for reactants and transition states for addition of dimethylborane (Me₂BH) to both ethylene and acetylene. Which reaction has the lower activation energy? Offer an explanation for your result.arrow_forwardAlcohols can be converted to alkyl bromides using PBr3, which causes a complete inversion of stereochemistry. OH 10 PBr 3 Draw the stepwise mechanism for bromination of an alcohol. Be sure to include non-zero formal charges and lone pairs as necessary. : OH Br of 0 Br. Br Br Add/Remove step X Click and drag to st= drawing a structurarrow_forward
- A. Complete and balance the following combustion reactions. Assume that each hydrocarbon is converted completely to carbon dioxide and water. 1. Propane + O2 → 2. Cyclohexane + 02→ 3.2-Methylpentane + O2 → B. Following are structural formulas and heats of combustion of acetaldehyde and ethylene oxide. Which of these compounds is the more stable? Explain. CH-CH H,C-CH2 Acetaldehyde -1164 kJ (-278.8 kcal)/mol Ethylene oxide -1264 kJ (-302.1 kcal)/molarrow_forward4:30 PM Wed Apr 27 * 74% O O Q E HW 12 Home Insert Draw Layout Review View I| Select Objects Draw with Touch 40. There are five compounds with the formula C6H14 (one of them is linear and the others are branched). Draw structural formulas for any two of those branched isomers. See Example 6.3 on page 152. H3C CH3 CH3 44. Name the following alkanes. CH¿CH3 CH,CH3 CH3 CH;CH2CHCH2CH¿CH3 CH;CHCHCH,CH;CH3 CH;CHCHCH3 CH3 CH3 a C 3-CHhylheypare ethyl-2 methyllnexano а. 7+3 dimethibulane С. 46. Name the following alkenes. CH2=CHCH,CHCH;CHCH3 CH2CH3 CH2=CHCH2CH3 CH3 CH3 CH2=CHCH2CHCH3 a b C |burene а. b. C. 48. Name the following alkynes. CH,CH3 GH=CH CH3 C=CCH2CH3 CH;C=CCHCH,CH3 a b Carrow_forwardOE 2 O NH Draw the structure of all organic products formed in the following reaction. <-5 1. KOH 2. (CH₂)₂CHCH₂Cl 3. OH, H₂Oarrow_forward
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