9- Compute the total elongation caused by an axial load of 100 kN applied to a flat bar 20 mm thick , tapering from a width of 120 mm to 40 mm in a length of 10 m as shown in fig. Assume E=200 Gpa thickness=20 mm 120 mm 40 mm P=100 kN P=100 kN 10 m
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- A tie-down on the deck of a sailboat consists of a bent bar boiled at both ends, as shown in the figure. The diameter dBof the bar is 1/4 in., the diameter D Wof the washers is 7/8 in., and the thickness is of the fiberglass deck is 3/8 in. If the allowable shear stress in the fiberglass is 300 psi, and the allowable bearing pressure between the washer and the fiberglass is 550 psi, what is the allowable load P allowon the tie-down?A steel rod is stretched between two walls. At 20C, the tensile force in the rod is 5000N. If the stress is not to exceed 130MPa at -20C, find the minimum allowable diameter of the rod. Use a=11.17x10^-6C and E=200GPa. -Draw and label the diagram correctly, No diagram in the solution will be marked wrong. -Shortcut solution will be marked wrong. -Show complete solution and explanationThe one end of a hollow square bar whose side is 10.42 in with 1.42 in thickness is under a tensile stress 102,500 psi and the other end is connected with a U bracket using a pin. Find the minimum diameter of pin is used. Take oall = 243 ksi for pin material.
- The one end of a hollow square bar whose side is 10.17 in with 1.17 in thickness is under a tensile stress 102,500 psi and the other end is connected with a U bracket using a double-pin system. Find the minimum diameter of pin is used according to shear strength. Take the factor of safety as 1.5 and σ allowable= 243 ksi for pin material.The one end of a hollow square tube whose side is 10.47 in with 1.47 in thickness is under a tensile stress 102,500 psi and the other end is connected with a U bracket using (a double-pin) system. Find the minimum diameter of pin is used according to shear strength. Take the factor of safety as 1.5 and σ(allowable) = 243 ksi for pin material.Question Two A steel flat of thickness 10 mm tapers uniformly from 60 mm at one end to 40 mm at other end in a length of 600 mm. If the bar is subjected to a load of 80 kN, find its extension. Take E = 2 x 10 MPa. What is the percentage error if average area is used for calculating extension?
- 1. A solid square rod is cantilevered at one end. The rod is 0.8 m long and supports a completely reversing transverse load at the other end of 50 kN. The material is AISI 1060 hot-rolled steel (?? =370 MPa,?? =680 MPa ). Use a design factor of 2 and determine the dimensions of the square cross section for the following cases. Neglect any stress concentration. a. The rod must support this load for 100 cycles. b. The rod must support this load for 104 cycles. c. The rod must have infinite life.If the allowable tensile stress for the bar is (ot)allow = 20 ksi, and the allowable shear stress for the pin is Tallow = 11.6 ksi. Assume the hole in the bar has the same diameter d as the pin. Take t = 1/4 in. and w = 2 in. (Figure 1) Figure w/2 [w/2 P 1 of 1 > Part A Determine the diameter of the pin so that the load P will be a maximum. Express your answer to three significant figures and include appropriate units. d= Submit Part B P = Submit μA Value Request Answer What is this maximum value for P? Express your answer to three significant figures and include appropriate units. li μA Provide Feedback Value Units Request Answer ? Units ?A steel rod is stretched between two walls. At 20C, the tensile force in the rod is 5000N. If the stress is not to exceed 130MPa at -20C, find the minimum allowable diameter of the rod. Use a=11.17x10^-6C and E=200GPa. -Draw and label the diagram correctly, No diagram in the solution will be marked wrong. -Shortcut solution will be marked wrong.- Direction of the assumption of the equilibrium equation must be shown, no direction will be marked wrong. -Show complete solution and explanation
- 80 mm 20 mm 7 mm M M Click to see additional instructions Calculate the minimum Safety Factor if the radius r = 5mm and M= 17.5 Nm. The material is mild steel with Sy = 220 MPa. Fill in the answers below and make sure of the unit. 4. The second moment of area: I= mm4. 5. Maximum normal stress in beam: o = MPa. 6. The safety factor: SF =The one end of a hollow square bar whose side is 10.47 in with 1.47 in thickness is under a tensile stress 102,500 psi and the other end is connected with a U bracket using a double-pin system. Find the minimum diameter of pin is used according to shear strength. Take the factor of safety as 1.5 and σallowable=243 ksi for pin material.A metal bar is made out of A-36 steel and has a diameter d = 23mm with the end at A fixed to the wall. There is are balanced axial loads at B of P₁ = 30 kN and a point load at C 35 kN. The distance from A to B is L₁ of P2 570 mm 390 mm. Calculate the = and the distance from B to C is L2 displacement of point C relative to point A. A L₁ ↑ d B L2 - P₁₁ Р1 С The displacement at C is 8 = -0.00306 d - cc 080 BY NO SA 2021 Cathy Zupke P₂ x mm