A mutant is found that has the following protein sequence in that part of the protein: Tyr Lys Gly Arg Thr Cys Ser Premature Stop. What is the likely mutation? Obetween A12 and C13 insert T. between C13 and C14 insert T. OA15 -> del. C13 and C14. -> del. O G8 -> T. G20 -> A. T21 -> del.
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- A Section of a GeneAAG ATA CAG GCT CGG TAA For the DNA sequence shown above, identify the following: mRNA codons tRNA anticodons amino acids The section of a gene shown above (AAG ATA CAG GCT CGG TAA) is called the Answer (template or non-template) strand. It is also known as the Answer (sense or antisense) strand. The amino acids are determined from the Answer (DNA or mRNA or tRNA) strandhe Sequence below comes from the alpha-2 globin of the human hemoglobin gene cluster found in chromosome 16. The globin region of the hemoglobin protein itself consists of 2 alpha chains and 2 beta chains. 1 actcttctgg tccccacaga ctcagagaga acccaccatg gtgctgtctc ctgccgacaa 61 gaccaacgtc aaggccgcct ggggtaaggt cggcgcgcac gctggcgagt atggtgcgga 121 ggccctggag aggatgttcc tgtccttccc caccaccaag acctacttcc cgcacttcga 181 cctgagccac ggctctgccc aggttaaggg ccacggcaag aaggtggccg acgcgctgac 241 caacgccgtg gcgcacgtgg acgacatgcc caacgcgctg tccgccctga gcgacctgca 301 cgcgcacaag cttcgggtgg acccggtcaa cttcaagctc ctaagccact gcctgctggt 361 gaccctggcc gcccacctcc ccgccgagtt cacccctgcg gtgcacgcct ccctggacaa 421 gttcctggct tctgtgagca ccgtgctgac ctccaaatac cgttaagctg gagcctcggt 481 agccgttcct cctgcccgct gggcctccca acgggccctc ctcccctcct tgcaccggcc 541 cttcctggtc…A double mutant produced by uneven crossing-over contains two single nucleotide mutations that result in frame shifts and are separated by about 20 base pairs. The first is an insertion, while the second is a deletion. The amino acid sequences of the wildtype and mutant polypeptide in this region of the protein are as follows: Wildtype: Lys – Lys – Tyr – His – Gln – Trp – Thr – Cys – AsnDouble Mutant: Lys – Gln – Ile – Pro – Pro – Val – Asp – Met – Asn a) What are the original and double mutant mRNA sequences. You may find it useful to use the conventional symbols Y for pyrimidine, R for purine, N for any nucleotide, and H for A,C, or T. 2. b) Which nucleotide was inserted? 3. c) Which nucleotide was deleted?
- Wild type genomic sequence of a portion of a gene and the wild type sequence of portion of the protein gene product. The protein sequence only matches partially. ТАT AAA GGG СGA ССА ССТ GсT AАT GGG АСт тTG AGG Tyr Lys Gly Arg Pro Pro Ala Pro Arg Gln Tyr Trp Note: The five amino acids at the amino end of the WT protein match the coding sequence perfectly, but not the six at the carboxyl end. This is for an obvious reason that you should figure out before starting the problem. One of the difficulties with this problem is that you do not have the DNA sequence for the carboxyl end of the protein, but that should not be a problem! And, so far, there are no mutations; nothing unusual, it is just a normal eukaryotic gene!! A mutant is found that has the following protein sequence in that part of the protein: Tyr Lys Gly Arg Thr Cys Ser Premature Stop. What is the likely mutation? between A12 and C13 insert T. between C13 and C14 insert T. A15 -> del. C13 and C14 -> del. G8 -> T. G20 -> A. T21…5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. Write the resulting amino acid sequence using the 3 letter code. Write the answer in a all capital letters. Leave a space between the amino acids. Do not write 5' and 3'. 5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. If the G in Bold changes to a T, then the result will be A) A nonsense mutation B) A frameshift mutation C) A silent substitution D) A missense mutation 5'GGT ACG TTG GGG CTC CAT3' This sequence is transcribed and translated. If the G in Bold changes to a A, then the result will be A) A nonsenese mutation B) A frameshift mutation C) A silent substitution D) A missense mutationFigure out the mutation. You will need the codon table for this question. WT genomic sequence of a really small gene and matching complete amino acid sequence of its gene product. GGT ATG GGG ACT TTG AGG ATG ATA AGG CGT AAA TAA ATAT Met Gly Thr Leu Arg Met Ile Arg Arg Lys A mutant is found that has the following protein sequence: Met Gly Thr Leu Arg Gly. What is the likely mutation? between T14 and G15, insert T. G7 -> del. T5 -> del. G29, T30, A31 -> del between T14 and G15, insert AA. A31 -> T. C11 -> del
- Associated SNPs outside of gene no effect on protein production or function. T G Associated SNPs within gene no effect on protein production or function Regulatory sequences A Coding region с T Noncoding SNP: changes amount of protein produced www.Biolnteractive.org Causative SNPs within gene Unassociated SNP far from gene on same chromosome or different chromosome Protein Coding SNP: changes amino acid sequence b. Which types of SNPs might be identified in a GWAS? 4. Consider the different types of SNPs shown in Figure 3: associated, unassociated, and causative (including both noncoding and coding). a. Which types of SNPs affect protein production or function for the gene of interest? Figure 3. A diagram showing various ways in which a SNP could be associated with a certain gene and its trait. GWAS in the News Read the following news release, which describes a GWAS study with dogs. Note that a dog's coat refers to its fur or hair. Variants in Three Genes Account for Most Dog Coat…GIVEN THE FOLLOWING DNA SEQUENCES (+) OF THE GENBANK: INDICATE WHICH IS THE TEMPLATE MOLECULE, WHICH IS THE mRNA AND THE POLYPEPTIDE THAT IS FORMED FROM THE SEQUENCE DNA 5' atgagtaaagga 3'What would the amino acid sequence be for the following DNA Transcript? 5’AAGCCATTTAAAGGC 3’ 3’ TTCGGTAAATTTCCG 5’ Phe Gly Lys Phe Pro Phe Leu Lys Phe Val Lys Phe Phe Lys Pro Lys Pro Phe Lys Gly More information is needed
- Figure 1 is a bacterial gene (1-180). The first base to be transcribed is the base located at position 77. 45 5' TTGGT CTTGG TCGGA TTCCA GAGGA TGAAG TGTTG ACAGC GCATT 3' 3 AACCA GAACC AGCCT AAGGT CTCCT ACTTC ACAAC TGTCG CGTAA 5' 46 5 AATTG ACCTT GCTGT ATTAT AGCCA AGGAC AGATC TACGA GCATG 3' 3 TTAAC TGGAA CGACA TAATA TCGGT TCCTG TCTAG ATGCT CGTAC 5' 91 5 TGCGA ACCGC AAGCA TTCGT TCTCC TAGGC TACTC GATCC CGTAA 3' 3 ACGCT TGGCG TTCGT AACCA AGAGG ATCCG ATGAG CTAGG GCATT 5 77 90 110 135 136 5 TGATG TAGCT GATTC TGTTG AAAGG CTCCT TTTGG AGCCT TTTTT 3 3' ACTAC ATCGA CTAAG ACAAC TTTCC GAGGA AAACC TCGGA AAAAA 5 156 180 Figure 1. Illustrate how termination of transcription occurs in the gene above. (Hint: position from 156 to 180)Below is the DNA sequence of a gene, what is the protein sequence? 5'-GGTAAGCTAGCTATGACTACCCTGACATAGATATCGACTAGCTG-3' Insert the amino acid sequence using the single letter designation for the amino acid (ex: use ACG instead of AlaCysGly). Include only the letters in the correct order as they would be translated using no commas, no spaces and no dashes.The following is a portion of a protein: met-trp-tyr-arg-gly-pro-thr-Various mutant forms of this protein have been recovered. Using the normal and mutant sequences, determine the DNA and mRNA sequences that code for this portion of the protein, and explain each of the mutations. a. met-trp- b. met-cys-ile-val-val-leu-gln- c. met-trp-tyr-arg-ser-pro-thr- d. met-trp-tyr-arg-gly-ala-val-ile-ser-pro-thr-