A Scotch yoke is a mechanism that transforms the circular motion of a crank into the reciprocating motion of a shaft (or vice versa). It has been used in a number of different internal combustion engines and in control valves. In the Scotch yoke shown, the acceleration of Point A is defined by the relation  a=-1.5sin(kt) , where a and t are expressed in m/s2 and seconds, respectively, and k=3 rad/s. Knowing that x=0 and v=0.6 m/s when t =0, determine the position of Point A when t=0.5 s.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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A Scotch yoke is a mechanism that transforms the circular motion of a crank into the reciprocating motion of a shaft (or vice versa). It has been used in a number of different internal combustion engines and in control valves. In the Scotch yoke shown, the acceleration of Point A is defined by the relation  a=-1.5sin(kt) , where a and t are expressed in m/s2 and seconds, respectively, and k=3 rad/s. Knowing that x=0 and v=0.6 m/s when t =0, determine the position of Point A when t=0.5 s.

QUESTION 1
A Scotch yoke is a mechanism that transforms the circular motion of a crank into the reciprocating motion of a shaft (or vice versa). It has been used in a number of different
internal combustion engines and in control valves. In the Scotch yoke shown, the acceleration of Point A is defined by the relation a = - 1.5sin (kt), where a and t are
expressed in m/s² and seconds, respectively, and k=3 rad/s. Knowing that x=0 and v=0.6 m/s when t=0, determine the position of Point A when t=0.5 s.
201 mm
208 mm
220 mm
216 mm
|:
A
fi
B
D
Transcribed Image Text:QUESTION 1 A Scotch yoke is a mechanism that transforms the circular motion of a crank into the reciprocating motion of a shaft (or vice versa). It has been used in a number of different internal combustion engines and in control valves. In the Scotch yoke shown, the acceleration of Point A is defined by the relation a = - 1.5sin (kt), where a and t are expressed in m/s² and seconds, respectively, and k=3 rad/s. Knowing that x=0 and v=0.6 m/s when t=0, determine the position of Point A when t=0.5 s. 201 mm 208 mm 220 mm 216 mm |: A fi B D
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