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An AC Motor with impedance Z₁ = 45 + j100 is supplied by a 111 Vrms, 68 Hz source. Find a) Power factor (pf). b) Average power (active power). c) Reactive power, d) e) Complex power. Apperant power, f) Determine the capacitor required to be connected in parallel with motor so that power factor is corrected to 0.92. O a. a) pf=0.410, b) active power = 23.054 W. c) reactive power = 102.462 VAR, d) Complex Power- 23.054+j102.462 VA, e) Apperant Power 112.358 VA, f) Capacitor Value = 31.481 uF O b. a) pf=0.357. b) active power = 46.108 W. c) reactive power = 51.231 VAR, d) Complex Power= 46.108+j51.231 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value = 15.741 uF O c. a) pf=0.460, b) active power = 23.054 W. c) reactive power = 102.462 VAR d) Complex Power 46.108+j102.462 VA, e) Apperant Power- 56.179 VA, f) Capacitor Value = 31.481 uF O d. a) pf=0.410. b) active power = 46.108 W. c) reactive power 102.462 VAR, d) Complex Power- 46.108 j102.462 VA, e) Apperant Power 112.358 VA, f) Capacitor Value -15.741 uF O e. a) pf 0.460, b) active power 102.462 VAR, d) Complex Power 46.108+j102.462 VA e) Apperant Power 112.358 VA, f) Capacitor Value = 31.481 uF 23.054 W, c) reactive power = 51.231 VAR, d) Complex Power= 23.054 46.108 W. c) reactive power O f. a) pf=0.357, b) active power = j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF O g. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF Oh. a) pf=0.357, b) active power = 23.054 W. c) reactive power = 102.462 VAR, d) Complex Power- 23.054+j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF

An AC Motor with impedance Z₁ = 45 + j100 is supplied by a 111 Vrms, 68 Hz source. Find a) Power factor (pf). b) Average power (active power). c) Reactive power, d) e) Complex power. Apperant power, f) Determine the capacitor required to be connected in parallel with motor so that power factor is corrected to 0.92. O a. a) pf=0.410, b) active power = 23.054 W. c) reactive power = 102.462 VAR, d) Complex Power- 23.054+j102.462 VA, e) Apperant Power 112.358 VA, f) Capacitor Value = 31.481 uF O b. a) pf=0.357. b) active power = 46.108 W. c) reactive power = 51.231 VAR, d) Complex Power= 46.108+j51.231 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value = 15.741 uF O c. a) pf=0.460, b) active power = 23.054 W. c) reactive power = 102.462 VAR d) Complex Power 46.108+j102.462 VA, e) Apperant Power- 56.179 VA, f) Capacitor Value = 31.481 uF O d. a) pf=0.410. b) active power = 46.108 W. c) reactive power 102.462 VAR, d) Complex Power- 46.108 j102.462 VA, e) Apperant Power 112.358 VA, f) Capacitor Value -15.741 uF O e. a) pf 0.460, b) active power 102.462 VAR, d) Complex Power 46.108+j102.462 VA e) Apperant Power 112.358 VA, f) Capacitor Value = 31.481 uF 23.054 W, c) reactive power = 51.231 VAR, d) Complex Power= 23.054 46.108 W. c) reactive power O f. a) pf=0.357, b) active power = j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF O g. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF Oh. a) pf=0.357, b) active power = 23.054 W. c) reactive power = 102.462 VAR, d) Complex Power- 23.054+j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF

Refrigeration and Air Conditioning Technology (MindTap Course List)
Refrigeration and Air Conditioning Technology (MindTap Course List)
8th Edition
ISBN:9781305578296
Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Chapter12: Basic Electricity And Magnetism
Section: Chapter Questions
Problem 17RQ: What are the three types of opposition to current flow that impedance represents?
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Power Analysis I want the solution within twenty minutes
An AC Motor with impedance Z₁ = 45 + j100 is supplied by a 111 Vrms, 68 Hz source. Find a) Power factor (pf). b) Average power (active power). c) Reactive power, d) e) Complex power. Apperant power, f) Determine the capacitor required to be connected in parallel with motor so that power factor is corrected to 0.92. O a. a) pf=0.410, b) active power = 23.054 W. c) reactive power = 102.462 VAR, d) Complex Power- 23.054+j102.462 VA, e) Apperant Power 112.358 VA, f) Capacitor Value = 31.481 uF O b. a) pf=0.357. b) active power = 46.108 W. c) reactive power = 51.231 VAR, d) Complex Power= 46.108+j51.231 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value = 15.741 uF O c. a) pf=0.460, b) active power = 23.054 W. c) reactive power = 102.462 VAR d) Complex Power 46.108+j102.462 VA, e) Apperant Power- 56.179 VA, f) Capacitor Value = 31.481 uF O d. a) pf=0.410. b) active power = 46.108 W. c) reactive power 102.462 VAR, d) Complex Power- 46.108 j102.462 VA, e) Apperant Power 112.358 VA, f) Capacitor Value -15.741 uF O e. a) pf 0.460, b) active power 102.462 VAR, d) Complex Power 46.108+j102.462 VA e) Apperant Power 112.358 VA, f) Capacitor Value = 31.481 uF 23.054 W, c) reactive power = 51.231 VAR, d) Complex Power= 23.054 46.108 W. c) reactive power O f. a) pf=0.357, b) active power = j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF O g. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF Oh. a) pf=0.357, b) active power = 23.054 W. c) reactive power = 102.462 VAR, d) Complex Power- 23.054+j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF
Transcribed Image Text:An AC Motor with impedance Z₁ = 45 + j100 is supplied by a 111 Vrms, 68 Hz source. Find a) Power factor (pf). b) Average power (active power). c) Reactive power, d) e) Complex power. Apperant power, f) Determine the capacitor required to be connected in parallel with motor so that power factor is corrected to 0.92. O a. a) pf=0.410, b) active power = 23.054 W. c) reactive power = 102.462 VAR, d) Complex Power- 23.054+j102.462 VA, e) Apperant Power 112.358 VA, f) Capacitor Value = 31.481 uF O b. a) pf=0.357. b) active power = 46.108 W. c) reactive power = 51.231 VAR, d) Complex Power= 46.108+j51.231 VA, e) Apperant Power= 112.358 VA, f) Capacitor Value = 15.741 uF O c. a) pf=0.460, b) active power = 23.054 W. c) reactive power = 102.462 VAR d) Complex Power 46.108+j102.462 VA, e) Apperant Power- 56.179 VA, f) Capacitor Value = 31.481 uF O d. a) pf=0.410. b) active power = 46.108 W. c) reactive power 102.462 VAR, d) Complex Power- 46.108 j102.462 VA, e) Apperant Power 112.358 VA, f) Capacitor Value -15.741 uF O e. a) pf 0.460, b) active power 102.462 VAR, d) Complex Power 46.108+j102.462 VA e) Apperant Power 112.358 VA, f) Capacitor Value = 31.481 uF 23.054 W, c) reactive power = 51.231 VAR, d) Complex Power= 23.054 46.108 W. c) reactive power O f. a) pf=0.357, b) active power = j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF O g. a) pf=0.410, b) active power = 46.108 W, c) reactive power = 51.231 VAR, d) Complex Power= 46.108 j51.231 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 31.481 uF Oh. a) pf=0.357, b) active power = 23.054 W. c) reactive power = 102.462 VAR, d) Complex Power- 23.054+j102.462 VA, e) Apperant Power= 56.179 VA, f) Capacitor Value = 15.741 uF
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