Select the statement that is true. O Gene A and gene C are furthest apart. In this case, there were no double crossing over events. O The parent genotypes were AABBCC, and aabbcc (Gene order not necessarily correct). O Gene A is in the middle. Question 10 Consider the following F2 progeny for a 3-point cross. |AaBbCc 26 |AaBbcc 5 AabbCc 212 aaBbcc 328 aabbcc 7 aabbcc 22 22 total 600 T ID
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- From the powerpoint presentation, choose five (5) terms or concepts pertaining to chromosomal abnormality in the number. Describe each in a sentence. https://www.slideshare.net/farhanali911/chromosomal-abnormalities-33461290Assume that there is complete dominance and complete penetrance at each locus and that epistasis does not occur. (These are the same conditions we used in class). Write your answers in numeric form (not in words). Referring to the cross DdFfGgHhRrTT x DDffGgHhRRTt: How many different gametes does the DdFfGgHhRrTT parent produce? | How many different genotypes are found among the progeny of this cross? How many different phenotypes are found among the progeny of this cross? What is the probability that the first offspring from this cross will show the dominant phenotype for all loci? (Type in as a decimal and round to 6 digits.) What is the probability that the first offspring from this cross will be heterozygous for all loci? (Type in as a decimal and round to 6 decimal digits.) What is the probability that the first offspring from this cross will be a son with genotype DDFfGghhRrTt? (Type in as a decimal and round to 6 decimal digits).what is the probability that if the couple has three children, none of them will be affected by the syndrome. refer to the attached picture and show solution. is it 107/144? can you verify my answer. please refer to the picture below.
- Consider this pedigree showing an autosomal dominant rare disorder. What is the degree of penetrance? Show your work. na оп 16 19 fa 16 R 9XAssume that there is complete dominance and complete penetrance at each locus and that epistasis does not occur. (These are the same conditions we used in class). Write your answers in numeric form (not in words). Referring to the cross: Dd EE GG hh xMxm x Dd ee Gg HH xMY How many different gametes are produced by the individual of genotype DdEEGGhhXMXm? What is the probability that the first offspring from this cross will be genotype DDEeGgHhXMxm? our answer rounded properly to 5 decimal digits. What is the probability that the first offspring from this cross will be a son that shows the dominant phenotype for all loci? (Type in your answer rounded properly to 5 decimal digits.)If the proband (III-2) marries a heterozygous woman, what is the probability that they will have a heterozygous daughter? If this same couple has a son, what is the probability that he will be affected? Show complete solutions and box or highlight your final answers.
- Here are the progeny of this cross: (Note that the categories are not in any particular order.)Fly type # of prog. Phenotype symbols Categorywt eyes black body wt wings 97 grn+ blk crv+Green eyes black body curved wings 709 ParentalGreen eyes wt body wt wings 9Green eyes black body wt wings 162wt eyes wt body wt wings 727wt eyes black body curved wings 12wt eyes wt body curved wings 179Green eyes wt body curved wings 105Total = 2000 9.) Write the phenotype symbols in the right-hand column. The first one has been done for you.10.) Next to that, label all fly categories as parental (NCOs), SCOs, and DCOs. One has been donefor you.11.) After each SCO/DCO label, write which gene got “unlinked” in these offspring.12.) Put these three genes into a genetic map in the proper order.13.) Calculate the genetic distance between the genes and label the map with these distances.14.) Calculate the cross-over interference15.) Return to questions #1-6 above. For question 6, you gave your opinion, but…Shown above is a family pedigree tree in which family members afflictedwith the disease Haemophilia are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passingon the disease to their future children (represented by the ? symbolabove) because the hemophilia runs in the woman’s family. Turner syndrome is a disease in which an individual is bornwith only a single X chromosome. Suppose the woman in thecouple is a carrier for hemophilia and has a child with Turnersyndrome. Would this child have the disease?The e-gram (graph to the right of allelic ladder image) and above is from a woman. She has variations 14 and 15 at STR D3S1358. If she has children with a man who has variations 12 and 19 at the same STR, what are the possible combinations of variations that their children would have?
- Cystic fibrosis is a genetic disease that causes an abnormal production of mucus which in turn can cause damage and infection to the lungs and other organs. In the following pedigree, black indicates all those persons afflicted with cystic fibrosis (square symbols are males, circles are females). There's a healthy couple and they have two children. One is a 23-year-old daughter with cystic fibrosis who is married to a 24-year-old male who is healthy. The other child is a 15-year-old son who is healthy After studying the pedigree, write a logical hypothesis suggesting the cause of cystic fibrosis in terms of dominant or recessive alleles. On the basis of your hypothesis, write an appropriate genotype for both of the parents. Using a Punnett square, what is the probability of the parents having a child with cystic fibrosis? If the daughter's husband is a carrier of cystic fibrosis, what is the probability that they have a child with cystic fibrosis? Show your Punnett square.If the proband (III-2) marries a carrier woman, what is the probability that they will have an affected son? affected daughter? (Please show complete solution. Thanks.)The mother of a family with 10 children has blood typeRh+. She also has a very rare condition (elliptocytosis,phenotype E) that causes red blood cells to be oval rather than round in shape but that produces no adverseclinical effects. The father is Rh− (lacks the Rh+ antigen)and has normal red blood cells (phenotype e). The children are 1 Rh+ e, 4 Rh+ E, and 5 Rh− e. Information isavailable on the mother’s parents, who are Rh+ E andRh− e. One of the 10 children (who is Rh+ E) marriessomeone who is Rh+ e, and they have an Rh+ E child.a. Draw the pedigree of this whole family.b. Is the pedigree in agreement with the hypothesisthat the Rh+ allele is dominant and Rh− is recessive?c. What is the mechanism of transmission ofelliptocytosis?d. Could the genes governing the E and Rh phenotypesbe on the same chromosome? If so, estimate the mapdistance between them, and comment on your result