Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 1, Problem 1.20P
Interpretation Introduction
(a)
Interpretation:
The hybrid-orbital picture for the water molecule using oxygen
Concept introduction:
A new set of orbitals formed from the combination of the atomic orbitals is known as hybrid orbitals. The hybrid orbitals are obtained due to the mixing of atomic orbitals with different azimuthal quantum numbers. The hybrid orbitals have the property of directionality that is the electron density in the hybrid orbitals is directional.
Interpretation Introduction
(b)
Interpretation:
The departures from tetrahedral geometry that might be expected from the presence of two unshared electron pairs are to be explained.
Concept introduction:
A new set of orbitals formed from the combination of the atomic orbitals is known as hybrid orbitals. The hybrid orbitals are obtained due to the mixing of atomic orbitals with different azimuthal quantum numbers. The hybrid orbitals have the property of directionality that is the electron density in the hybrid orbitals is directional.
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Consider the reaction BF3 + NH3 -> F3B-NH3
(a) Describe the changes in hybridization of the B and N atoms as a result of this reaction.
(b) Describe the shapes of all the reactant molecules with their bond angles.
(c) Draw the overall shape of the product molecule and identify the bond angles around B and N atoms.
(d) What is the name of the bond between B and N.
(e)Describe the bonding orbitals that make the B and F, B and N & N and H bonds in the product molecule.
A useful solvent that will dissolve salts as well as organic compounds is the compound acetonitrile, H3CCN. It is present in paint strippers.(a) Write the Lewis structure for acetonitrile, and indicate the direction of the dipole moment in the molecule.(b) Identify the hybrid orbitals used by the carbon atoms in the molecule to form σ bonds.(c) Describe the atomic orbitals that form the π bonds in the molecule. Note that it is not necessary to hybridize the nitrogen atom.
Butadiene, C4H6, is a planar molecule that has the followingcarbon–carbon bond lengths:
(a) Predict the bond angles around each of the carbon atoms and sketch the molecule. (b) From left to right, what is the hybridization of each carbon atom in butadiene? (c) The middle C—C bond length in butadiene (1.48 Å) is a little shorter than the average C—C single bond length (1.54 Å). Does this imply that the middle C—C bond in butadiene is weaker or stronger than the average C—C single bond? (d) Based on your answer for part (c), discuss what additional aspects of bonding in butadiene might support the shorter middle C—C bond.
Chapter 1 Solutions
Organic Chemistry
Ch. 1 - Prob. 1.1PCh. 1 - Prob. 1.2PCh. 1 - Prob. 1.3PCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. 1.8PCh. 1 - Prob. 1.9PCh. 1 - Prob. 1.10P
Ch. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.15PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21APCh. 1 - Prob. 1.22APCh. 1 - Prob. 1.23APCh. 1 - Prob. 1.24APCh. 1 - Prob. 1.25APCh. 1 - Prob. 1.26APCh. 1 - Prob. 1.27APCh. 1 - Prob. 1.28APCh. 1 - Prob. 1.29APCh. 1 - Prob. 1.30APCh. 1 - Prob. 1.31APCh. 1 - Prob. 1.32APCh. 1 - Prob. 1.33APCh. 1 - Prob. 1.34APCh. 1 - Prob. 1.35APCh. 1 - Prob. 1.36APCh. 1 - Prob. 1.37APCh. 1 - Prob. 1.38APCh. 1 - Prob. 1.39APCh. 1 - Prob. 1.40APCh. 1 - Prob. 1.41APCh. 1 - Prob. 1.42APCh. 1 - Prob. 1.43APCh. 1 - Prob. 1.44APCh. 1 - Prob. 1.45APCh. 1 - Prob. 1.46APCh. 1 - Prob. 1.47APCh. 1 - Prob. 1.48APCh. 1 - Prob. 1.49AP
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