Concept explainers
Interpretation : The percent yield needs to be calculated and given table needs to be completed.
Methanol Reaction Data | ||
CO(g) | CH3OH(l) | |
Mass | 8.52g | |
Molar Mass | 28.01 g/mol | 32.05g/mol |
Moles |
Concept introduction : Wood alcohol is produced when CO reacts with hydrogen gas to produce methanol.
Percent yield is the efficiency of the
Answer to Problem 95A
Methanol Reaction Data | ||
CO(g) | CH3OH(l) | |
Mass | 8.5g | 8.52 |
Molar Mass | 28.01 g/mol | 32.05g/mol |
Moles | 0.30 | 0.266 |
Percent yield: 87.65%
Explanation of Solution
Step 1: write balance chemical equation
Step 2: convert mass of reactant to moles
Step 3: Convert moles of reactant to moles of product using mole ratio
1 moles of CO produce = 1 moles of CH3OH
0.30 moles of CO produce = 0.30 moles of CH3OH
Step 4: Convert moles of product to mass (theoretical yield)
Actual yield = 8.52 g of CH3OH
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