Determine the result when 100 g of steam at 100° C is passed into a mixture of 200 g of water and 20 g of ice at exactly 0 °C in a calorimeter that behaves thermally as if it were equivalent to 30 g of water.
The result when
Answer to Problem 37SP
Solution:
Explanation of Solution
Given data:
The mass of steam is
The mass of water is
The mass of ice is
The initial temperature of water and ice is
The initial temperature of steam is
The calorimeter behaves thermally equivalent to
Formula used:
The heat interaction of a body due to change in temperature is expressed by the formula,
Here,
The expression for heat of fusion is,
Here,
The expression for heat of condensation is,
Here,
The expression for net heat transfer in a calorimeter is written as,
Here,
Explanation:
Consider that the final temperature of the mixture is less than
Calculate the heat gained by steam to condense into water.
Here,
The standard value of latent heat of condensation of steam is
Understand that after condensation of all the steam into water at
Write the expression for the change in temperature of condensed steam into water from
Here,
Write the expression for heat lost by water due to change in temperature.
Here,
The standard value of specific heat of water is
Calculate the change in temperature of ice and water from
Here,
Understand that the change in temperature of the calorimeter is same as the change in temperature of water and ice.
Here,
Substitute
Write the expression for heat required to convert ice at
Here,
The standard value of latent heat of fusion of ice is
Recall the expression for heat transfer due to temperature difference in order to calculate the heat supplied to change the temperature of water at
Here,
Substitute
Recall the expression for heat transfer due to temperature difference in order to calculate the heat removed from
Here,
Substitute
Understand that the calorimeter is equivalent to
Here,
Substitute
Recall the expression for net heat transferred in a calorimeter. Take the heat released by the body as positive and the heat absorbed by the body as negative
Substitute
Further solve as,
Understand that the final temperature of the mixture cannot be more than
Rewrite the expression for heat released by the mass of steam condensed.
Here,
Substitute
The final temperature of the mixture is
Substitute
The final temperature of the mixture is
Further solve as,
Conclusion:
The result is that
Want to see more full solutions like this?
Chapter 18 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
- A certain ideal gas has a molar specific heat of Cv = 72R. A 2.00-mol sample of the gas always starts at pressure 1.00 105 Pa and temperature 300 K. For each of the following processes, determine (a) the final pressure, (b) the final volume, (c) the final temperature, (d) the change in internal energy of the gas, (e) the energy added to the gas by heat, and (f) the work done on the gas. (i) The gas is heated at constant pressure to 400 K. (ii) The gas is heated at constant volume to 400 K. (iii) The gas is compressed at constant temperature to 1.20 105 Pa. (iv) The gas is compressed adiabatically to 1.20 105 Pa.arrow_forwardEqual masses of substance A at 10.0C and substance B at 90.0C are placed in a well-insulated container of negligible mass and allowed to come to equilibrium. If the equilibrium temperature is 75.0Q which substance has the larger specific heat? (a) substance A (b) substance B (c) The specific heats are identical. (d) The answer depends on the exact initial temperatures. (e) More information is required.arrow_forward(a) The inside of a hollow cylinder is maintained at a temperature Ta, and the outside is at a lower temperature, Tb (Fig. P19.45). The wall of the cylinder has a thermal conductivity k. Ignoring end effects, show that the rate of energy conduction from the inner surface to the outer surface in the radial direction is dQdt=2Lk[TaTbln(b/a)] Suggestions: The temperature gradient is dT/dr. A radial energy current passes through a concentric cylinder of area 2rL. (b) The passenger section of a jet airliner is in the shape of a cylindrical tube with a length of 35.0 m and an inner radius of 2.50 m. Its walls are lined with an insulating material 6.00 cm in thickness and having a thermal conductivity of 4.00 105 cal/s cm C. A heater must maintain the interior temperature at 25.0C while the outside temperature is 35.0C. What power must be supplied to the heater? Figure P19.45arrow_forward
- An aluminum rod 0.500 m in length and with a cross-sectional area of 2.50 cm2 is inserted into a thermally insulated vessel containing liquid helium at 4.20 K. The rod is initially at 300 K. (a) If one-half of the rod is inserted into the helium, how many liters of helium boil off by the time the inserted half cools to 4.20 K? Assume the upper half does not yet cool. (b) If the circular surface of the upper end of the rod is maintained at 300 K, what is the approximate boil-off rate of liquid helium in liters per second after the lower half has reached 4.20 K? (Aluminum has thermal conductivity of 3 100 W/m K at 4.20 K; ignore its temperature variation. The density of liquid helium is 125 kg/m3.)arrow_forwardIn 1993, the U.S. government instituted a requirement that all room air conditioners sold in the United States must have an energy efficiency ratio (EER) of 10 or higher. The EER is defined as the ratio of the cooling capacity of the air conditioner, measured in British thermal units per hour, or Btu/h, to its electrical power requirement in watts. (a) Convert the EER of 10.0 to dimensionless form, using the conversion 1 Btu = 1 055 J. (b) What is the appropriate name for this dimensionless quantity? (c) In the 1970s, it was common to find room air conditioners with EERs of 5 or lower. State how the operating costs compare for 10 000-Btu/h air conditioners with EERs of 5.00 and 10.0. Assume each air conditioner operates for 1 500 h during the summer in a city where electricity costs 17.0 per kWh.arrow_forwardFor a temperature increase of 10 at constant volume, what is the heat absorbed by (a) 3.0 mol of a dilute monatomic gas; (b) 0.50 mol of a dilute diatomic gas; and (c) 15 mol of a dilute polyatomic gas?arrow_forward
- Beryllium has roughly one-half the specific heat of water (H2O). Rank the quantities of energy input required to produce the following changes from the largest to the smallest. In your ranking, note any cases of equality, (a) raising the temperature of 1 kg of H2O from 20C to 26C (b) raising the temperature of 2 kg of H2O from 20C to 23C (c) raising the temperature of 2 kg of H2O from 1C to 4C (d) raising the temperature of 2 kg of beryllium from 1C to 2C (e) raising the temperature of 2 kg of H2O from -1C to 2Carrow_forwardAn ideal gas initially at 300 K undergoes an isobaric expansion at 2.50 kPa. If the volume increases from 1.00 m3 to 3.00 m3 and 12.5 kJ is transferred to the gas by heat, what are (a) the change in its internal energy and (b) its final temperature?arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning