Determine the result when 10 g of steam at 100 °C is passed into a mixture of 400 g of water and 100 g of ice at exactly 0 °C in a calorimeter that behaves thermally as if it were equivalent to 50 g of water.
The result when
Answer to Problem 38SP
Solution:
Explanation of Solution
Given data:
The mass of steam is
The mass of water is
The mass of ice is
The initial temperature of water and ice is
The initial temperature of steam is
The calorimeter behaves thermally equivalent to
Formula used:
The heat interaction of a body due to change in temperature is expressed by the formula,
Here,
The expression for heat of fusion is,
Here,
The expression for heat of condensation is,
Here,
The expression for net heat transfer in a calorimeter is written as,
Here,
Explanation:
Consider that the final temperature of the mixture is more than
Calculate the heat gained by the steam to condense into water.
Here,
The standard value of latent heat of condensation of steam is
Understand that after the condensation of all the steam into water at
Write the expression for change in temperature of the condensed steam into water from
Here,
Write the expression for heat lost by water due to change in temperature.
Here,
The standard value of specific heat of water is
Calculate the change in temperature of ice and water from
Here,
Understand that the change in temperature of the calorimeter is the same as the change in temperature of water and ice.
Here,
Substitute
Write the expression for the heat required to convert ice at
Here,
The standard value of latent heat of fusion of ice is
Recall the expression for heat transfer due to temperature difference in order to calculate the heat supplied to change the temperature of water at
Here,
Substitute
Recall the expression for heat transfer due to temperature difference in order to calculate the heat removed from
Here,
Substitute
Understand that the calorimeter is equivalent to
Here,
Substitute
Recall the expression for the net heat transferred in a calorimeter. Take the heat absorbed by a body as negative and the heat released by a body as positive.
Substitute
Further solve as,
Understand that the final temperature of the mixture cannot be less than
Rewrite the expression for the heat absorbed by the mass of ice melted.
Here,
Substitute
The final temperature of the mixture is
Substitute
The final temperature of the mixture is
Further solve as,
Conclusion:
Therefore,
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Chapter 18 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
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