Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 19, Problem 19.15QE
Interpretation Introduction

Interpretation:

The fourth period element, which has one or more 3d electrons in the free element but none in any of its common oxidation states, has to be given.

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4. Which of the first transition series elements exhibits the greatest number of different oxidation states in its compounds? Explain.
Which lanthanide has the maximum number of unpairedelectrons in both its atom and 3+ ion? Give the number of un-paired electrons in the atom and ion.
Give the oxidation state of the metal for each of the following oxides of the first transition series. (Hint: Oxides of formula M3O4 are examples of mixed valence compounds in which the metal ion is present in more than oneoxidation state. It is possible to write these compound formulas in the equivalent format MO∙M2O3, to permit estimation of the metal’s two oxidation states.)(a) Sc2O3(b) TiO2(c) V2O5(d) CrO3(e) MnO2(f) Fe3O4(g) Co3O4(h) NiO(i) Cu2O

Chapter 19 Solutions

Chemistry: Principles and Practice

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Lanthanoids and its Position in Periodic Table - D and F Block Elements - Chemistry Class 12; Author: Ekeeda;https://www.youtube.com/watch?v=ZM04kRxm6tY;License: Standard YouTube License, CC-BY