Concept explainers
(a)
Interpretation: The
Concept introduction:
Mixture of acid and base undergoes equilibrium reaction and it’s
Weak acids are more stable and less reactive, so equilibrium follows the direction of formation weak acids in a reaction.
Lesser the
(b)
Interpretation: The
Concept introduction:
Mixture of acid and base undergoes equilibrium reaction and it’s
Weak acids are more stable and less reactive, so equilibrium follows the direction of formation weak acids in a reaction.
Lesser the
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Essential Organic Chemistry (3rd Edition)
- Which statement about the pKa value is false? The pKa value is calculated from the equilibrium constant for the dissociation of the acid. The pKa value is a measure of the strength of an acid. The pKa value of a given acid gives an indication of the strength of the conjugate base of that acid. A larger pKa value indicates a stronger acid and a weaker associated conjugate base. All of these statements are correct.arrow_forwardEstimate the Keq for the acid/base equilibria below using pKa Values. (Not provided so I have been looking in my text book and online and not getting anywhere..)arrow_forward1. Cl2 2. 3 equiv. NaNH2 3. CH3I 4. excess H2 / Pd 5. Br2, hv For this sequence of reactions, draw the major organic product of step 5. You do not have to consider stereochemistry. Draw organic products only. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate multiple products using the + sign from the drop-down menu. P opy aste Previousarrow_forward
- 3. The ranking of the acids in terms of increasing acid strength. 4. The ranking of the conjugate bases in terms of increasing base strength. 5.A justification for the rankings based on the factors that influence the relative stability of the different conjugate bases. I need to answer these for C3H5ClO2, ClCH2CO2, and CH3COOH. (Acetic acid, 3-chloropropanic, and chloroacetic acid). Pleaseeee help I will definitely ratearrow_forwardC341 Chapters (Acid-base chemistry) 9.) Acid-base equilibrium. For each reaction, perform the following tasks: a.) Complete the following reactions using the appropriate curved arrows to demonstrate the flow of electrons pairs in each potential reaction. b.) Indicate if the reaction lies to the right or the left (circle the correct arrow direction). c.) Calculate an approximate Ken for each reaction. d.) Write the pKa values under each acid, so we can evaluate your progress better and award partial credit. d.) Finally, label the acid (A), base (B), conjugate acid (CA) and base (CB) correctly based on the direction you decided. Keq = Direction: OH eg HO Keq = Direction: Keq = Direction: LOH OH ONa لها LIⒸ CHgLi Page 5 of 7arrow_forward8. Consider each reaction below carefully. Identify the acid and base on the reactant side of the reaction. Draw the expected product of a proton transfer between the acid and base. Estimate the pka of the acid and conjugate acid. Determine whether the reaction is product or reactant favored. a. b. C. d. OH @O HICI HO NaH 39arrow_forward
- 3. The pKa1 and pKa,2 of ortho and para isomers of phthalic acid (diprotic acid) are shown below: pKa1 pKa2 phthalic acid terephthalic acid 2.98 5.28 3.51 4.82 CO2H CO2H HO2C phthalic acid terephthalic acid Provide an explanation on the differences of their pKa values.arrow_forwardI mostly need help setting up how to do the math for these problems. I also need help with knowing how to find which acid is the strongest. Give the Ka or pKa values that should be entered in the blanks below. pKa = -log10ka ; Ka = 10-pKa (a) hydrocyanic acid: Ka = 4.92 x 10-10 ; pKa = (b) acetic acid: Ka = ; pKa = 4.75 (c) lactic acid: Ka = 8.40 x 10-4 ; pKa = (d) formic acid: Ka = ; pKa = 3.75 (e) Which of these acids is the strongest?arrow_forwardUsing the HSAB theory, predict the direction of the ff. reactions and explain. a. CdI2 + CaF2 ↔️ CdF2+CaI2 b. NH2- + H20 ↔️ NH3 OH- c. H2Po4- + H2O ↔️ H3PO4 + OH-arrow_forward
- 1. For each statement, pick the correct answer. a. In the reaction below, SO,2 is Select] v (an acid, a base), H3O* is [ Select ] HSO4 is ( Select] , and H2O is [ Select ] H,0* = HSO; H20 b. For this reaction, the conjugate of SO, is ISelect] v and the conjugate of H3O* is (Select] C. According to Table 2, the stronger of the two acids in this reaction is [ Select ) and the weaker of the two acids is ( Select ] d. At equilibrium, there will be more SO42- and H30+ than Iarrow_forwardThe pka's of the the three hydrogens of phosphoric acid are 2.15, 7.2 and 12.3. These numbers tell us that it is much more difficult to remove the second and third hydrogens of phoshoric acid. Why do you think this is so?arrow_forward2. Consider the two cyclic molecules below А. a. The CH2 hydrogens of molecule A. and B. show very different acidities - the pka of A. is 16 while the pKa of B. is 36. Recall that the pka is the negative log of the acid dissociation constant. First, draw the resulting conjugate base anions when one CH2 proton is removed from molecule A. and molecule B. Then, explain the differences in acidities by examining the relative stability of the two conjugate bases. А. b. Now consider the two molecules A. and B. Note that A. is a dianion and B. is a neutral molecule. One of these molecules is a highly reactive compound first characterized in frozen noble gas matrices, that self-reacts rapidly at temperatures above liquid nitrogen temperature. The other compound was isolated at room temperature in the early 1960s, and is a stable ligand used in organometallic chemistry. Which molecule is the more stable molecule, and why? B. B.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning