Becker's World of the Cell (9th Edition)
9th Edition
ISBN: 9780321934925
Author: Jeff Hardin, Gregory Paul Bertoni
Publisher: PEARSON
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Chapter 25, Problem 1Q
Summary Introduction
To determine: The likelihood of a child having polydactyly who has a normal father and a mother with polydactyly.
Introduction: Alteration of the
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For a recessive condition, two normal heterozygous individuals have children.
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In man, muscular dystrophy is a condition in which the muscles waste away during early life and may result in a shorter life expectancy. It is due to a sex-linked, recessive gene. A certain couple has five children – three boys (ages 1yr, 3yrs, and 10yrs old) and two girls (ages 5yrs and 7yrs old). The oldest boy shows the symptoms of this disease. You are their family physician and they come to you for advice. What would you tell them about the chances of their other children developing the disease?
Albinism is caused by an autosomal recessive allele that interferes with skin pigmentation in mammals. Two normally pigmented human parents already have an albino boy. They plan to continue to have children until they get a girl. Some or all of this information is important for each of the questions below.
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Chapter 25 Solutions
Becker's World of the Cell (9th Edition)
Ch. 25 - Cloning can be done by somatic cell nuclear...Ch. 25 - If the DNA content of a diploid cell in the G1...Ch. 25 - Prob. 25.3CCCh. 25 - Prob. 1QCh. 25 - Prob. 25.4CCCh. 25 - What do you think would happen to a pathogenic...Ch. 25 - Prob. 25.6CCCh. 25 - The Truth About Sex. For each of the following...Ch. 25 - Ordering the Phases of Meiosis. Drawings of...Ch. 25 - Telling Them Apart. Briefly describe how you might...
Ch. 25 - Prob. 25.4PSCh. 25 - More about DNA. Let X be the amount of DNA present...Ch. 25 - Meiotic Mistakes. Infants born with Patau syndrome...Ch. 25 - Prob. 25.7PSCh. 25 - QUANTITATIVE Punnett Squares as Genetic Tools. The...Ch. 25 - QUANTITATIVE Genetic Mapping. The following table...Ch. 25 - Prob. 25.10PSCh. 25 - Prob. 25.11PS
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- A certain type of deafness in humans is inherited as an X-linked recessive trait. A man with this type of deafness married a normal woman, and they are expecting a child. They find out that they are distantly related. Part of the family tree is shown here.How would you advise the parents about the probability of their child being a deaf boy, a deaf girl, a normal boy, or a normal girl? Be sure to state any assumptions that you make.arrow_forwardHemophilia is a recessive sex-linked trait in humans. Sickle-cell anemia is a recessive trait on an autosome. A couple are both carriers of the sickle-cell trait. The man and woman are normal, but the woman is a carrier for hemophilia. How many of their male children would you expect to have both sickle-cell anemia and hemophilia? How many of their female children would have both conditions?arrow_forwardIn humans, color vision depends on genes encoding three pigments. The R (red pigment) and G (green pigment) genes are close together on the X chromosome, whereas the B (blue pigment) gene is autosomal. A recessive mutation in any one of these genes can cause color blindness. Suppose that a color-blind man married a woman with normal color vision. The four sons from this marriage were color-blind, and the five daughters were normal. Specify the most likely genotypes of both parents and their children, explaining your reasoning. (A pedigree drawing will probably be helpful.) (Problem 50 is by Rosemary Redfield.)arrow_forward
- Cystic fibrosis in humans is caused by mutations in a single gene and is inherited as an autosomal (non-sex chromosome) recessive trait. An unaffected couple has two children. The first child has cystic fibrosis, and the second child is unaffected. What is the probability that the second child is a carrier (heterozygous) for the mutation that causes the disease? 2/3 1 1/2 3/4arrow_forwardPossession of a third breast is a rare recessive disorder. A man who has a third breast marries a woman who is a carrier of this unusual disorder. She however, has a recessive disorder that results in excessive facial hair. Because the man and woman are first cousins, he is a carrier for the facial hair gene. What is the probability that the lovely couple’s first offspring will be hairy and have a third breast? What is the probability that the child will have excessive facial hair only?arrow_forwardRed-green color blindness is inherited as a sex-linked recessive trait. The gene is found on the X chromosome. How can a man with normal color vision father a daughter who is red-green color-blind? Group of answer choices The man is heterozygous for red-green color blindness. The woman with whom he mates is red-green color-blind. He can't (unless there is a mutation). The man's mother carries an allele for red-green color blindness, and the expression of the trait skipped a generation.arrow_forward
- Piebaldism is a skin condition that causes an infant to be born with white birthmarks due to a genetic mutation. It is an autosomal dominant trait. A woman with piebaldism married a man without it. They have three daughters, two of whom also have piebaldism. One of their piebald daughters married a man who also has piebaldism and they have two sons with piebaldism, one son without it and one daughter with it. Draw the pedigree for this family and fill in as many of their genotypes as you can.arrow_forwardIn humans, the gene for brachydactyly (abnormally short fingers) is a dominant gene. The normal finger condition is the recessive trait. Both parents are heterozygous at this location. What is the phenotype of the father? Of the mother? What percentage of their kids should be expected to have brachydactyly?arrow_forwardA couple who are both heterozygous for an autosomal recessive mutation that is narrowly expressed and fully penetrant are planning on having three children. What is the probability that one their children will be normal (unaffected) and two children will have the recessive mutant phenotype? Show your work. Please answer this question using the Bayes’ Theoremarrow_forward
- A human disease known as cystic fibrosis is inherited as a recessive trait. Two unaffected individuals have a child who has the disease. What is the probability that their next two children will NOT have the disease?arrow_forwardThe following pedigree shows the inheritance of Huntington’s disease, a fatal genetic disorder that causes neurodegeneration. Since signs and symptoms usually do not appear until adulthood, many who are carriers may not realize their risk of passing on the disease-causing allele. The following pedigree represents a family in which some people are affected by Huntington’s disease. Using just the information on this pedigree, is Huntington’s disease caused by a dominant allele or recessive alleles? What are the genotypes of the grandparents (I-1 and I-2)? What are the genotypes of the parents (II-6 and II-7)? If the parents above have another child, what is the chance that they will be affected by the Hungtington’s disease allele? What are the genotypes of the unaffected children (III-8, 9, 10)? What is the chance that the unaffected children above will pass on a Huntington’s disease allele to their children? What is the genotype of the affected child (III-11)? What is the chance…arrow_forwardIn humans, the gene for albinism (a) is recessive to the gene for normal skin pigmentation (A). If two heterozygous persons have children, what is the probability they will have a child who is an albino? What is the probability they will have a child that is a carrier of the recessive gene?arrow_forward
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