Becker's World of the Cell (9th Edition)
9th Edition
ISBN: 9780321934925
Author: Jeff Hardin, Gregory Paul Bertoni
Publisher: PEARSON
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Chapter 25, Problem 25.4CC
Summary Introduction
To determine: Whether the given information can be used to determine the order of genes A, B, and C on the same chromosome.
Introduction: Genes lying closely together on the same chromosome can be used to observe a pattern of segregation. Experiments conducted on fruit flies by Morgan depicted that the distance between the two genes lying on the same chromosome may give a measure of the frequency of their recombination. Genes lying far apart from each other show more chances of being separated by a crossover.
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Suppose researchers studied the first chromosome of a new species and mapped three genes of interest, indicated as a, b, and c. A three‑factor cross was performed and the number of gametes formed from the F2 generation was recorded in a table. Note that the order of genes in the table is arbitrary.
Calculate the recombination frequencies for each given gene pair in map units.
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After completing the gene mapping, the researchers treated individuals to induce inversions in the chromosomes. After treatment, another three‑factor cross was performed and the number of gametes formed from the F2 generation was recorded in a second table. Note that the order of genes in the table is arbitrary.
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Calculate the recombination frequencies for each given gene pair in map units.
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Chapter 25 Solutions
Becker's World of the Cell (9th Edition)
Ch. 25 - Cloning can be done by somatic cell nuclear...Ch. 25 - If the DNA content of a diploid cell in the G1...Ch. 25 - Prob. 25.3CCCh. 25 - Prob. 1QCh. 25 - Prob. 25.4CCCh. 25 - What do you think would happen to a pathogenic...Ch. 25 - Prob. 25.6CCCh. 25 - The Truth About Sex. For each of the following...Ch. 25 - Ordering the Phases of Meiosis. Drawings of...Ch. 25 - Telling Them Apart. Briefly describe how you might...
Ch. 25 - Prob. 25.4PSCh. 25 - More about DNA. Let X be the amount of DNA present...Ch. 25 - Meiotic Mistakes. Infants born with Patau syndrome...Ch. 25 - Prob. 25.7PSCh. 25 - QUANTITATIVE Punnett Squares as Genetic Tools. The...Ch. 25 - QUANTITATIVE Genetic Mapping. The following table...Ch. 25 - Prob. 25.10PSCh. 25 - Prob. 25.11PS
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- Assume you are mapping genes A, B, C, and D in Drosophila. You know that these genes are linked on the same chromosome, and you determine the recombination frequencies between each pair of genes to be as follows: A–B, 8%; A– C, 28%; A–D, 25%; B–C, 20%; B–D, 33%. (a) Describe how you determined the recombination frequency for each pair of genes. (b) Draw a chromosome map based on your data.arrow_forwardIn Drosophila, bar-shaped eyes (B), scalloped wings (S), crossvein-less wings (W), and eye Color (C) are located on the X chromosome. The recombination frequency of each gene is indicated on the table. Construct a chromosome map. Identify the first gene, second gene, third gene, and the fourth gene Write down the distances between genearrow_forwardConsider two loci A and B that are 30 cM apart on chromosome 1 in the fruit fly. A paracentric inversion is found to span about half of the distance between these loci, but not include either A or B. What is the approximate recombination frequency expected for these loci in … flies that are heterozygous for this inversion? RF(A-B) for heterozygous flies is … flies that are homozygous for this inversion? RF(A-B) for homozygous flies is …arrow_forward
- You perform a cross between two plants, one MmPp and one mmpp, and obtain offspring with the following phenotypes: 42 MP; 374 Mp; 367 mP; 27 mp. What can you conclude from these data? ONLY PICK ONE OF THE ANSWERS: The M and P genes are on different chromosomes The recombinant progeny are mP and Mp The M and P genes are far apart on the same chromosome The recombinant progeny are MP and mparrow_forwardBelow are the results from a 3 gene testcross between an XxYyZz plant and an xxyyzz plant: Testcross outcome: XYZ 365 xyz 367 xYz 110 XyZ 105 XYZ 3 Xyz 4 XYZ 25 xyZ 21 1. Determine the order of these genes on the chromosome. Indicate them on the diagram below. 2. Calculate the map distances between the genes (give you answer as map units). Indicate these distances on the diagram above. 3. Determine the coefficient of coincidence. 4. Determine the interference among these genes.arrow_forwardYou perform a cross between two plants, one MmPp and one mmpp, and obtain offspring with the following phenotypes: 42 MP; 374 Mp; 367 mP; 27 mp. What can you conclude from these data? Group of answer choices The M and P genes are on different chromosomes The recombinant progeny are mP and Mp The M and P genes are far apart on the same chromosome The recombinant progeny are MP and mparrow_forward
- Genes Q, R, and S are on the same chromosome. The crossoverfrequency between S and Q is 5%, the crossover frequency betweenQ and R is 30%, and the crossover frequency between R and S is35%. Use this information to create a linkage map for thechromosomearrow_forwardIn a series of mapping experiments, the recombination frequencies for four different linked genes of the Drosophila fly were determined, as shown in the figure. Based on this information, what is the most probable order of these genes on the chromosome? b 0 cn 90 rb 3.5 6.5 0 vg 19 9.0 16 0 b cn rb vg The numbers in the boxes are the recombination frequencies in between the genes (in percent). O b-rb-cn-vg O vg-cn-b-rb Orb-cn-vg-b b = black body cn = cinnabar eyes rb = reduced bristles vg = vestigial wings O vg-b-rb-cnarrow_forwardYou have determined that the gene order for three linked genes being studied is A B C. The number of recombinants resulting from crossover between genes A and BC are 44 and 48, respectively, while the double-crossover progeny total 4 and 6. What is the recombination frequency between genes A and B if the total progeny from the cross is 1000? Show all of your work.arrow_forward
- Please explain how I can solve this. Thank you You wanted to draw a linkage map for three genes in the fruit fly (A, B, C) that you suspect are linked. You have done a three-point testcross and found that out of the 1500 progeny in the cross, 612 are a · b · c, 603 are A · B · C, 93 are a · B · C, 85 are A · b · c, 53 are a · b · C, 47 are A · B · c, 5 are A · b · C, and 2 are a · B · c. From this data, you can deduce that the genes are linked and the distance between B and C is:arrow_forwardGive typing answer with explanation and conclusion to all parts The chromosomes drawn below are found in a human skin cell. The lines represent the chromosomes themselves. The letters indicate the location of a particular version of a gene. a) T/F An individual’s offspring are more likely to inherit a D1 and R together than a D1 and T9 together. b) T/F About 50% of the egg cells from this individual will have both T9 and BA5. c) T/F Because r is recessive, the frequency at which the r version of the gene occurs in a population is lower than the frequency at which the R version occurs in the population. d) T/F If the protein produced by the BA gene is involved in the formation of ovaries, then the BA gene is likely located on a sex chromosome. e) T/F Because the genes shown here are found in skin cells, these genes code for proteins required for skin cell function.arrow_forwardAs per our guidelines, we are able to only answer three subparts in a question that is posted. Please post the remaining subparts from Part B as separate questions. this is the remaining questions 4. What are the two parental classes and the two recombinant classes of offspring? 5. What is the percentage of recombination between these two loci? Show your calculations. 6. How many map units apart are they?arrow_forward
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genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license