(a)
The location and magnification of the final image formed by the two lenses.
(a)
Answer to Problem 79PQ
The image is formed at a distance of
Explanation of Solution
Write the expression for focal length of a thin lens.
Here,
Write the expression for image distance of the first lens.
Here,
Write the expression for magnification by first lens.
Here,
Write the expression for object distance from the second lens.
Here,
Write the expression for image distance for the second lens.
Here,
Write the expression for magnification by second lens.
Here,
Write the expression for final magnification.
Conclusion:
Substitute
Substitute
Substitute
Substitute
Substitute
Substitute
Therefore, the image is formed at a distance of
(b)
The final image formed is upright or inverted.
(b)
Answer to Problem 79PQ
The final image formed will be inverted.
Explanation of Solution
The image formed will be real as the final image distance is positive and the image formed will be inverted as the final magnification produced by two lenses is negative. Therefore, the final image formed will be real and inverted.
Conclusion:
Therefore, the final image formed will be inverted.
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Chapter 38 Solutions
Physics for Scientists and Engineers: Foundations and Connections
- Two converging lenses having focal lengths of f1 = 10.0 cm and f2 = 20.0 cm are placed a distance d = 50.0 cm apart as shown in Figure P35.48. The image due to light passing through both lenses is to be located between the lenses at the position x = 31.0 cm indicated. (a) At what value of p should the object be positioned to the left of the first lens? (b) What is the magnification of the final image? (c) Is the final image upright or inverted? (d) Is the final image real or virtual?arrow_forwardA doctor examines a mole with a 15.0-cm focal length magnifying glass held 13.5 cm from the mole. (a) Where is the image? (b) What is its magnification? (c) How big is the image of a 5.00 mm diameter mole?arrow_forwardAn object 1.50 cm high is held 3.00 cm from a person’s cornea, and its reflected image is measured to be 0.167 cm high. (a) What is the magnification? (b) Where is the image? (c) Find the radius of curvature of the convex mirror formed by the cornea. (Note that this technique is used by optometrists to measure the curvature of the cornea for contact lens fitting. The instrument used is called a keratometer, or curve measurer.)arrow_forward
- An amoeba is 0.305 cm away from the 0.300 cm- focal length objective lens of a microscope. (a) Where is the image formed by the objective lens? (b) What is this image’s magnification? (C) An eyepiece with a 2.00-cm focal length is placed 20.0 cm from the objective. Where is the final image? (d) What angular magnification is produced by the eyepiece? (e) What is the overall magnification? (See Figure 2.39.)arrow_forwardA microscope with an overall magnification of 800 has an objective that magnifies by 200. (a) What is the angular magnification of the eyepiece? (b) If there are two other objectives that can be used, having magnifications of 100 and 400, what other total magnifications are possible?arrow_forwardA leaf of length h is positioned 71.0 cm in front of a converging lens with a focal length of 39.0 cm. An observer views the image of the leaf from a position 1.26 in behind the lens, as shown in Figure P25.25. (a) What is the magnitude of the lateral magnification (the ratio of the image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the loaf directly? Figure P25.25arrow_forward
- People who do very detailed work close up, such as jewelers, often can see objects clearly at much closer distance than the normal 25 cm. (a) What is the power of the eyes of a woman who can see an object clearly at a distance of only 8.00 cm? (b) What is the image size of a 1.00-mm object, such as lettering inside a ring, held at this distance? (c) What would the size of the image be if the object were held at the normal 25.0 cm distance?arrow_forwardSuppose you want to use a converging lens to project the image of two trees onto a screen. As show n in Figure CQ36.9, one tree is a distance x from the lens and the other is at 2x. You adjust the screen so that the near tree is in locus. It you now want the far tree to be in focus, do you move the screen toward or away from the lens?arrow_forwardThe radius of curvature of the left-hand face of a flint glass biconvex lens (n = 1.60) has a magnitude of 8.00 cm, and the radius of curvature of the right-hand face has a magnitude of 11.0 cm. The incident surface of a biconvex lens is convex regardless of which side is the incident side. What is the focal length of the lens if light is incident on the lens from the left?arrow_forward
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