Statistics for Engineers and Scientists
Statistics for Engineers and Scientists
4th Edition
ISBN: 9780073401331
Author: William Navidi Prof.
Publisher: McGraw-Hill Education
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Chapter 6.7, Problem 4E

The article “Time Series Analysis for Construction Productivity Experiments” (T. Abdelhamid and J. Everett. Journal of Construction Engineering and Management. 1999:87–95) presents a study comparing the effectiveness of a video system that allows a crane operator to see the lifting point while operating the crane with the old system in which the operator relies on hand signals from a tagman. Three different lifts, A, B, and C, were studied. Lift A was of little difficulty, lift B was of moderate difficulty, and lift C was of high difficulty. Each lift was performed several times, both with the new video system and with the old tagman system. The time (in seconds) required to perform each lift was recorded. The following tables present the means, standard deviations, and sample sizes.

Chapter 6.7, Problem 4E, The article Time Series Analysis for Construction Productivity Experiments (T. Abdelhamid and J. , example  1

Chapter 6.7, Problem 4E, The article Time Series Analysis for Construction Productivity Experiments (T. Abdelhamid and J. , example  2

Chapter 6.7, Problem 4E, The article Time Series Analysis for Construction Productivity Experiments (T. Abdelhamid and J. , example  3

  1. a. Can you conclude that the mean time to perform a lift of low difficulty is less when using the video system than when using the tagman system? Explain.
  2. b. Can you conclude that the mean time to perform a lift of moderate difficulty is less when using the video system than when using the tagman system? Explain.
  3. c. Can you conclude that the mean time to perform a lift of high difficulty is less when using the video system than when using the tagman system? Explain.

a.

Expert Solution
Check Mark
To determine

Check whether there is evidence to conclude that the mean time to perform a lift of low difficulty is less when using the video system than when using the tagman system.

Answer to Problem 4E

There is no evidence to conclude that the mean time to perform a lift of low difficulty is less when using the video system than when using the tagman system.

Explanation of Solution

Given info:

Three different lifts, A, B, and C, were studied in the given experiment. Lift A was of little difficulty, lift B was of moderate difficulty, and lift C was of high difficulty. The summary statistics for three lifts are given below:

Low difficulty:

Tagman: X¯=47.79, sX=2.19 and nX=14

Video: Y¯=47.15, sY=2.65 and nY=40

Moderate difficulty:

Tagman: X¯=69.33, sX=6.26 and nX=12

Video: Y¯=58.50, sY=5.59 and nY=24

High difficulty:

Tagman: X¯=109.71, sX=17.02 and nX=17

Video: Y¯=84.52, sY=13.51 and nY=29

Calculation:

State the test hypotheses.

Null hypothesis:

H0:μXμY0

Alternative hypothesis:

H1:μXμY>0

Tests statistic and P-value:

Software Procedure:

Step-by-step procedure to obtain the test statistic using the MINITAB software:

  • Choose Stat > Basic Statistics > 2-Sample t.
  • Choose Summarized data.
  • In first, enter Sample size as 14, Mean as 47.79, Standard deviation as 2.19.
  • In second, enter Sample size as 40, Mean as 47.15, Standard deviation as 2.65.
  • Choose Options.
  • In Confidence level, enter 95.
  • In Alternative, select greater than.
  • Click OK in all the dialogue boxes.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 6.7, Problem 4E , additional homework tip  1

From the MINITAB output, the test statistic is 0.89 and the P-value is 0.191.

Conclusion:

The P-value is 0.191 and the significance level is 0.05.

Here, the P-value is greater than the significance level.

That is, 0.191(=P-value)>0.05(=α).

Therefore, the null hypothesis is not rejected.

Thus, there is no evidence to conclude that the mean time to perform a lift of low difficulty is less when using the video system than when using the tagman system.

b.

Expert Solution
Check Mark
To determine

Check whether there is evidence to conclude that the mean time to perform a lift of moderate difficulty is less when using the video system than when using the tagman system.

Answer to Problem 4E

There is evidence to conclude that the mean time to perform a lift of moderate difficulty is less when using the video system than when using the tagman system.

Explanation of Solution

Calculation:

State the test hypotheses.

Null hypothesis:

H0:μXμY0

Alternative hypothesis:

H1:μXμY>0

Tests statistic and P-value:

Software Procedure:

Step-by-step procedure to obtain the test statistic using the MINITAB software:

  • Choose Stat > Basic Statistics > 2-Sample t.
  • Choose Summarized data.
  • In first, enter Sample size as 12, Mean as 69.33, Standard deviation as 6.26.
  • In second, enter Sample size as 24, Mean as 58.50, Standard deviation as 5.59.
  • Choose Options.
  • In Confidence level, enter 95.
  • In Alternative, select greater than.
  • Click OK in all the dialogue boxes.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 6.7, Problem 4E , additional homework tip  2

From the MINITAB output, the test statistic is 5.07 and the P-value is 0.000.

Conclusion:

The P-value is 0.000 and the significance level is 0.05.

Here, the P-value is less than the significance level.

That is, 0.000(=P-value)<0.05(=α).

Therefore, the null hypothesis is rejected.

Thus, there is evidence to conclude that the mean time to perform a lift of moderate difficulty is less when using the video system than when using the tagman system.

c.

Expert Solution
Check Mark
To determine

Check whether there is evidence to conclude that the mean time to perform a lift of high difficulty is less when using the video system than when using the tagman system.

Answer to Problem 4E

There is evidence to conclude that the mean time to perform a lift of high difficulty is less when using the video system than when using the tagman system.

Explanation of Solution

Calculation:

State the test hypotheses.

Null hypothesis:

H0:μXμY0

Alternative hypothesis:

H1:μXμY>0

Tests statistic and P-value:

Software Procedure:

Step-by-step procedure to obtain the test statistic using the MINITAB software:

  • Choose Stat > Basic Statistics > 2-Sample t.
  • Choose Summarized data.
  • In first, enter Sample size as 17, Mean as 109.71, Standard deviation as 17.02.
  • In second, enter Sample size as 29, Mean as 84.52, Standard deviation as 13.51.
  • Choose Options.
  • In Confidence level, enter 95.
  • In Alternative, select greater than.
  • Click OK in all the dialogue boxes.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 6.7, Problem 4E , additional homework tip  3

From the MINITAB output, the test statistic is 5.21 and the P-value is 0.000.

Conclusion:

The P-value is 0.000 and the significance level is 0.05.

Here, the P-value is less than the significance level.

That is, 0.000(=P-value)<0.05(=α).

Therefore, the null hypothesis is rejected.

Thus, there is evidence to conclude that the mean time to perform a lift of high difficulty is less when using the video system than when using the tagman system.

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Chapter 6 Solutions

Statistics for Engineers and Scientists

Ch. 6.1 - Fill in the blank: If the null hypothesis is H0: ...Ch. 6.1 - Fill in the blank: In a test of H0: 10 versus...Ch. 6.1 - An engineer takes a large number of independent...Ch. 6.1 - The following MINITAB output presents the results...Ch. 6.1 - The following MINITAB output presents the results...Ch. 6.2 - For which P-value is the null hypothesis more...Ch. 6.2 - Prob. 2ECh. 6.2 - If P = 0.01, which is the best conclusion? i. H0...Ch. 6.2 - If P = 0.50, which is the best conclusion? i. H0...Ch. 6.2 - True or false: If P = 0.02, then a. The result is...Ch. 6.2 - George performed a hypothesis test. 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